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SpiderQuestion
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SpiderSynQuestion
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How many heads of the departments are older than 56 ?
SELECT count(*) FROM head WHERE age > 56
How many leaders of the divisions are older than 56 ?
department_management
List the name, born state and age of the heads of departments ordered by age.
SELECT name , born_state , age FROM head ORDER BY age
List the name, born state and age of the leaders of departments ordered by age.
department_management
List the creation year, name and budget of each department.
SELECT creation , name , budget_in_billions FROM department
List the establishment year, name and budget of each division.
department_management
What are the maximum and minimum budget of the departments?
SELECT max(budget_in_billions) , min(budget_in_billions) FROM department
What are the maximum and minimum budget of the divisions?
department_management
What is the average number of employees of the departments whose rank is between 10 and 15?
SELECT avg(num_employees) FROM department WHERE ranking BETWEEN 10 AND 15
What is the average number of staffs of the divisions whose rank is between 10 and 15?
department_management
What are the names of the heads who are born outside the California state?
SELECT name FROM head WHERE born_state != 'California'
What are the names of the leaders who are born outside the California state?
department_management
What are the distinct creation years of the departments managed by a secretary born in state 'Alabama'?
SELECT DISTINCT T1.creation FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id JOIN head AS T3 ON T2.head_id = T3.head_id WHERE T3.born_state = 'Alabama'
What are the different establishment years of the divisions managed by a secretary born in state 'Alabama'?
department_management
What are the names of the states where at least 3 heads were born?
SELECT born_state FROM head GROUP BY born_state HAVING count(*) >= 3
What are the names of the states where at least 3 leaders were born?
department_management
In which year were most departments established?
SELECT creation FROM department GROUP BY creation ORDER BY count(*) DESC LIMIT 1
In which year were most divisions established?
department_management
Show the name and number of employees for the departments managed by heads whose temporary acting value is 'Yes'?
SELECT T1.name , T1.num_employees FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id WHERE T2.temporary_acting = 'Yes'
Show the name and number of staffs for the divisions managed by heads whose temporary acting value is 'Yes'?
department_management
How many acting statuses are there?
SELECT count(DISTINCT temporary_acting) FROM management
How many acting statuses are there?
department_management
How many departments are led by heads who are not mentioned?
SELECT count(*) FROM department WHERE department_id NOT IN (SELECT department_id FROM management);
How many divisions are led by leaders who are not mentioned?
department_management
What are the distinct ages of the heads who are acting?
SELECT DISTINCT T1.age FROM management AS T2 JOIN head AS T1 ON T1.head_id = T2.head_id WHERE T2.temporary_acting = 'Yes'
What are the different ages of the leaders who are acting?
department_management
List the states where both the secretary of 'Treasury' department and the secretary of 'Homeland Security' were born.
SELECT T3.born_state FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id JOIN head AS T3 ON T2.head_id = T3.head_id WHERE T1.name = 'Treasury' INTERSECT SELECT T3.born_state FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id JOIN head AS T3 ON T2.head_id = T3.head_id WHERE T1.name = 'Homeland Security'
List the states where both the secretary of 'Treasury' division and the secretary of 'Homeland Security' were born.
department_management
Which department has more than 1 head at a time? List the id, name and the number of heads.
SELECT T1.department_id , T1.name , count(*) FROM management AS T2 JOIN department AS T1 ON T1.department_id = T2.department_id GROUP BY T1.department_id HAVING count(*) > 1
Which division has more than 1 leader at a time? List the id,name and the number of leaders.
department_management
Which head's name has the substring 'Ha'? List the id and name.
SELECT head_id , name FROM head WHERE name LIKE '%Ha%'
Which leader's name has the substring 'Ha'? List the id and name.
department_management
How many farms are there?
SELECT count(*) FROM farm
How many farms are there?
farm
Count the number of farms.
SELECT count(*) FROM farm
Count the number of farms.
farm
List the total number of horses on farms in ascending order.
SELECT Total_Horses FROM farm ORDER BY Total_Horses ASC
List the total number of horses on farms in ascending order.
farm
What is the total horses record for each farm, sorted ascending?
SELECT Total_Horses FROM farm ORDER BY Total_Horses ASC
What is the total horses record for each farm, sorted ascending?
farm
What are the hosts of competitions whose theme is not "Aliens"?
SELECT Hosts FROM farm_competition WHERE Theme != 'Aliens'
What are the hosts of contests whose topic is not "Aliens"?
farm
Return the hosts of competitions for which the theme is not Aliens?
SELECT Hosts FROM farm_competition WHERE Theme != 'Aliens'
Return the hosts of contests for which the topic is not Aliens?
farm
What are the themes of farm competitions sorted by year in ascending order?
SELECT Theme FROM farm_competition ORDER BY YEAR ASC
What are the topics of farm competitions sorted by year in ascending order?
farm
Return the themes of farm competitions, sorted by year ascending.
SELECT Theme FROM farm_competition ORDER BY YEAR ASC
Return the topics of farm competitions, sorted by year ascending.
farm
What is the average number of working horses of farms with more than 5000 total number of horses?
SELECT avg(Working_Horses) FROM farm WHERE Total_Horses > 5000
What is the average number of working horses of farms with more than 5000 total number of horses?
farm
Give the average number of working horses on farms with more than 5000 total horses.
SELECT avg(Working_Horses) FROM farm WHERE Total_Horses > 5000
Give the average number of working horses on farms with more than 5000 total horses.
farm
What are the maximum and minimum number of cows across all farms.
SELECT max(Cows) , min(Cows) FROM farm
What are the maximum and minimum number of cows across all farms.
farm
Return the maximum and minimum number of cows across all farms.
SELECT max(Cows) , min(Cows) FROM farm
Return the maximum and minimum number of cows across all farms.
farm
How many different statuses do cities have?
SELECT count(DISTINCT Status) FROM city
How many different statuses do towns have?
farm
Count the number of different statuses.
SELECT count(DISTINCT Status) FROM city
Count the number of different statuses.
farm
List official names of cities in descending order of population.
SELECT Official_Name FROM city ORDER BY Population DESC
List official names of towns in descending order by the number of people.
farm
What are the official names of cities, ordered descending by population?
SELECT Official_Name FROM city ORDER BY Population DESC
What are the formal names of towns, ordered descending by residents?
farm
List the official name and status of the city with the largest population.
SELECT Official_Name , Status FROM city ORDER BY Population DESC LIMIT 1
List the formal name and status of the city with the largest populace.
farm
What is the official name and status of the city with the most residents?
SELECT Official_Name , Status FROM city ORDER BY Population DESC LIMIT 1
What is the formal name and status of the town with the most residents?
farm
Show the years and the official names of the host cities of competitions.
SELECT T2.Year , T1.Official_Name FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID
Show the years and the formal names of the host towns of competitions.
farm
Give the years and official names of the cities of each competition.
SELECT T2.Year , T1.Official_Name FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID
Give the years and formal names of the towns of each contest.
farm
Show the official names of the cities that have hosted more than one competition.
SELECT T1.Official_Name FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID GROUP BY T2.Host_city_ID HAVING COUNT(*) > 1
Show the formal names of the towns that have held more than one contest.
farm
What are the official names of cities that have hosted more than one competition?
SELECT T1.Official_Name FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID GROUP BY T2.Host_city_ID HAVING COUNT(*) > 1
What are the formal names of towns that have hosted more than one competition?
farm
Show the status of the city that has hosted the greatest number of competitions.
SELECT T1.Status FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID GROUP BY T2.Host_city_ID ORDER BY COUNT(*) DESC LIMIT 1
Show the status of the town that has hosted the greatest number of contests.
farm
What is the status of the city that has hosted the most competitions?
SELECT T1.Status FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID GROUP BY T2.Host_city_ID ORDER BY COUNT(*) DESC LIMIT 1
What is the status of the town that has hosted the most contests?
farm
Please show the themes of competitions with host cities having populations larger than 1000.
SELECT T2.Theme FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID WHERE T1.Population > 1000
Please show the topics of contests with host cities having populations larger than 1000.
farm
What are the themes of competitions that have corresponding host cities with more than 1000 residents?
SELECT T2.Theme FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID WHERE T1.Population > 1000
What are the topics of contests that have corresponding host cities with more than 1000 residents?
farm
Please show the different statuses of cities and the average population of cities with each status.
SELECT Status , avg(Population) FROM city GROUP BY Status
Please show the different statuses of cities and the average populace of cities with each status.
farm
What are the statuses and average populations of each city?
SELECT Status , avg(Population) FROM city GROUP BY Status
What are the statuses and average populace of each town?
farm
Please show the different statuses, ordered by the number of cities that have each.
SELECT Status FROM city GROUP BY Status ORDER BY COUNT(*) ASC
Please show the different statuses, ordered by the number of towns that have each.
farm
Return the different statuses of cities, ascending by frequency.
SELECT Status FROM city GROUP BY Status ORDER BY COUNT(*) ASC
Return the different statuses of towns, ascending by frequency.
farm
List the most common type of Status across cities.
SELECT Status FROM city GROUP BY Status ORDER BY COUNT(*) DESC LIMIT 1
List the most common type of Status across towns.
farm
What is the most common status across all cities?
SELECT Status FROM city GROUP BY Status ORDER BY COUNT(*) DESC LIMIT 1
What is the most common status across all towns?
farm
List the official names of cities that have not held any competition.
SELECT Official_Name FROM city WHERE City_ID NOT IN (SELECT Host_city_ID FROM farm_competition)
List the formal names of towns that have not held any competition.
farm
What are the official names of cities that have not hosted a farm competition?
SELECT Official_Name FROM city WHERE City_ID NOT IN (SELECT Host_city_ID FROM farm_competition)
What are the formal names of towns that have not hosted a farm competition?
farm
Show the status shared by cities with population bigger than 1500 and smaller than 500.
SELECT Status FROM city WHERE Population > 1500 INTERSECT SELECT Status FROM city WHERE Population < 500
Show the status shared by towns with number of people bigger than 1500 and smaller than 500.
farm
Which statuses correspond to both cities that have a population over 1500 and cities that have a population lower than 500?
SELECT Status FROM city WHERE Population > 1500 INTERSECT SELECT Status FROM city WHERE Population < 500
Which statuses correspond to both towns that have a population over 1500 and towns that have a population lower than 500?
farm
Find the official names of cities with population bigger than 1500 or smaller than 500.
SELECT Official_Name FROM city WHERE Population > 1500 OR Population < 500
Find the formal names of towns with number of people bigger than 1500 or smaller than 500.
farm
What are the official names of cities that have population over 1500 or less than 500?
SELECT Official_Name FROM city WHERE Population > 1500 OR Population < 500
What are the formal names of towns that have number of people over 1500 or less than 500?
farm
Show the census ranking of cities whose status are not "Village".
SELECT Census_Ranking FROM city WHERE Status != "Village"
Show the count of population ranking of towns whose status are not "Village".
farm
What are the census rankings of cities that do not have the status "Village"?
SELECT Census_Ranking FROM city WHERE Status != "Village"
What are the count of population rankings of towns that do not have the status "Village"?
farm
which course has most number of registered students?
SELECT T1.course_name FROM courses AS T1 JOIN student_course_registrations AS T2 ON T1.course_id = T2.course_Id GROUP BY T1.course_id ORDER BY count(*) DESC LIMIT 1
which curriculum has most number of registered students?
student_assessment
What is the name of the course with the most registered students?
SELECT T1.course_name FROM courses AS T1 JOIN student_course_registrations AS T2 ON T1.course_id = T2.course_Id GROUP BY T1.course_id ORDER BY count(*) DESC LIMIT 1
What is the name of the curriculum with the most registered students?
student_assessment
what is id of students who registered some courses but the least number of courses in these students?
SELECT student_id FROM student_course_registrations GROUP BY student_id ORDER BY count(*) LIMIT 1
what is id of students who registered some curriculums but the least number of curriculums in these students?
student_assessment
What are the ids of the students who registered for some courses but had the least number of courses for all students?
SELECT student_id FROM student_course_registrations GROUP BY student_id ORDER BY count(*) LIMIT 1
What are the ids of the students who registered for some courses but had the least number of courses for all students?
student_assessment
what are the first name and last name of all candidates?
SELECT T2.first_name , T2.last_name FROM candidates AS T1 JOIN people AS T2 ON T1.candidate_id = T2.person_id
what are the forename and surname of all candidates?
student_assessment
What are the first and last names of all the candidates?
SELECT T2.first_name , T2.last_name FROM candidates AS T1 JOIN people AS T2 ON T1.candidate_id = T2.person_id
What are the full names of all the candidates?
student_assessment
List the id of students who never attends courses?
SELECT student_id FROM students WHERE student_id NOT IN (SELECT student_id FROM student_course_attendance)
List the id of students who never attends curriculum?
student_assessment
What are the ids of every student who has never attended a course?
SELECT student_id FROM students WHERE student_id NOT IN (SELECT student_id FROM student_course_attendance)
What are the ids of every student who has never attended a curriculum?
student_assessment
List the id of students who attended some courses?
SELECT student_id FROM student_course_attendance
List the id of students who attended some curriculums?
student_assessment
What are the ids of all students who have attended at least one course?
SELECT student_id FROM student_course_attendance
What are the ids of all students who have attended at least one curriculum?
student_assessment
What are the ids of all students for courses and what are the names of those courses?
SELECT T1.student_id , T2.course_name FROM student_course_registrations AS T1 JOIN courses AS T2 ON T1.course_id = T2.course_id
What are the ids of all students for curriculums and what are the names of those curriculums?
student_assessment
What is detail of the student who most recently registered course?
SELECT T2.student_details FROM student_course_registrations AS T1 JOIN students AS T2 ON T1.student_id = T2.student_id ORDER BY T1.registration_date DESC LIMIT 1
What is detail of the student who most recently registered curriculum?
student_assessment
What details do we have on the students who registered for courses most recently?
SELECT T2.student_details FROM student_course_registrations AS T1 JOIN students AS T2 ON T1.student_id = T2.student_id ORDER BY T1.registration_date DESC LIMIT 1
What details do we have on the students who registered for courses most recently?
student_assessment
How many students attend course English?
SELECT count(*) FROM courses AS T1 JOIN student_course_attendance AS T2 ON T1.course_id = T2.course_id WHERE T1.course_name = "English"
How many students attend curriculum English?
student_assessment
How many students are attending English courses?
SELECT count(*) FROM courses AS T1 JOIN student_course_attendance AS T2 ON T1.course_id = T2.course_id WHERE T1.course_name = "English"
How many students are attending English curriculum?
student_assessment
How many courses do the student whose id is 171 attend?
SELECT count(*) FROM courses AS T1 JOIN student_course_attendance AS T2 ON T1.course_id = T2.course_id WHERE T2.student_id = 171
How many curriculums do the student whose id is 171 attend?
student_assessment
How many courses does the student with id 171 actually attend?
SELECT count(*) FROM courses AS T1 JOIN student_course_attendance AS T2 ON T1.course_id = T2.course_id WHERE T2.student_id = 171
How many curriculums does the student with id 171 actually attend?
student_assessment
Find id of the candidate whose email is [email protected]?
SELECT T2.candidate_id FROM people AS T1 JOIN candidates AS T2 ON T1.person_id = T2.candidate_id WHERE T1.email_address = "[email protected]"
Find id of the candidate whose email is [email protected]?
student_assessment
What is the id of the candidate whose email is [email protected]?
SELECT T2.candidate_id FROM people AS T1 JOIN candidates AS T2 ON T1.person_id = T2.candidate_id WHERE T1.email_address = "[email protected]"
What is the id of the candidate whose email is [email protected]?
student_assessment
Find id of the candidate who most recently accessed the course?
SELECT candidate_id FROM candidate_assessments ORDER BY assessment_date DESC LIMIT 1
Find id of the candidate who most recently accessed the curriculum?
student_assessment
What is the id of the candidate who most recently accessed the course?
SELECT candidate_id FROM candidate_assessments ORDER BY assessment_date DESC LIMIT 1
What is the id of the candidate who most recently accessed the curriculum?
student_assessment
What is detail of the student who registered the most number of courses?
SELECT T1.student_details FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id ORDER BY count(*) DESC LIMIT 1
What is detail of the student who registered the most number of courses?
student_assessment
What are the details of the student who registered for the most number of courses?
SELECT T1.student_details FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id ORDER BY count(*) DESC LIMIT 1
What are the details of the student who registered for the most number of courses?
student_assessment
List the id of students who registered some courses and the number of their registered courses?
SELECT T1.student_id , count(*) FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id
List the id of students who registered some curriculums and the number of their registered curriculums?
student_assessment
For every student who is registered for some course, how many courses are they registered for?
SELECT T1.student_id , count(*) FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id
For every student who is registered for some curriculum, how many curriculums are they registered for?
student_assessment
How many registed students do each course have? List course name and the number of their registered students?
SELECT T3.course_name , count(*) FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id JOIN courses AS T3 ON T2.course_id = T3.course_id GROUP BY T2.course_id
How many registed students do each curriculum have? List curriculum name and the number of their registered students?
student_assessment
For each course id, how many students are registered and what are the course names?
SELECT T3.course_name , count(*) FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id JOIN courses AS T3 ON T2.course_id = T3.course_id GROUP BY T2.course_id
For each curriculum id, how many students are registered and what are the curriculum names?
student_assessment
Find id of candidates whose assessment code is "Pass"?
SELECT candidate_id FROM candidate_assessments WHERE asessment_outcome_code = "Pass"
Find id of candidates whose assessment code is "Pass"?
student_assessment
What are the ids of the candidates that have an outcome code of Pass?
SELECT candidate_id FROM candidate_assessments WHERE asessment_outcome_code = "Pass"
What are the ids of the candidates that have an outcome code of Pass?
student_assessment
Find the cell mobile number of the candidates whose assessment code is "Fail"?
SELECT T3.cell_mobile_number FROM candidates AS T1 JOIN candidate_assessments AS T2 ON T1.candidate_id = T2.candidate_id JOIN people AS T3 ON T1.candidate_id = T3.person_id WHERE T2.asessment_outcome_code = "Fail"
Find the cell phone number of the candidates whose assessment code is "Fail"?
student_assessment
What are the cell phone numbers of the candidates that received an assessment code of "Fail"?
SELECT T3.cell_mobile_number FROM candidates AS T1 JOIN candidate_assessments AS T2 ON T1.candidate_id = T2.candidate_id JOIN people AS T3 ON T1.candidate_id = T3.person_id WHERE T2.asessment_outcome_code = "Fail"
What are the cell phone numbers of the candidates that received an assessment code of "Fail"?
student_assessment
What are the id of students who registered course 301?
SELECT student_id FROM student_course_attendance WHERE course_id = 301
What are the id of students who registered course 301?
student_assessment
What are the ids of the students who registered for course 301?
SELECT student_id FROM student_course_attendance WHERE course_id = 301
What are the ids of the students who registered for course 301?
student_assessment
What is the id of the student who most recently registered course 301?
SELECT student_id FROM student_course_attendance WHERE course_id = 301 ORDER BY date_of_attendance DESC LIMIT 1
What is the id of the student who most recently registered course 301?
student_assessment
What are the ids of the students who registered for course 301 most recently?
SELECT student_id FROM student_course_attendance WHERE course_id = 301 ORDER BY date_of_attendance DESC LIMIT 1
What are the ids of the students who registered for course 301 most recently?
student_assessment
Find distinct cities of addresses of people?
SELECT DISTINCT T1.city FROM addresses AS T1 JOIN people_addresses AS T2 ON T1.address_id = T2.address_id
Find different towns of locations of people?
student_assessment
What are the different cities where people live?
SELECT DISTINCT T1.city FROM addresses AS T1 JOIN people_addresses AS T2 ON T1.address_id = T2.address_id
What are the different towns where people live?
student_assessment
Find distinct cities of address of students?
SELECT DISTINCT T1.city FROM addresses AS T1 JOIN people_addresses AS T2 ON T1.address_id = T2.address_id JOIN students AS T3 ON T2.person_id = T3.student_id
Find different towns of location of students?
student_assessment
What are the different cities where students live?
SELECT DISTINCT T1.city FROM addresses AS T1 JOIN people_addresses AS T2 ON T1.address_id = T2.address_id JOIN students AS T3 ON T2.person_id = T3.student_id
What are the different towns where students live?
student_assessment
List the names of courses in alphabetical order?
SELECT course_name FROM courses ORDER BY course_name
List the names of curriculums in alphabetical order?
student_assessment
What are the names of the courses in alphabetical order?
SELECT course_name FROM courses ORDER BY course_name
What are the names of the curriculums in alphabetical order?
student_assessment
List the first names of people in alphabetical order?
SELECT first_name FROM people ORDER BY first_name
List the forenames of people in alphabetical order?
student_assessment
What are the first names of the people in alphabetical order?
SELECT first_name FROM people ORDER BY first_name
What are the forenames of the people in alphabetical order?
student_assessment
What are the id of students who registered courses or attended courses?
SELECT student_id FROM student_course_registrations UNION SELECT student_id FROM student_course_attendance
What are the id of students who registered curriculums or attended curriculums?
student_assessment

Dataset Card for Sypder-Syn

Spyder-Syn is a human curated variant of the Spider Text-to-SQL database. The database was created to test the robustness of text-to-SQL models for robustness of synonym substitution.

The source GIT repo for Sypder-Syn is located here: https://github.com/ygan/Spider-Syn

Details regarding the data perterbation methods used and objectives are described in ACL 2021: arXiv

Paper Abstract

Recently, there has been significant progress in studying neural networks to translate text descriptions into SQL queries. Despite achieving good performance on some public benchmarks, existing text-to-SQL models typically rely on the lexical matching between words in natural language (NL) questions and tokens in table schemas, which may render the models vulnerable to attacks that break the schema linking mechanism. In this work, we investigate the robustness of text-to-SQL models to synonym substitution. In particular, we introduce Spider-Syn, a human-curated dataset based on the Spider benchmark for text-to-SQL translation. NL questions in Spider-Syn are modified from Spider, by replacing their schema-related words with manually selected synonyms that reflect real-world question paraphrases. We observe that the accuracy dramatically drops by eliminating such explicit correspondence between NL questions and table schemas, even if the synonyms are not adversarially selected to conduct worst-case adversarial attacks. Finally, we present two categories of approaches to improve the model robustness. The first category of approaches utilizes additional synonym annotations for table schemas by modifying the model input, while the second category is based on adversarial training. We demonstrate that both categories of approaches significantly outperform their counterparts without the defense, and the first category of approaches are more effective.

Citation Information

@inproceedings{gan-etal-2021-towards,
    title = "Towards Robustness of Text-to-{SQL} Models against Synonym Substitution",
    author = "Gan, Yujian  and
      Chen, Xinyun  and
      Huang, Qiuping  and
      Purver, Matthew  and
      Woodward, John R.  and
      Xie, Jinxia  and
      Huang, Pengsheng",
    month = aug,
    year = "2021",
    address = "Online",
    publisher = "Association for Computational Linguistics",
    url = "https://aclanthology.org/2021.acl-long.195",
    doi = "10.18653/v1/2021.acl-long.195",
    pages = "2505--2515",
}
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