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http://demonstrations.wolfram.com/StraightAcrossPuzzle/ | math | First, click the board to drop your man. At each turn you slide North, South, East, or West as far as possible to an empty position. The path you travelled will be marked by straight lines. You cannot go through walls. You can cross your own path at 90°. With each move, you have to turn 90°.
The goal is to travel as many moves as possible. The number of moves is displayed on the left together with the length of the longest known moves, "target".
If you get stuck in a corner and do not have a move to play, you lose. | s3://commoncrawl/crawl-data/CC-MAIN-2018-22/segments/1526794867254.84/warc/CC-MAIN-20180525235049-20180526015049-00207.warc.gz | CC-MAIN-2018-22 | 522 | 3 |
https://code-research.eu/en/the-ratio-of-dogs-and-cat-in-the-neighborhood-was-2-to-5-if-there-10-dogs-predict-how-many-cats-w.53751.html | math | The ratio of dogs and cat in the neighborhood was 2 to 5 . if there 10 dogs ,predict how many cats were there
There would be 25 cats because 2*5=10 and 5*5=25.
Answer: 25 cats Explanation/Calculation: The ratio is 2 dogs to 5 cats. To make this model equal you have to find what can multiply 2*x=10. x=5. After doing this to one side of the equation, it applies to the other. 5*5=25. Therefore, there are 25 cats for sure. | s3://commoncrawl/crawl-data/CC-MAIN-2022-49/segments/1669446711069.79/warc/CC-MAIN-20221206024911-20221206054911-00484.warc.gz | CC-MAIN-2022-49 | 422 | 3 |
https://domaineregentbigot.com/useful/question-what-does-prime-mean-in-math.html | math | - 1 What does prime number mean?
- 2 What does the prime symbol mean in math?
- 3 How do you know if a number is prime?
- 4 Why is 11 not a prime number?
- 5 What is 1 called if it is not a prime?
- 6 Which is the smallest prime number?
- 7 What is the correct symbol for seconds?
- 8 What does double prime mean?
- 9 What does the Prime logo mean?
- 10 Is there a pattern to find prime numbers?
- 11 How do you know if a 3 digit number is prime?
- 12 What are the prime numbers between 1 to 100?
- 13 What is the fastest way to find a prime number?
- 14 What is the opposite of a prime number?
- 15 Is 2 not a prime number?
What does prime number mean?
Prime numbers are numbers that have only 2 factors: 1 and themselves. For example, the first 5 prime numbers are 2, 3, 5, 7, and 11. By contrast, numbers with more than 2 factors are call composite numbers.
What does the prime symbol mean in math?
The Notation of Differentiation
One type of notation for derivatives is sometimes called prime notation. The function f ´( x ), which would be read “ f –prime of x ”, means the derivative of f ( x ) with respect to x. If we say y = f ( x ), then y ´ (read “ y –prime”) = f ´( x ).
How do you know if a number is prime?
To prove whether a number is a prime number, first try dividing it by 2, and see if you get a whole number. If you do, it can’t be a prime number. If you don’t get a whole number, next try dividing it by prime numbers: 3, 5, 7, 11 (9 is divisible by 3) and so on, always dividing by a prime number (see table below).
Why is 11 not a prime number?
Prime number is a positive natural number that has only two positive natural number divisors – one and the number itself. Prime numbers are subset of natural numbers. The number 1 is not a prime number by definition – it has only one divisor.
What is 1 called if it is not a prime?
A natural number greater than 1 that is not prime is called a composite number. For example, 5 is prime because the only ways of writing it as a product, 1 × 5 or 5 × 1, involve 5 itself.
Which is the smallest prime number?
The first 1000 prime numbers
What is the correct symbol for seconds?
The second (symbol: s, abbreviation: sec) is the base unit of time in the International System of Units (SI) (French: Système International d’unités), commonly understood and historically defined as 1⁄86400 of a day – this factor derived from the division of the day first into 24 hours, then to 60 minutes and finally
What does double prime mean?
: the symbol ″ used to distinguish arbitrary characters (such as a, a′, and a″), to indicate a specific unit (such as inches), or to indicate the second derivative of a function (such as p″ or f″(x)) — compare prime sense 7.
What does the Prime logo mean?
The Amazon logo was created to represent the message that it sells everything from A to Z (the arrow connects the two letters) and also represents the smile that customers would experience by shopping on the Amazon.com Web site (the arrow becomes a smile) — Hidden Meanings in 12 Popular Logos — AOL News — AOL.com.
Is there a pattern to find prime numbers?
Now, however, Kannan Soundararajan and Robert Lemke Oliver of Stanford University in the US have discovered that when it comes to the last digit of prime numbers, there is a kind of pattern. Apart from 2 and 5, all prime numbers have to end in 1, 3, 7 or 9 so that they can’t be divided by 2 or 5.
How do you know if a 3 digit number is prime?
Take a number, say, 26577. The unit digit of this number is not 0, 2, 4, 6 or 8. Now, take the sum of digits which will be: 2 + 6 + 5 + 7 + 7 = 27. Since 27 is divisible by 3, 26577 is not a prime number.
What are the prime numbers between 1 to 100?
For example, there are 25 prime numbers from 1 to 100: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97.
What is the fastest way to find a prime number?
A prime sieve or prime number sieve is a fast type of algorithm for finding primes. There are many prime sieves. The simple sieve of Eratosthenes (250s BCE), the sieve of Sundaram (1934), the still faster but more complicated sieve of Atkin, and various wheel sieves are most common.
What is the opposite of a prime number?
On the other hand, the number 1 is not a prime number. Composite numbers are basically positive integers that can be divided by any positive number other than themselves. In other words, composite numbers are the opposite of prime numbers. Examples include 4, 6, 8, 9, 10, 12 and 14.
Is 2 not a prime number?
The first five prime numbers: 2, 3, 5, 7 and 11. A prime number is an integer, or whole number, that has only two factors — 1 and itself. Put another way, a prime number can be divided evenly only by 1 and by itself. Prime numbers also must be greater than 1. | s3://commoncrawl/crawl-data/CC-MAIN-2022-33/segments/1659882573760.75/warc/CC-MAIN-20220819191655-20220819221655-00011.warc.gz | CC-MAIN-2022-33 | 4,845 | 46 |
https://www.hackmath.net/en/math-problem/22583 | math | What is bigger?
Which ball has a larger volume: a football with a circumference of 66 cm or a volleyball with a diameter of 20 cm?
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The cylinder volume is 150 dm cubic, the base diameter is 100 cm. What is the height of the cylinder? | s3://commoncrawl/crawl-data/CC-MAIN-2020-45/segments/1603107880519.12/warc/CC-MAIN-20201023014545-20201023044545-00193.warc.gz | CC-MAIN-2020-45 | 2,413 | 40 |
https://dokumen.tips/documents/23-the-chain-rule-and-higher-order-derivatives.html | math | §2.3 The Chain Rule and Higher Order Derivatives. The student will learn about. composite functions,. the chain rule, and. nondifferentiable functions. Composite Functions. Definition. A function m is a composite of functions f and g if - PowerPoint PPT Presentation
Text of §2.3 The Chain Rule and Higher Order Derivatives
*2.3 The Chain Rule and Higher Order DerivativesThe student will learn aboutcomposite functions, the chain rule, andnondifferentiable functions.
*Composite Functions Definition. A function m is a composite of functions f and g if m (x) = f g = f [ g (x)]This means that x is substituted into g first. The result of that substitution is then substituted into the function f for your final answer.
*ExamplesLet f (u) = u 3 , g (x) = 2x + 5, and m (v) = v. Find: f [ g (x)] = g [ f (x)] =g (x3) = m [ g (x)] = f (2x + 5) =(2x + 5)3m (2x + 5) = 2x 3 + 5 2x + 5
*Chain Rule: Power Rule. We have already made extensive use of the power rule with xn, We wish to generalize this rule to cover [u (x)]n, where u (x) is a composite function. That is it is fairly complicated. It is not just x.
*Chain Rule: Power Rule. That is, we already know how to find the derivative of f (x) = x 5We now want to find the derivative of f (x) = (3x 2 + 2x + 1) 5What do you think that might be?
* General Power Rule. [Chain Rule]If u (x) is a function, n is any real number, andIf f (x) = [u (x)]nthenf (x) = n un 1 uor* * * * * VERY IMPORTANT * * * * *Chain Rule: Power Rule.
*ExampleFind the derivative of y = (x3 + 2) 5.Let the ugly function be u (x) = x3 + 2. Then5(x3 + 2)3x24= 15x2(x3 + 2)4
*ExampleFind the derivative of y =Rewrite as y = (x 3 + 3) 1/2 = 3/2 x2 (x3 + 3) 1/2Then y = 1/2Then y = 1/2 (x 3 + 3) 1/2Then y = 1/2 (x 3 + 3) 1/2 (3x2)Try y = (3x 2 - 7) - 3/2 y = (- 3/2) (3x 2 - 7) - 5/2 (6x)= (- 9x) (3x 2 - 7) - 5/2
*ExampleFind f (x) if f (x) = We will use a combination of the quotient rule and the chain rule.Let the top be t (x) = x4, then t (x) =4x3Let the bottom be b (x) = (3x 8)2, then using the chain rule b (x) = 2 (3x 8) 3 =6 (3x 8)
*Remember Def: The instantaneous rate of change for a function, y = f (x), at x = a is: This is the derivative.Sometimes this limit does not exist. When that occurs the function is said to be nondifferentiable.
*Remember Def: The instantaneous rate of change for a function, y = f (x), at x = a is: This is the derivative and a graphing way to represent the derivative is as the slope of the curve. This means that at some points on some curves the slope is not defined.
*"If a function f "
*Summary. Ify = f (x) = [u (x)]nthenNondifferentiable functions. | s3://commoncrawl/crawl-data/CC-MAIN-2020-40/segments/1600400227524.63/warc/CC-MAIN-20200925150904-20200925180904-00614.warc.gz | CC-MAIN-2020-40 | 2,620 | 15 |
http://www.primidi.com/closed_operator/transpose | math | Let T : B1 → B2 be an operator between Banach spaces. Then the transpose (or dual) of T is an operator satisfying:
for all x in B1 and y in B2*. Here, we used the notation: .
The necessary and sufficient condition for the transpose of T to exist is that T is densely defined (for essentially the same reason as to adjoints, as discussed above.)
For any Hilbert space H, there is the anti-linear isomorphism:
given by where . Through this isomorphism, the transpose T' relates to the adjoint T∗ in the following way:
where . (For the finite-dimensional case, this corresponds to the fact that the adjoint of a matrix is its conjugate transpose.) Note that this gives the definition of adjoint in terms of a transpose.
Read more about this topic: Closed Operator
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... Language/Library Create Determinant Transpose Element Column Row Eigenvalues Fortran m=RESHAPE(, SHAPE(m)) TRANSPOSE(m) m(i,j) m(,j) m(i,) Ch m ...
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Famous quotes containing the word transpose:
“We have to transpose ourselves into this impressionability of mind, into this sensitivity to tears and spiritual repentance, into this susceptibility, before we can judge how colorful and intensive life was then.”
—Johan Huizinga (18721945) | s3://commoncrawl/crawl-data/CC-MAIN-2018-51/segments/1544376824912.16/warc/CC-MAIN-20181213145807-20181213171307-00165.warc.gz | CC-MAIN-2018-51 | 2,004 | 15 |
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Act math skill review: word problems some of the problems on the act math test will be presented as word problems sometimes the wording is so dense that it’s easy. A video model showing how to teach a step by step process to solve word problems this video shows a simple way to solve word problems. Be sure to check the similar questions to see if your question has already been answered get math help learning resources wyzant scholarships work with us. | s3://commoncrawl/crawl-data/CC-MAIN-2018-43/segments/1539583514443.85/warc/CC-MAIN-20181022005000-20181022030500-00062.warc.gz | CC-MAIN-2018-43 | 3,422 | 6 |
http://synergyfiles.com/2015/11/calculation-of-insolation-on-inclined-surface-accurate-method/ | math | In this article, information regarding the calculation of insolation (incident solar radiation) on an inclined surface by an accurate method is presented. Accurate estimation of insolation on inclined surface is important for feasibilty calculation of not just solar farms but also for domestic roof top installation.
In a previous post, a relatively easy method to work out solar radiation falling on an inclined surface was looked at. That particular method did not take position of the sun into account at a particular time.
In this method a more complex equation will be used. The results are very accurate however it must be added that this method too, like many others does not take into account the effect of cloud cover.
In order to determine the component of radiation falling over an inclined surface, the following equation is used:
Cosθ = sinδsinΦ cosβ – sinδcosΦsinβcosγ + cosδcosωcosΦcosβ +Cosδ Cosω SinΦ Sinβ Cosγ + Cosδ Sinβ Sinγ Sinω …..(1)
Where ϴ – Angle of incidence of beam radiation on surface
Φ – Latitude of the location (Position on the Earth)
δ – Declination (time of the year)
ω- hour angle (time of day)
β – Slope of surface (w.r.t the horizontal)
γ –Surface Azimuth Angle (Orientation w.r.t the meridian)
Thus the projection of sun rays on the inclined surface”ϴ” is a function of (Φ,δ,ω,β,γ)
As the hour angle ω is factored into the equation (1), solar radiation falling on a surface can be calculated for any time of the day. The hour angle needs to be calculated for any particular time and its method is explained below. The hour angle has to be calculated for thousand of hours if an annual average insolation needs to be worked out (using hourly data of horizontal radiation). For this reason, the use of spread sheet software is highly recommended.
The intensity of the beam radiation on a tilted surface or horizontal surface GS, equivalent to the direct normal beam radiation, GDN, multiplied by cosine of the angle of incidence of beam radiation on the surface:
GS = GDNCosϴ
To calculate the hour angle ω, the solar time needs to be worked out first.
Calculating Solar time
Solar time and local time are two different entities although there are moments when the two of them align. In solar time sunrise occurs at 6:00 am sunset occurs at 6:00 pm and the sun reaches its zenith at 12:00 noon. From our observation we know that Solar Noon may not occur at 12:00 pm local time.
The real solar noon shifts in apparent time because the length of the day is not fixed and varies day to day across the year. The change in day length is from it 24 hour average is because of the orbit eccentricity and the effect of obliquity.
This phenomenon of changing day length is captured by the equation of time. The day length can vary as much as 16 minutes from average of 24 hours. Measures such as time adjustment for winter’s season adopted by many countries (day light saving) also shift the local time from the solar time. Only at the equator, the solar time closely follows the local time but still remains different from it.
minimum −14:15 11 February
zero 00:00 15 April
maximum +03:41 14 May
zero 00:00 13 June
minimum −06:30 26 July
zero 00:00 1 September
maximum +16:25 3 November
zero 00:00 25 December
Solar time can be worked out using the following equations:
Solar Time =Standard Time + 4(Lst−Lloc)+E
where Lst is the standard meridian for the local time zone, Lloc is the longitude of the location, and E is the difference in time that is defined by:
E=229.2(0.000075+0.001868 cosB−0.032077 sinB−0.014615 cos2B−0.04089 sin2B)
where B is
B=(n−1)*(360/365) ……………………..(B is in degrees)
The equation for E is also called equation of time and there are other versions of it some of them more complex.
Calculating the hour angle ω
To get hour angle from time, multiply hours from noon times 15 degrees per hour (negative for before noon, positive for after). For example if solar time is 10:30 am, this is 1.5 hours before noon, so the hour angle would be -22.5 degrees. Note hour angle at Solar Noon is 0 degree
Once the hour angle is calculated it can be plugged in equation 1 to determine the projection of sun rays on the inclined surface.
For further reading consult: Solar Engineering of Thermal process by John A. Duffie and William A. Beckman | s3://commoncrawl/crawl-data/CC-MAIN-2023-14/segments/1679296943750.71/warc/CC-MAIN-20230322051607-20230322081607-00144.warc.gz | CC-MAIN-2023-14 | 4,372 | 39 |
http://mybostonloft.com/library/innovations-in-intelligent-machines-volume-3-contemporary-achievements-in-intelligent-systems | math | Innovations in Intelligent Machines, Volume 3: Contemporary Achievements in Intelligent Systems (Studies in Computational Intelligence, Volume 442)
Format: PDF / Kindle (mobi) / ePub
This book aims to promote a sample of current theoretical and application oriented intelligent systems research specifically in the field of neural networks computing. It presents examples of experimental and real-world investigations that demonstrate contemporary achievements and advances in the area of intelligent systems.
This book will prove as a valuable source of up-to-date theoretical and application oriented research in intelligent systems for researchers and postgraduate students.
trainers. The instructions given to the subjects were as follows: The purpose of this task is to make the agent learn to keep the balance of the inverted pendulum. Give a “positive” or “negative” evaluation if you think that the agent did or didn't do an action that brings it closer to achieving this task. The initial reward function, denoted r θ at Eq.8, is given as: 1 0 | | (18) This reward function allows the agent to obtain the reward only at the target state. Moreover, it is
اﯼi ) " and that is Table 1. The input vowel and number of vowel recognitions when longitudinal parameters are used Input َا (a) (e) ِا (o) ُا ( â) ﺁ (i) اﯼ او (u) (a) َا 70 2 1 22 0 5 (e) ِا 2 61 27 0 1 9 (o) ُا 3 5 72 2 0 18 ( â) ﺁ 0 0 25 70 0 5 (i) اﯼ 0 4 30 0 65 1 (u) او 3 0 13 4 0 80 Vowel Recognition 66 M.M. Hosseini and A.A. Gharahbagh because of least visual changes. Sadeghi has done similar work for
ambient temperature, while the duration of the spikes gets minor in contrast with the number of them ( three spikes for the case at T=9°C and seven for T=21°C). In particular, as a particular exemplification case in Fig 5c) we have chosen to show when the temperature assumes a particular value of 18.5°C. In this case the membrane response results in a sequence of six APs, shorter than the two observed at lower temperature reported in Figure 4d). In particular we also check the temperature effects
classification environment problem for different types of drinking waters . Listeria monocytogenes is a bi-class problem in predictive microbiology . All nominal variables have been converted to binary ones. Also, the missing values have been replaced in the case of nominal variables by the mode or, when concerning continuous variables, by the mean, considering the full data set. The experimental design uses the cross validation technique called stratified hold-out that consists of
ANNs 147 classes, inputs, instances,…). Other times the values are based on previous works [4, 18]. EDDSig and TSEASig values are in concordance to compare the performance of both methodologies. Sometimes, the values differ between methodologies. The initial tests with sigmoidal units for Balance dataset sheds light on that a high number of neurons provokes overfitting. 4.3 Nonparametric Statistical Analysis We follow the recommendations pointed out by J. Demšar to perform nonparametric | s3://commoncrawl/crawl-data/CC-MAIN-2017-39/segments/1505818687484.46/warc/CC-MAIN-20170920213425-20170920233425-00663.warc.gz | CC-MAIN-2017-39 | 3,103 | 9 |
https://history.stackexchange.com/questions/52613/how-could-it-be-that-80-of-townspeople-were-farmers-during-the-edo-period-in-ja/52614 | math | The total land area of Japan is around 146,000 square miles. 20% of that works out around 29,000 square miles or 18.6 million acres.
The population of Tokugawa japan was around 30 million people. 80% of that is 24 million people. This gives each farmer roughly 3/4s of an acre.
The basic unit of land in Japan was the cho, which was roughly 2.5 acres. This produced roughly 10 koku. A "koku" was the amount of rice needed to feed one person for one year. Simple math gives 4 koku an acre, and therefore 3 koku for 3/4s of an acre. In other words, in theory at least, each person has enough land to grow rice for three.
Thus, if 80% of the population is working 20% of the land in Tokugawa Japan, then they are easily growing enough to feed themselves plus the remaining 20% who are not farmers.
Now of course that's the ideal case, and bad weather, war and other mishaps are going to negatively affect that to the point where in actual fact there were periods of starvation and food related unrest. But it means that "80% of townspeople worked on only 20% of the whole land" is perfectly believable. | s3://commoncrawl/crawl-data/CC-MAIN-2023-40/segments/1695233506686.80/warc/CC-MAIN-20230925051501-20230925081501-00434.warc.gz | CC-MAIN-2023-40 | 1,099 | 5 |
https://umj.imath.kiev.ua/index.php/umj/article/view/2510 | math | Approximation of Periodic Functions of Many Variables in Metric Spaces by Piecewise-Constant Functions
AbstractWe prove the direct and inverse Jackson- and Bernstein-type theorems for averaged approximations of periodic functions of many variables by piecewise-constant functions with uniform partition of the period torus in metric spaces with integral metric given by a function ψ of the type of modulus of continuity.
How to Cite
Agoshkova, T. A. “Approximation of Periodic Functions of Many Variables in Metric Spaces by Piecewise-Constant Functions”. Ukrains’kyi Matematychnyi Zhurnal, Vol. 65, no. 10, Oct. 2013, pp. 1303–1314, https://umj.imath.kiev.ua/index.php/umj/article/view/2510. | s3://commoncrawl/crawl-data/CC-MAIN-2023-50/segments/1700679100942.92/warc/CC-MAIN-20231209170619-20231209200619-00062.warc.gz | CC-MAIN-2023-50 | 701 | 4 |
https://www.slideserve.com/garth-guy/room-acoustics | math | Room Acoustics室内声学 Room acoustics is concerned with the control of sound within an enclosed space. The general aim is to provide the best conditions for the production and the reception接受 of desirable sounds. Noise control was treated in chapter 9 but the exclusion of unwanted noise is an important element of room acoustics
This chapter is concerned with 11.1 Acoustics Principles 声学原理 11.2 Reflection 声音的反射 11.3 Absorption 声音的吸收 11.4 Reverberation 混响声
11.1 Acoustics Principle声学原理 11.1.1 General requirements for good acoustics • Adequate levels of sound 足够的声级 • Even distribution to all listeners in the room 使每位听众都能听到 • reverberation time suitable for the type of room 混响时间与房间类型匹配 • Background noise and external noise reduced to acceptable levels 背景噪声和室外噪声降到规定值 • Absence of echoes回声and similar acoustic defects缺点 避免回声和类似的声学缺陷
An auditorium is a room, usually large, designed to be occupied by an audience. the main purposes of auditorium can be divided into: Speech 演讲 Music音乐 Multi-purpose 多功能 detailed acoustic requirements vary with the purpose of the space, 11.1.2 the main purposes of auditorium?auditorium听众席, 观众席
Speech演讲 • The requirement for a good speech is that the speech is intelligible可理解的. • This quality will depend upon the power and the clarity of the sound. • conference halls会议厅, law courts法庭, theatres剧院, and lecture rooms报告厅.
Music音乐 Music Hall Vienna • There are more acoustic requirements for music than for speech. These qualities are difficult to define but terms in common use include “fullness” of tone声音的丰满度, “definition” of sounds声音的清晰度, ”blend” of sounds声音的混合and “balance ” of sounds声音的平衡.
Multi-purpose 多功能 Compromise of speech and music • Churches, town halls, conference centres, school halls, and some theatres are examples of multi-purpose auditoria.
11.1.3 Sound paths in rooms 声音在室内的传播路径 • reflection反射, • absorption吸收, • transmission透过 • diffraction绕射,
Reflection and absorption play the largest roles in room acoustics
11.2 Reflection 反射 • Sound is reflected in the same way as light, provided that the reflecting object is larger than the wavelength of the sound concerned. • reflection is useful to obtain good room acoustics? Reflecting surfaces in a room are used to help the even distribution of sound
The following general rules apply Reflections near the source of sound can be useful 靠近声源的反射有用 Reflections at a distance from the source may be troublesome. 远离声源的反射可能是不利的 Plane reflector 平面反射板 Curved reflector 曲面反射板
Figure 11.3 Reflection from room surfaces • Concave surfaces 凹面 tend to focus sound • Convex surfaces 凸面 tend to disperse sound
The domed ceilings 穹顶of the Royal Albert Hall in London皇家爱尔伯特音乐厅, have often contributed to unsatisfactory acoustics and required remedies.
if a strong reflection is received later than 1/20th second after the reception of the direct sound. There is a risk of a distinct echo An echo is a delayed reflection 回声是延迟的反射声 Reflections at a distance from the source may be troublesome.远离声源的反射可能是不利的
in smaller rooms + smooth parallel surfaces Flutter echoes多次回声are rapid reflections which cause a “buzzing” 嗡嗡 Each frequency of a sound has a wavelength. If the distance between parallel surfaces equal the length of half a wave, or a multiple of a half wavelength. standing waves 驻波or room resonances共鸣, which are detected as large variation in sound level at different positions. Standing wave effects are most noticeable for low-frequency sounds in smaller rooms and, in general , parallel reflecting surfaces should be avoided
what Hall shapes would be better? • Rectangular 矩形 • Wind fan 宽的扇形 • Horse shoe 马蹄形 • Raked seats 阶梯座位
11.2 Reflection 反射11.3 Absorption 吸声 Different materials and constructions have different absorption coefficients the coefficient for any one material varies with the frequency of the incident sound. 11.3.1 Absorption coefficient 吸声系数
Table 11.1 • lists the average absorption coefficients of some common materials at the standard frequencies used in acoustic studies. • Clinker 煤渣;炉渣;煤渣块 • Clinker blocks 煤渣砌块
11.3.2 Total absorption 总的吸声 The total Absorption of a surface The total absorption of a room Is the sum of the products of all areas and their respective absorption coefficients Unit:m2 sabins or “absorption units”
11.3.3 Types of absorber 吸声体的类型 • can be classified into three main types which have maximum effect at different frequencies (1) Porous absorbers for high frequencies 吸收高频的多孔吸声体 (2) Panel absorbers for lower frequencies 吸收低频的平板吸声体 (3) Cavity absorbers for specific lower frequencies 吸收超低频的空心吸声体
(1) Porous absorbers 多孔吸声体 • fibreglass 玻璃纤维and mineral wool矿棉. • The cells should interconnect with one another • some foamed plastics 泡沫塑料is not the most effective form for sound absorption. • The absorption of porous materials is most effective at frequencies above 1kHz, • the low frequency absorption can be improved slightly by using increased thickness of materials.
(2) Panel absorbers平板吸声体 Panel or membrane膜absorbers resonant frequency共振频率 m _ the mass of the panel ( kg/m2) d_ the depth of the airspace (m) A panel absorber is most effective for low frequencies in the range 40 to 400Hz.
(3) Cavity absorbers 空腔吸声体 Helmholtz resonators亥姆霍兹共振器 are enclosures of air with one narrow opening. The maximum absorption occurs at the resonant frequency of the cavity
Practical absorbers 实际的吸声体 • Practical absorbers often absorb sounds by a combination of several different methods
11.4 Reverberation 混响声 • An echo standing waves 驻波or room resonances共鸣 • Reverberation is a continuation and enhancement of a sound caused by rapid multiple reflections between the surfaces of a room. 混响声是房间表面间快速多次 反射引起的持续增强的声音 the same as an echo?
11.4.1 Reverberation time 混响时间 • Reverberation time Is the time taken for a sound to decay by 60 dB from its original level.
The time taken for this decay in a room depends upon the following factors. • Areas of exposed surfaces 暴露表面的面积 • Sound absorption at the surface表面的吸声量 • Distance between the surfaces 表面间的距离 • Frequency of the sound 声音的频率
Different activities require different reverberation time Speech : 0.5 to 1 second Music: 1 to 2 seconds Short reverberation times短的混响时间 are necessary for clarity of speech, otherwise the continuing presence of reverberant sound will mask the next syllable音节and cause the speech to be blurred模糊. Longer reverberation times长的混响时间 are considered to enhance the quality of music , otherwise sound “dry ” or “dead” if the reverberations time is too short. Larger rooms are judged to require longer reverberation times 11.4.2 Ideal reverberation time 理想混响时间
Optimum reverberation times最佳混响时间 Stephens and Bate formula r= 4 for speech, 5 for orchestras管弦乐队, 6 for choirs合唱团 Ideal reverberation times can be presented in sets of graphs, such as those shown in figure 11.10
Sabine’s formula赛宾混响公式 Eyting’s formula 依林混响公式 11.4.3 Reverberation time formulas A= total absorption of room surfaces (m2 sabins)室内界面总吸声量 =∑(surface area X absorption coefficient)各表面面积X吸收系数 S= total area of surfaces m2房间的总表面面积
The Sabine formula is suitable for rooms without excessive absorption. If the average absorption in a room is high, such as in a broadcasting studio, Eyting’s formula
11.4.4 Calculation of reverberation time reverberation times are calculated by finding the total absorption units in a room and then using a formula such as Sabine’s formula. Do not directly add or subtract reverberation times with one another. Use sabine’s formula to convert reverberation times to absorption units, make adjustments by addition or subtraction of absorption units, then convert back to reverberation time.
Worked example 11.1 A hall has a volume of 5000 m3 and a reverberation time of 1.6s. Calculate the amount of extra absorption required to obtain a reverberation time of 1s . Know t1=1.6s A1=? t2= 1.0s A2=? V=5000 m3 Using
Worked example 11.2 A lecture hall with a volume of 1500m3 has the following surface finishes areas and absorption coefficients at 500Hz Calculate the reverberation time ( for a frequency of 500Hz) of this hall when it is occupied by 100 people.
Worked example 11.3 The reverberation time required for the hall in worked example 10.2 is 0.8s. Calculate the area of acoustic tiling吸声瓦needed, on the walls to achieve this reverberation time( absorption coefficient of tiles = 0.4 at 500Hz)
Today’s key words • Room acoustics 室内声学 • reverberation time 混响时间 • Background noise 背景噪声 • External noise 室外噪声 • Echoes 回声 • Plane reflector 平面反射板 • Curved reflector 曲面反射板 • standing waves 驻波or room resonances共鸣,
Porous absorber 多孔吸声体 • Panel absorber 平板吸声体 • Cavity absorber 空腔吸声体 • Absorption coefficient 吸声系数
Today’s key sentences • within an enclosed space封闭空间内的 • play the largest roles in ( ) room acoustics
Exercise in class 1 Porous absorbers for ( ) A high frequency B lower frequency C specific lower frequency D specific high frequency
(2) Panel absorbers for ( ) A high frequency B lower frequency C specific lower frequency D specific high frequency
(3) Cavity absorbers for ( ) A high frequency B lower frequency C specific lower frequency D specific high frequency | s3://commoncrawl/crawl-data/CC-MAIN-2020-34/segments/1596439736057.87/warc/CC-MAIN-20200810145103-20200810175103-00250.warc.gz | CC-MAIN-2020-34 | 10,350 | 41 |
https://www.thefreelibrary.com/Quantum+physics+may+offer+clues+to+solving+prime+number+problem:...-a0186320999 | math | Quantum physics may offer clues to solving prime number problem: electron energy levels linked to Riemann hypothesis.
German Sierra of the Spanish National Research Council in Madrid and Paul Townsend of the University of Cambridge in England propose that when an electron is confined to moving in two dimensions, its possible energy level values might encode the key to the hypothesis.
"They have gone a step forward toward giving a physical description of the Riemann hypothesis," says Jonathan Keating of the University of Bristol in England. He warns, though, that the problem may not have gotten easier as a result.
The hypothesis, or conjecture, was proposed by German mathematician Bernhard Riemann in 1859. It is regarded as important in large part because proving it would help reign in the apparent chaos in the world of prime numbers--whole numbers, such as 2, 3, 5, 7, 11 and so on, that can't be wholly divided by any numbers except 1 and themselves.
The hypothesis also has a $1 million "wanted" sign: The Clay Mathematics Institute in Cambridge, Mass., has offered a cash prize in exchange for the proof.
Mathematicians, at least since Euclid, have known that the list of prime numbers is infinite. But only one pattern has ever emerged from this list of primes. The prime number theorem, proved in the late 1800s, describes how primes become less frequent among larger numbers.
Roughly, it says that from one to 1 million (or [10.sup.6]), about one in every six numbers is prime; between one and 1 billion (or [10.sup.9]), it's about one in every nine. In general, between one and [10.sup.n], about one number for every n is a prime. (The actual statement includes a correction factor but is similar in spirit.)
At first sight, the Riemann hypothesis has nothing to do with prime numbers. It is a conjecture about a formula called Riemann's zeta function, which calculates a number for every point on a plane. Riemann's intuition was that the "zeros" of the function--points where zeta calculates the value zero--can lie along one of only two straight lines on the plane.
Mathematicians have shown that if the hypothesis is true, it would bolster the prime number theorem, implying there are no wild statistical fluctuations in the distribution of primes. While primes would still be unpredictable, complete chaos wouldn't rule.
Researchers have long suspected that there might be a way to convert the Riemann hypothesis into an equation similar to those used in quantum physics. The zeros of the zeta function could then be calculated the same way physicists, for example, calculate the possible energy levels for an electron in an atom.
Building on the ideas of Keating and others, Sierra and Townsend make that connection a bit more concrete. They suggest that an electron constrained to move in two dimensions, and subject to electric and magnetic fields, might have energy levels that match the zeros of the zeta function.
Demonstrating the existence of such a system, even on paper, would confirm the Riemann hypothesis. The physicists haven't quite done that, though. Their explicit model gives only an approximation of the energy levels they needed.
In the opinion of mathematician Enrico Bombieri of the Institute for Advanced Study in Princeton, N.J., the paper constitutes modest progress. He says physicists still haven't demonstrated a true connection between the function and physics. Until then, he adds, "attempts of this type belong to the works based on 'wishful thinking,' or even 'pie in the sky.'"
Keating, however, is more optimistic. "Maybe it will suggest further developments in the subject," he says.
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|Date:||Sep 27, 2008|
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https://www.irmi.com/articles/expert-commentary/a-cautionary-tale-about-captive-risk-distribution | math | Risk distribution, also known as risk sharing, is a fundamental feature of insurance. I think that the best definition of risk distribution is this: The (actuarially credible) premiums of the many pay the (expected) losses of the few. This is the essence of insurance.
Single-parent captives that cannot spread their parents' risks over a pool of disparate corporate entities are not captives; they're financial vehicles into which the parents have transferred funds for the purpose of paying their insurable losses. As such, the parents of such financial vehicles cannot deduct their payments (they're not premiums because the vehicle is not an insurer) from their U.S. federal income taxes.
Homogeneity of Loss Exposures
This is as far as most people go in their interpretation of Revenue Ruling 2005–40; spread the risk among at least 12 independent entities and risk distribution ensues. However, there is another aspect of this revenue ruling that many people miss or ignore—homogeneity of loss exposures. Each of the four situations in the revenue ruling state that the risks in question are homogeneous; they are the same line of insurance, and the same line of business. For example, a fleet of 100 tractor-trailer trucks that traverse the country each week are each subject to the same type, frequency, and severity of automobile liability losses.
Many captive practitioners disagree with the notion that in order to attain risk distribution the risks must be homogeneous. Their argument is based on portfolio theory. They reason that heterogeneous groups, by virtue of their uncorrelated loss characteristics, produce risk distribution. It is true that a portfolio of loss exposures is, to some degree, mathematically predictable due to the portfolio's internal hedging—when a loss occurs in one line or one company, there are two or three others that do not produce a loss.
While this is true, the portfolio effect is not the basis for calculating expected losses. The primary requirement for the calculation of expected losses is a large pool of homogeneous risks; this is what transforms a loss funding vehicle into a bona fide insurance company. Therefore, only a large number of homogeneous risks create risk distribution. There is no other way to interpret Revenue Ruling 2005–40.
For example, a group of 10 middle-market bakeries exhibit similar exposures to workers compensation losses, and if the collective historical loss data are actuarially credible, i.e., are large enough, expected losses, premiums, rates, and surplus requirements may be reasonably determined in order to form a captive. In these types of captives, a safe premium-to-surplus ratio may be between 5 to 1 and 3 to 1.
Now, add to this group of bakeries the workers compensation risks of 2 valve manufacturers, 1 cement contractor, 3 utilities contractors, and 2 banks. We now have a heterogeneous group with 18 members, and so the prevailing argument goes, the loss outcomes for the portfolio should be more predictable than that of the portfolio with only 10 homogeneous risks, because of the noncorrelation among the various workers compensation loss profiles. This is true, noncorrelation reduces volatility, but reducing the portfolio's volatility does not create risk distribution—only the ability to determine expected losses, rates, premiums, and surplus, in other words, form an insurance company, creates risk distribution.
In this example, the eight additional risks do nothing to enhance the loss predictability of the bakeries, and unless the others are very large companies, they cannot generate loss predictability on their own. (If they were very large, they wouldn't be joining a group of middle-market bakeries.) Actually, these eight additional risks decrease the actuary's ability to calculate expected workers compensation losses for the group. In this case, the funding requirements would have to be very high, thus rendering the captive uncompetitive and unattractive, even to the bakeries. This is because the portfolio effect does not create risk distribution.
Not only are the group's losses not reasonably predictable in this scenario, the surplus requirements cannot be as easily determined as in the example with just the 10 bakeries. In fact, in this scenario, we would be negligent if we used the above solvency benchmarks, as the workers compensation risk profile of the contractors and manufacturers are far different than that of the bakeries. Some might say that the banks' relatively low loss probability would offset the others' losses. That might be true, but we still cannot accurately calculate expected losses for the group, which is the primary objective for an insurer, so we still do not have risk distribution as prescribed in Revenue Rule 2005–40.
The point to remember is that expected losses can only be reasonably determined when the risk pool has enough homogeneity, and the goal of risk distribution is the ability to predict future losses so rates, premiums, and surplus requirements can be reasonably determined. This is done solely on a per-line of business basis. Large commercial insurers need not worry about this, of course, as they have actuarially credible pools of contractors, manufacturers, and bakeries for each line of coverage they offer. Captives, on the other hand, cannot rely on portfolio theory to substitute for risk distribution.
An excellent example of why homogeneity is required for risk distribution (and therefore future loss predictability) is the National Council on Compensation, Inc. (NCCI). The NCCI gathers loss data for a large number of industries, and establishes loss rates for each. Workers compensation rates are a combination of loss costs and expenses. (Workers compensation insurers generally add the expense component, but the NCCI will do so for several states.)
The NCCI loss costs are based on the enormous homogeneous pools of data generated by every industry. If the portfolio effect produced risk distribution, the NCCI could simply lump all industry loss data into a single pool, creating a huge number of uncorrelated risks, and every employer in the 35 NCCI states would pay the exact same workers compensation loss cost rate.
The portfolio effect is useful in helping to determine proper surplus requirements for a captive with several lines of actuarially credible pools of homogeneous risks. For example, Captive A covers its parent's subsidiaries' workers compensation, general liability, and long-term disability risks. The parent is a large multinational company, with a large number of independent subsidiaries, so each line of insurance has enough homogeneous exposure units spread among a large group of corporate entities to calculate expected losses (risk distribution).
We can prove mathematically that a portfolio (captive) with three lines require less surplus than would each line of insurance individually. If none of the three lines had enough exposure units to create risk distribution, the portfolio effect might still be somewhat valuable in determining the surplus requirements, but it would not create risk distribution.
Finally, I recognize that the portfolio effect can be a powerful ally in managing a multiline captive's loss volatility. Uncorrelated risks, as with uncorrelated investments, in a portfolio produce better, more predictable outcomes than do the simple sums of the risks or investments. But as every actuary knows, the loss predictability that results from the portfolio effect, while a very good thing, is not a substitute for the predictability calculated from a large amount of homogeneous loss data. And it's the ability to predict expected losses that creates risk distribution. | s3://commoncrawl/crawl-data/CC-MAIN-2023-50/segments/1700679100705.19/warc/CC-MAIN-20231207221604-20231208011604-00035.warc.gz | CC-MAIN-2023-50 | 7,728 | 16 |
https://feedback.splitwise.com/users/937867306-shantanu-ambegaonkar | math | 1 result found
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We just added a very basic calculator function to our web app, so you can now use basic mathematical operations when entering a cost (addition, subtraction, multiplication, and division). We hope to add similar features to our mobile apps at some point in the future!
An error occurred while saving the commentShantanu Ambegaonkar supported this idea ·
Hello Team, When some one is entering Numbers in Value section there can be additional parameter like "+" so that in the end if we enter "=" it will add all the numbers and we don't have to use calculator separately.
Ex: In Value Section we can enter:
As soon as "=" is entered everything should be added to give a single value which we can easily sumbit and proceed.
This is a much needed feature. | s3://commoncrawl/crawl-data/CC-MAIN-2023-23/segments/1685224645089.3/warc/CC-MAIN-20230530032334-20230530062334-00523.warc.gz | CC-MAIN-2023-23 | 881 | 8 |
https://web2.0calc.com/questions/still-need-help_2 | math | Hi, I am getting different answers and need further help
Ricky has a dumpling five-shooter with one dumpling in one of the five chambers. He spins it and fires, repeating this two-step process until he gets the dumpling to come out. What is the probability that he gets the dumpling to come out on the 2nd or 4th shot? Answer should be a common fraction.
Is this a repost Jenny?
If so, what is the address of the original post? | s3://commoncrawl/crawl-data/CC-MAIN-2021-31/segments/1627046154053.17/warc/CC-MAIN-20210731043043-20210731073043-00397.warc.gz | CC-MAIN-2021-31 | 427 | 4 |
http://sxpaperbogw.gvu-edu.us/substitution-and-income-effects.html | math | If the price of a good increases, then there will be two different effects – known as the income and substitution effect if a good increases in price. Substitution and income effects at the aggregate level: the effective budget constraint of the government and the flypaper effect cristian f sepulveda. When you're rolling in cash (or broke as a joke), how does your behavior change the income and substitution effect explain reactions to.
We discuss the substitution effect and income effect definitions and personal preferences, and how how to determine which one dominates. Previous papers by quantifying both the income and substitution effects relative contribution of substitution and income effects to the total rebound effect.
Substitution and income effect alternative to utility maximization we have examined how individuals maximize their welfare by maximizing their utility. Income and substitution effects [see chapter 5 and 6] 2 two demand functions • marshallian demand xi(p1,,pn,m) describes how consumption. Labor supply is unresponsive to permanent changes in wage rates thus, income and substitution effects cancel, but are they both close to zero or both large. The primary difference between income effect and substitution effect is that income effect is a result of income being freed up whereas.
Substitution and income effect as the price of a good is raised its supply also increases thus we get a normal upward sloping curve in the same way, a higher. Indifference curve analysis with its technique of looking upon the price effect as a combination of income effect and substitution effect explains relationship. Below are some notes which might be of assistance to those teaching this course income and substitution effects with indifference curves any.
Income y and the two goods have respective prices p1 and p2 to decompose this into substitution and income effects, we first leave. Learn more about the income effect and substitution effect in economics find out how these two principles impact consumer demand. Wage rises - income & substitution effects (labour markets) levels: a level, ib exam boards: aqa, edexcel, ocr, ib, eduqas, wjec print page.
Summary of substitution and income effects – the movement from a to b is composed of two effects: – substitution effect - caused by change in p x /p. The income effects are negative, but significantly different from zero only in the case of wives the theorem that the substitution effect is positive is confirmed by. What are income and substitution effects when the price of q1, p1, changes there are two effects on the consumer first, the price of q1 relative to the. | s3://commoncrawl/crawl-data/CC-MAIN-2018-43/segments/1539583515041.68/warc/CC-MAIN-20181022113301-20181022134801-00108.warc.gz | CC-MAIN-2018-43 | 2,661 | 6 |
https://www.shaalaa.com/question-bank-solutions/describe-necessary-theory-davisson-german-establishing-wave-nature-electrons-de-broglie-wavelength_57395 | math | Describe with the necessary theory the davisson and german establishing wave nature of electrons. Calculate the de-broglie wavelength of an alpha particle accelerating through a potential difference of 200 volts given :- mass of alpha
particle = 6.68×10-27kg.
According to de Broglie’s hypothesis, a beam of material particle must possess wave
like characteristics and should undergo phenomena like reflection , refraction, interference, diffraction and polarization as the ordinary light waves do. The first experimental verification of wave nature of atomic particles was provided by davisson and germer.
In this experiment , from a hot filament F electrons are accelerated by a small voltage V to strike a target made of a single nickel crystal.
• The electrons are scattered off the crystal in all directions.
• Help of an scattered electrons in all directions can be recorded with the help of an electron detector which can be rotated on a circular graduated scale.
• For any accelerating voltage ,V the scattering curve shows a peak or maximum in a particular direction. It is found that for an accelerating voltage of 54 volts a very large number of electrons are scattered at a particular angle , ∅ = 50°.
• It is assumed that the electron undergoes diffraction and the peak represents the first order spectrum at an angle of 50°.
The diffraction effects is explained as follows.
• The atomic planes of the nickel crystal act like the ruling of a diffraction grating.
• The interatomic distances of a nickel crystal is known to be a = 2.15 A°.
• The interatomic spacing of a nickel crystal is d = 0.09 A°.
• Since, it is assumed that the electrons undergo diffraction they must follow braggs law, 2dsinθ = nλ
• It is seen that the glancing angle θ = 65°. Assuming the order of diffraction , n= 1 the electron wavelength is experimentally calculated as
`λ_E = 1.65 A°.`
• On the other hand since the electron energy is
`E = 1/2mv^2 = eV`
• The wavelength associated with an electron wave can be written as
`λ_r = h/(sqrt(2mE)) = h/(sqrt(2meV)) = 12.25/sqrt(V)`
• here the accelerating potential V = 54 volts for which the theoretical electron wavelength is found to be
`λ_T = 1.67 A°.`
• Which is very close to the experimental value , `λ_E` .
• This agreement confirms de Broglie hypothesis of matter waves.
Given data : - `m_p = 6.68 × 10^-27 Kg , q_α = 4e = 6.4 xx 10^-19 c`
V =200 volts.
Formul :- `-1/2 mV^2 = q_α V , λ = h/(mV) `
Solutions :-- `1/2 mV^2 = q_αV , v = √ (2q_αV)/m`
`λ= h/(√2q_αmV) `
`= (6.63 xx 10^-34)/(√ 2 xx6.4 xx 10^-19 xx 6.68 xx 10^-27 xx 200`
Answer : de Broglie wavelength of an alpha particle | s3://commoncrawl/crawl-data/CC-MAIN-2021-17/segments/1618038098638.52/warc/CC-MAIN-20210417011815-20210417041815-00144.warc.gz | CC-MAIN-2021-17 | 2,690 | 31 |
https://questions.llc/questions/1578810/a-0-230-kg-wooden-rod-is-1-55-m-long-and-pivots-at-one-end-it-is-held-horizontally-and | math | A 0.230-kg wooden rod is 1.55 m long and pivots at one end. It is held horizontally and then released.
1) What is the angular acceleration of the rod after it is released? three sf with units
2) What is the linear acceleration of a spot on the rod that is 1.02 m from the axis of rotation?
3) At what location along the rod should a die be placed so that the die just begins to separate from the rod as it falls?
T = moment at pivot = m g (1.55/2)
alpha = T/moment of inertia
moment of inertia about end = (1/3)mL^2 | s3://commoncrawl/crawl-data/CC-MAIN-2022-33/segments/1659882573908.30/warc/CC-MAIN-20220820043108-20220820073108-00529.warc.gz | CC-MAIN-2022-33 | 515 | 7 |
https://math.answers.com/Q/How_do_you_convert_miles_per_hour_to_kilometers_per_hour | math | To convert miles to kilometers, multiply by 1.6. The same if you want to convert miles/hour to kilometers/hour.
Divide km per hour by 1.609
You cannot convert 25 "kilometers" as a length measure in miles per hour as a speed. 25 kilometers per hour are 15.5 miles per hour.
Conversion: mph x 1.6093 = kilometers per hour
Multiply miles per hour (mph) by 1.609 to get kilometers per hour (km/h)
1 Kilometer per Hour = 0.621371192237334 Miles per Hour.So, multiplying it to km/hr we can get mile/hr.
301 kilometers per hour is 187.03 miles per hour.
Multiply the mph by 1.609
"Mile" is a distance, but "kilometers per hour" is a speed. You can't directly convert one to the other. 3 miles = 4.828 kilometers 3 miles per hour = 4.828 kilometers per hour
Multiply miles per hour by 1.60934 to get km per hour.
To convert miles to kilometers, you multiply by approximately 1.609. This means that 2000 miles per hour would translate into approximately 3218 kilometers per hour.
186,000 (miles per second) = 1.07761674 × 109 km per hour.
Multiply miles per second by 5,793 to get kilometers per hour. (mps x 5793 = kph)
One kilometer per hour = 0.621371 miles per hour so: Kph x 0.621371=Mph
Miles per second x 5793.64 = kilometers per hour
68.35 mph. 1 kilometer is equal to .62137 miles. To convert from kilometers to miles, simply multiply the kilometers by .62137
To convert miles per hour to kilometres per hour, multiply by 1.609344. In this instance, 88 miles per hour is equal to 88 x 1.609344 = 141.622272 kilometres per hour.
To convert from miles per hour to kilometres per hour, multiply by 1.609344. Therefore, 71 miles per hour is equal to 71 x 1.609344 = 114.263424 kilometres per hour.
To convert miles per hour to kilometres per hour, multiply by 1.609344. Therefore, 187 miles per hour is equal to 187 x 1.609344 = 300.947328 kilometres per hour.
100.2 Miles per Hour = 161.25626880000001 Kilometers per Hour
Answer: 40 mph = 64.3737 km/h
roughly MPH X 1.609
Miles per hour can be converted to kilometers per minute by dealing with the individual units. Convert first to miles per minute by multiplying by 1/60. Then convert miles to kilometers by multiplying by 1. 609.
Suggestion: Convert miles to kilometers, then it should be easy to compare. One mile is about 1.6 kilometers. | s3://commoncrawl/crawl-data/CC-MAIN-2021-49/segments/1637964359093.97/warc/CC-MAIN-20211201052655-20211201082655-00504.warc.gz | CC-MAIN-2021-49 | 2,291 | 24 |
https://xtronic.org/download/calculator/kmb-electrical-calculator/amp/ | math | Here’s a calculator that every technician, maintenance person, or home hobbyist should have. This Electrical Calculator contains tons of useful calculations used to figure out the everyday used formulas (ohms, amps, volts, etc.), or for those formulas that are hard to find or seldom used.
This is great for homework or on the job. KMB Electrical Calculator includes an easy-to-use 3D resistor color code reader which works with variable inputs and outputs. The Volt, Amp, and Ohm function are free to use. | s3://commoncrawl/crawl-data/CC-MAIN-2024-18/segments/1712296817438.43/warc/CC-MAIN-20240419141145-20240419171145-00208.warc.gz | CC-MAIN-2024-18 | 508 | 2 |
http://opinio.blogdrives.com/comments?id=517 | math | The Senate voted earlier today to conduct an inventory of offshore oil and gas resources. Proponents of the bill claim that they just need to know what is out there for the future$ Those who voted for it are from both sides of the aisle.$$ A proposed amendment$$$ to the bill to get rid of the inventory provision was defeated 52-44. This provision would include areas that have been off limits to drilling for almost a quarter century.$$$$ A succession of Presidents including Good ole G.W. has extended it. Of course there is growing pressure to find out what we can rip from the earth, instead of ways to wean ourselves from the needs. Like I said it had bipartisan support and as I should bipartisan opponents. As for those who are opponents 27 of the 44 Senators who voted against it are from States where the drilling is prohibited. At least they stood up for their people and their earth. While some who were against it were because they saw it leading to drilling that isn’t all there is to it. To be honest I agree that it’s their first step in trying to get drilling$$$$$. There are immediate problems what they plan on doing will more than likely harm the waters and animals that live in them.$$$$$$ The bottom line is I’m upset I didn’t know about this sooner and should’ve paid more attention. That way I could’ve at least made my opinions known to those voting which in the end is sometimes all we can do.
$ “This gives Americans full information of what it is there…This is not a drilling amendment” D-LA Sen. Mary Landrieu.
$$ I really hate how everyone always refers to people from a different party as “the ones on the other side of the aisle”
$$$ The amendment was proposed by Democrat Bill Nelson and Republican Mel Martinez both Senators from
$$$$ Oil and gas drilling has been banned in almost all The country’s coastal areas outside the Gulf of Mexico when a moratorium was issued by Congress in 1981.
$$$$$ Can anyone say
$$$$$$ Processes that include seismic activity.
|jordan 13 |
May 8, 2012 03:39 AM PDT
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|Leave a Comment:| | s3://commoncrawl/crawl-data/CC-MAIN-2018-09/segments/1518891817908.64/warc/CC-MAIN-20180226005603-20180226025603-00452.warc.gz | CC-MAIN-2018-09 | 2,166 | 11 |
https://www.nagwa.com/en/videos/894125360347/ | math | A body slides down a smooth plane under the action of its weight. Which one of the following variables does the acceleration of the body depend on? Is it (A) the reaction of the plane, (B) the weight of the body, (C) the mass of the body, or (D) the angle of inclination of the plane?
Let’s begin by sketching a diagram to model the scenario. If we let the mass of the body be 𝑚 kilograms, then its weight exerts a force vertically downwards equal to mass multiplied by gravity. The weight 𝑊 is equal to 𝑚𝑔. We have a normal reaction force 𝑅 acting perpendicular to the plane. And we will let the angle of inclination to the plane be 𝜃 degrees.
As the body is sliding down the plane under the action of its weight, there are no extra forces we need to consider. And as the plane is smooth, there will be no frictional force. We need to calculate the components of the weight force that are parallel and perpendicular to the plane. Using our knowledge of right angle trigonometry, the force perpendicular to the plane is equal to 𝑚𝑔 cos 𝜃 and the force parallel to the plane is equal to 𝑚𝑔 sin 𝜃.
Newton’s second law states that the sum of the forces is equal to the mass multiplied by acceleration. Resolving perpendicular to the plane, the sum of our forces is equal to 𝑅 minus 𝑚𝑔 multiplied by cos 𝜃. As the body is not accelerating in this direction, this is equal to zero. And the normal reaction force 𝑅 is therefore equal to 𝑚𝑔 multiplied by cos 𝜃. We can therefore conclude that the reaction of the plane does not impact the acceleration of the body.
Let’s now consider what happens when we resolve parallel to the plane. The only force acting on the body in this direction is 𝑚𝑔 multiplied by sin 𝜃. This is equal to the mass 𝑚 multiplied by the acceleration 𝑎. We can divide both sides of this equation by the mass 𝑚. This means that the acceleration 𝑎 is equal to 𝑔 sin 𝜃. And we can therefore conclude that neither the mass nor the weight of the body impacts the acceleration. The only variable that will affect the acceleration of the body is the angle of inclination 𝜃.
We can therefore conclude that the correct answer is option (D). The acceleration of the body depends on the angle of inclination of the plane. We can actually go one stage further. As 𝜃 lies between zero and 90 degrees, we know that as the angle 𝜃 increases, the acceleration increases. This is because the function sin 𝜃 is increasing between zero and 90 degrees. | s3://commoncrawl/crawl-data/CC-MAIN-2021-25/segments/1623488517048.78/warc/CC-MAIN-20210622093910-20210622123910-00175.warc.gz | CC-MAIN-2021-25 | 2,553 | 6 |
http://tir.no/pdf/algebra | math | By Laurie Boswell, Timothy D. Kanold, Lee Stiff, Holt Mcdougal
Read Online or Download Algebra PDF
Best algebra & trigonometry books
I wished a short refresher simply because i'm activity searching and this occasionally comes up on interviews because of my profession. I havent needed to use this kind of math for particularly some time although. I dont disagree even if with a few reviewers who've complained that the fabric isn't written for newcomers. I needed to fight with a lot of the ebook and needed to pass over yes chapters greater than as soon as.
The ultimate a part of a three-volume set delivering a contemporary account of the illustration idea of finite dimensional associative algebras over an algebraically closed box. the topic is gifted from the point of view of linear representations of quivers and homological algebra. This quantity offers an advent to the illustration conception of representation-infinite tilted algebras from the viewpoint of the time-wild dichotomy.
Dieses Buch erleichtert Ihnen den Einstieg in das eigenständige Lösen von Aufgaben zur Algebra, indem es Ihnen nicht einfach nur Aufgaben mit Lösungen, sondern vor allem auch Hinweise zur Lösungsfindung und ausführliche Motivationen bietet. Damit ist das Werk excellent geeignet zur Prüfungsvorbereitung, wenn Sie ein tieferes Verständnis der Algebra entwickeln wollen oder wenn Sie sich gerne an kniffligen Aufgaben einer faszinierenden mathematischen Disziplin versuchen.
- A Course in Constructive Algebra
- Finite Fields for Computer Scientists and Engineers (The Springer International Series in Engineering and Computer Science)
- Gradings on simple Lie algebras
- Proceedings, Vol. 4
- Introduction to the theory of categories and functors
Extra resources for Algebra
3 Order of Operations 21 MIXED REVIEW STUDENT HELP Skills Review For help with fractions, see pp. 781–783. EVALUATING EXPRESSIONS Evaluate the expression for the given value of the variable. 1) 24 58. 8a when a = 4 59. ᎏᎏ when x = 3 60. 5 x 4 1 61. ᎏᎏ • x when x = ᎏᎏ 3 6 5 3 63. ᎏᎏ º p when p = ᎏᎏ 16 8 62. 5 EVALUATING EXPONENTIAL EXPRESSIONS Evaluate the expression for the given value of the variable. 2) 64. (6w)2 when w = 5 65. 4(t 3) when t = 3 66. 9b2 when b = 8 67. 5x 2 when x = 16 68. (7x)3 when x = 2 69.
What number can 5 be subtracted from to get 1? B. What number can be subtracted from 5 to get 1? C. What number can 1 be subtracted from to get 5? ELECTIONS The number of votes received by the new student council president is represented by x. Match the sentence with the equation or inequality that represents it. A. x = 125 B. x < 125 C. x ≥ 125 D. x ≤ 125 10. She received no more than 125 votes. 11. She received at least 125 votes. 12. She received exactly 125 votes. 13. She received less than 125 votes.
The quotient of x and 16 is greater than or equal to 32. D. 16 + x ≤ 32 60. The product of 16 and x is less than 32. E. 16x > 32 61. The fourth power of x is 16. F. x º 16 = 32 62. The sum of 16 and x is less than or equal to 32. G. 16x = 32 63. The quotient of x and 16 is greater than 32. x H. ᎏᎏ ≥ 32 16 64. The product of 16 and x is greater than 32. I. 16x < 32 65. COMPUTER CENTER Your school is building a new computer center. Four hundred square feet of the center will be available for computer stations.
Algebra by Laurie Boswell, Timothy D. Kanold, Lee Stiff, Holt Mcdougal | s3://commoncrawl/crawl-data/CC-MAIN-2018-47/segments/1542039750800.95/warc/CC-MAIN-20181121193727-20181121215727-00415.warc.gz | CC-MAIN-2018-47 | 3,426 | 16 |
https://socialcar-project.eu/en/a-man-who-is-walking-has-a-momentum-of-80-kilogram-meters-per-second-west-the-man-has-a-mass-of-80.10803633.html | math | A man who is walking has a momentum of 80 kilogram meters per second west. The man has a mass of 80 kilograms. Which is the velocity of the man?
So, momentum is the product of mass times velocity. Some times, one just says mass times speed, but not in this problem. They ask for velocity, a vector. vector momentum = mass * vector velocity, So the velocity is 80/80 = 1 m/s west. | s3://commoncrawl/crawl-data/CC-MAIN-2022-40/segments/1664030334912.28/warc/CC-MAIN-20220926144455-20220926174455-00501.warc.gz | CC-MAIN-2022-40 | 379 | 2 |
https://answers.yahoo.com/question/index?qid=20091204153325AAtMjFC | math | math homework help: algebra 1?
the united states postal service receives 38 million changes of address per year. find the rate per day. round to the nearest thousand.
- badbedbugzLv 51 decade agoFavorite Answer
38,000,000 ÷ 365 = 104109.589
Rounded that would be 104,000 per day.
- Anonymous4 years ago
For all those problems you opt to elect and label a variable. In issue one they write appropriate to the dimensions in terms of the width. enable x = the width in view that we are informed the dimensions is one unit greater beneficial than the width we then have: x + a million = the dimensions. with the aid of fact the element of a rectangle is given by length circumstances width (or equivalently width circumstances length), we get the equation: (x)(x + a million) = 30 by the distributive assets we get x^2 + x = 30 placing one component to 0 x^2 + x - 30 = 0 element (x +6)(x-5) = 0 consequently x + 6 = 0 or x - 5 = 0 x = -6 or x = 5. in view that we are speaking a pair of distance we are in a position to brush aside the destructive answer. So the width (which we categorised as x) is 5 gadgets, and the dimensions (which we categorised as x + a million) is 6 gadgets. For issue 2, in view that we are speaking approximately consecutive unusual integers, (ex 3, 5, 7, 9, 11), all of us understand they might desire to be separated by 2 gadgets each. enable x = the 1st consecutive unusual integer Then x + 2 is the 2d consecutive unusual integer. Product implies multiplication, so (x)(x + 2) = 195 x^2 + 2x = 195 x^2 + 2x - 195 = 0 (x + 15)(x - 13) = 0 x = - 15 or x = 13 the 1st pair of ideas is -15 and -15 + 2 = -13 the 2d pair of ideas is 13 and 13 + 2 = 15 | s3://commoncrawl/crawl-data/CC-MAIN-2020-50/segments/1606141197278.54/warc/CC-MAIN-20201129063812-20201129093812-00617.warc.gz | CC-MAIN-2020-50 | 1,675 | 7 |
https://bitcoincasinoreview.info/vetri-vld-historical-data-current-vld-price-charts-live-history/ | math | Dynamic and history value of price VLD. Maximal value of price vetri was 0.003999$ - 2020-10-22 18:00:12, Minimal price of VLD was 0.001$ value and fixed at 2020-12-14 23:00:08. Today price of vetri is : 0$
We will update it as soon as possible. If you want to help, you can contact us. | s3://commoncrawl/crawl-data/CC-MAIN-2021-39/segments/1631780058222.43/warc/CC-MAIN-20210926235727-20210927025727-00361.warc.gz | CC-MAIN-2021-39 | 286 | 2 |
https://studysoup.com/tsg/11587/calculus-early-transcendentals-1-edition-chapter-4-4-problem-24e | math | rectangles beneath a line a. A rectangle is constructed with one side on the po ? sitive? -axis one side on the positive ? y-axis, and the vertex opposite the origin on the line ? y? =10 ? 2?x. What dimensions maximize the area of the rectangle? What is the maximum area? b. Is it possible to construct a rectangle with a greater area than that found in part (a) by placing one side of the rectangl?e on the li?ne ?y =10 ? 2x ? , and the vertices not on that line on? the p? ositive? and y? -axes? Find the dimensions of the rectangle of maximum area that can be constructed in this way.
Solution 24E \Step 1: (a)Let us consider the side on the x-axis extends to the point (x,0) and the side on the y-axis to (0,x).Line equation which has vertex on it is given by y=10-2x Consider the length of the rectangle be x and the width of rectangle be y then area of rectangle,A=xy The objective function is area of rectangle A=xy Step 2: We convert A in terms of single variable x A=x(10 2x) =10x 2x 2 ;0 x 5 Which is the function in single variable x With A(0)=10(0)-2(0)=0 2 And A(5)=10(5)-2(5) =50-50 =0 Step 3: Now in order to maximize A we need to find critical point by evaluating A’=0 A’=0 dA = 0 dx d (10x 2x ) = 0 dx (10 4x) = 0 x = 14 = 2 Hence x= 5 gives maximum area 2 | s3://commoncrawl/crawl-data/CC-MAIN-2020-50/segments/1606141195069.35/warc/CC-MAIN-20201128040731-20201128070731-00249.warc.gz | CC-MAIN-2020-50 | 1,277 | 2 |
https://calculator.academy/crawl-ratio-calculator/ | math | Enter the transmission ratio, transfer case ratio, and the axle gear ratio to calculate the crawl ratio.
- Gear Reduction Calculator
- Final Drive Ratio Calculator
- Torque to Force Calculator
- Rollout Calculator
Crawl Ratio Formula
The following formula is used to calculate a crawl ratio.
CR = TR* TCR * AGR
- Where CR is the crawl ratio
- TR is the transmission ratio
- TCR is the transfer case ratio
- AGR is the axle gear ratio.
To calculate the crawl ratio, multiply the transmission ratio, transfer case ratio, and axle gear ratio together.
Crawl Ratio Definition
A crawl ratio is a measure of the number of rotations an engine makes in order to turn a tire one full rotation.
Crawl Ratio Example
How to calculate a crawl ratio?
- First, determine the transmission ratio.
Measure the transmission ratio.
- Next, determine the TCR.
Calculate the transfer case ratio.
- Next, determine the AGR.
Calculate the axle gear ratio.
- Finally, calculate the crawl ratio.
Calculate the crawl ratio using the equation above.
Normal crawl ratios on cars range from 20:1 to 30:1 | s3://commoncrawl/crawl-data/CC-MAIN-2023-06/segments/1674764500041.18/warc/CC-MAIN-20230202200542-20230202230542-00582.warc.gz | CC-MAIN-2023-06 | 1,073 | 26 |
https://waesearch.kobv.de/uid.do?query=ntrs_oai_oai%3Acasi.ntrs.nasa.gov%3A20190001518&index=internal&plv=2 | math | We present results of recent Neutron Star Interior Composition Explorer (NICER) observations of the accreting millisecond X-ray pulsar (AMXP) IGR J17062-6143 that show that it resides in a circular, ultracompact binary with a 38-minute orbital period. NICER observed the source for 26 kiloseconds over a 5.3-day span in 2017 August, and again for 14 and 11 kiloseconds in 2017 October and November, respectively. A power spectral analysis of the August exposure confirms the previous detection of pulsations at 163.656 Hertz in Rossi X-ray Timing Explorer (RXTE) data, and reveals phase modulation due to orbital motion of the neutron star. A coherent search for the orbital solution using the Z squared method finds a best-fitting circular orbit with a period of 2278.21 seconds (37.97 minutes), a projected semimajor axis of 0.00390 lt-s (Localization Test Statistic), and a barycentric pulsar frequency of 163.6561105 Hertz. This is currently the shortest known orbital period for an AMXP. The mass function is 9.12 times 10 (sup minus 8) solar mass, presently the smallest known for a stellar binary. The minimum donor mass ranges from approximately 0.005 to 0.007 times the solar mass for a neutron star mass from 1.2 to 2 times the solar mass. Assuming mass transfer is driven by gravitational radiation, we find donor mass and binary inclination bounds of 0.0175-0.0155 times the solar mass and 19 degrees less than i less than 27.5 degrees, where the lower and upper bounds correspond to 1.4 and 2 times the solar mass neutron stars, respectively. Folding the data accounting for the orbital modulation reveals a sinusoidal profile with fractional amplitude 2.04 plus or minus 0.11 percent (0.3-3.2 kiloelectronvolts).
Astrophysical Journal (ISSN 2041-8205) (e-ISSN 2041-8213); 858; 2; L13 | s3://commoncrawl/crawl-data/CC-MAIN-2020-10/segments/1581875146066.89/warc/CC-MAIN-20200225110721-20200225140721-00003.warc.gz | CC-MAIN-2020-10 | 1,797 | 2 |
http://mathhelpforum.com/differential-geometry/133223-cauchy-sequence.html | math | Hey guys, I'm having trouble wrapping my head around Cauchy Sequences.
So, I know that the definition of such a sequence is if then . This means that the sequence is getting epsilon close to each other far down the number line.
How do we know what to choose for and if we say when trying to prove that the sequence is Cauchy?
Also, the proof "if a sequence converges, then it is Cauchy," (bottom of first page here: http://legacy.lclark.edu/~istavrov/a...t30-cauchy.pdf)
why is it true that ? Why is it less than epsilon over two and not just epsilon. I assume it has something to do with the triangle inequality?
If theres any trick to understanding this stuff please share! | s3://commoncrawl/crawl-data/CC-MAIN-2017-17/segments/1492917122996.52/warc/CC-MAIN-20170423031202-00452-ip-10-145-167-34.ec2.internal.warc.gz | CC-MAIN-2017-17 | 675 | 6 |
https://hurmaninvesteraravxey.web.app/29242/40855.html | math | earlier date from the later date
- Convert the number of days between two dates to weeks, months, or years, as desired
Two's complement is the way every I am trying to read a i2c temperature sensor and the output is in twos complement that needs to be converted. Convert the binary number 11001100 from 8-bit 2's complement notation to decimal. Remember to specify the sign of the decimal number. This tool allows you to convert a Decimal, Binary or Hexidecimal number to and from a "Two's Complement Representation". ** Note: This means that when This application is all in one package, that supports all types of conversion, calculation as well as ASCII translation. It supports all four number systems: Binary, English: Convert 8-bit binary numbers C and D (two's complement) to decimal and hexadecimal number representation. (1 p).
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100000 -32 31 32 O 1-31 Question 3 (3 Points) Convert The Following Decimal Numbers To 6-bit Two's Complement Binary Numbers And Add Them. Indicate Whether Or Not The Sum Overflows Understanding Two’s Complement • An easier way to find the decimal value of a two’s complement number: ~x + 1 = -x • We can rewrite this as x = ~(-x -1), i.e. subtract 1 from the given number, and flip the bits to get the positive portion of the number. • Example: 0b11010110 • Subtract 1: 0b11010110-1 … Decimal/Two’s Complement Converter. An arbitrary-precision, decimal to two’s complement and two’s complement to decimal converter.
We use 2's complement to calculate the binary of negative integers.
What is the general procedure to convert a $32$-bit $2$'s complement number to decimal? For instance, if I was given the $2$'s complement representation
To do this, you first check if the number is negative or positive by looking at the sign bit. If it is positive, simply convert it to decimal.
Holders may convert their Convertible Senior Notes on or after December 1, 2017, business through acquisitions allows Infinera to complement its technological The numbers of Infinera Shares are rounded to two decimal numbers in the
Minute trades what is converted into a put trading. security strategies and touch best computers for directional and tactics torrent point decimal aug. complement : fyllnad complementary : komplementerande complete : full, komplettera, convert : omvända, konvertera converted : konverterad converter decilitre : deciliter decimal : decimal decimal−count : decimalräkning year : anno in two : itu in vain : förgäves inability : oförmåga inaccessibility up into smaller pieces, so you may see a decimal with a lot of zeros after it. If your credit card has to convert your winnings from a single currency to one more, there From the No Limit texas hold em match, gamers can receive one card or two His moans grew to complement mine, and I knew the sensation of my wet These has cialis gone generic art; conversion cialis 20 mg from: spots offered "Furlong" comes from two 14Th-Century English phrases, "fuhr" (furrow) and These are examples of converting an eight-bit two's complement number to decimal. To do this, you first check if the number is negative or positive by looking at the sign bit.
Reuploads of this mod on Steam Workshop / Armaholic / PlayWithSix are not
Minimum Distance Parsing is a third combining the two techniques, by first 3 and to analyze differences in their be- complements of NPs but are less likely to oc- havior. Lemmas of compound con- stituents Turning again to the example attachments) were ignored in the experiments. digit of the messages' decimal ids. Leave two's complement of double-precision number.
become due out of the proceeds yielded by converting the amount so three decimal places, with 0.0005 being rounded upwards), at which the data/decimals.ui.h:7 572 msgid "Maximal number of decimals to display (and round to)" 573 msgstr data/main.ui.h:57 1067 msgid "Convert to Base Units" 1068 msgstr data/main.ui.h:273 1921 msgid "Two's complement input" 1922 msgstr Negative numbers are entered as two's complement. Antal siffror är det antal siffror som Add-in Functions, List of Analysis Functions Part Two · Text Functions. mil-A-8625 two layer coating tjocklek c:a 0,5mm. 12.00.
The number is positive, so simply convert it to decimal: 01101001 2 = 69 16 = 6×16 + 9 = 105 10 . Interpret 11110010 as a two's complement binary number, and give its decimal equivalent.
Then, to get the non-negative decimal value of the object, I convert the two complement back to its original value : 0001 1100. which gives me the result is 28. But the correct answer is 156, this is the value I will get if I did not replace the MSB (1) with (0) when converting the two complement back to the original value . 1001 1100
It is a system in which the negative numbers are represented by the two’s complement of the absolute value. For example : -9 converts to 11110111 (to 8 bits), which is -9 in two’s complement. Two's complement calculator is very helpful. If you are an experienced professional or any student who need to perform calculations and find out 2's complement very often, then you need to use this highly advanced Two's complement calculator to find out the best and the most accurate results.
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av T Maunula · 2018 · Citerat av 9 — and students jointly created two distinct positions for students to act in. Students in formula = 1,8 + 32 is used to convert values for temperature in Celsius to the complement to learning theories which focus on the interaction itself. extracted in Excerpt 7.2 in which the teacher distinguishes between a decimal. av D Brehmer · 2018 · Citerat av 1 — mathematics education to interpret how the two curricula incorporated the targeted terms and how While Kate is still reading the word problem, Beth suggests a conversion from the We complement our answers to the first and third research questions by In particular, a mathematical object like a decimal fraction can be. Decimals in numeric fields are indicated with a decimal point ('. | s3://commoncrawl/crawl-data/CC-MAIN-2022-33/segments/1659882570913.16/warc/CC-MAIN-20220809064307-20220809094307-00378.warc.gz | CC-MAIN-2022-33 | 6,427 | 33 |
https://www.geogebra.org/m/xBg4a4YQ | math | Ellipse (Graph & Equation Anatomy)
- Tim Brzezinski
Move the various sliders in this applet around to investigate what happens to the graph of an ellipse as you change various parameters within the standard form of its equation. Key questions: Is it ever possible for the graph of an ellipse to become a circle? If so, under what condition(s) will this happen? Is it possible to tell the location of an ellipse's center just by looking at its equation? If so, how? How can the length of an ellipse's semimajor & semiminor axes be determined just by looking at its equation? What must happen to ensure that the graph's major axis is horizontal? Vertical? What must happen to ensure that the graph's minor axis is horizontal? Vertical?
Questions are located above the applet. | s3://commoncrawl/crawl-data/CC-MAIN-2023-23/segments/1685224656737.96/warc/CC-MAIN-20230609132648-20230609162648-00436.warc.gz | CC-MAIN-2023-23 | 773 | 4 |
https://risingconnection.com.au/product/power-shield-commander-rt-3000-pscrt3000/ | math | • Pure sine wave output
• Rack/Tower design
• Built-in boost and buck AVR
• Output power factor 0.8
• Programmable power management outlets
• ECO mode operation for energy saving (ECO)
• Emergency Power Off Function (EPO)
• Hot-swappable battery design
• Long-run models available
• Multiple communication available
Commander RT 3000
With pure sine wave output, the Commander Rackmount Tower guarantees compatibility for all kinds of loads. It’s perfect power protection for versatile applications such as networking, telecom and other mission-critical applications.
The ECO mode function allows cost-effective operation of UPS Systems as high as 98%. In this operation mode, load is supplied by the mains. In the event of a mains failure, the inverter takes over the load and provides supply continuity to the connected systems.
To provide longer backup time the 2kVA and 3kVA models are expandable to include an additional battery bank.
• Pure sine wave output
• Model : PSCRT3000
• Capacity : 3000VA/2400W
• Topology : Line Interactive, Pure Sine Wave
• Voltage : 240Vac (Nominal)
• Voltage Range : 162 – 290Vac
• Frequency : 50/60Hz ±5Hz (Auto sensing)
• Output Voltage (AC Mode) : 240Vac (Selectable 208/220/230Vac) ±10% AVR
• Voltage Regulation (Batt. Mode) : ±3%
• Frequency Range (Batt. Mode) : 50Hz or 60Hz ±1Hz
• Current Crest (Typical) : 3:1 Ratio
• Transfer time : 6ms
• Wave Form (Batt. Mode) : Pure sine Wave
• ECO Mode : 98% (Advanced)
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• Two year warranty with opportunity to increase warranty period. | s3://commoncrawl/crawl-data/CC-MAIN-2021-10/segments/1614178361808.18/warc/CC-MAIN-20210228235852-20210301025852-00434.warc.gz | CC-MAIN-2021-10 | 2,931 | 53 |
http://www.ck12.org/trigonometry/Equivalent-Polar-Curves/lesson/Equivalent-Polar-Curves-TRIG/ | math | Equivalent Polar Curves
The expression “same only different” comes into play in this section. We will graph two distinct polar equations that will produce two equivalent graphs. Use your graphing calculator and create these curves as the equations are presented.
Comparing Graphs of Polar Equations
Plot the following polar equations and compare the graphs.
Both equations, one in rectangular form and one in polar form, are circles with a radius of 4 and center at the origin.
Earlier, you were asked if there is a way you can determine if the two equations are equivalent.
As you learned in this section, we can compare graphs of equations to see if the equations are the same or not.
As you can see from the plots, your friend is correct. Your graph and his are the same, therefore the equations are equivalent.
For each equation in rectangular form given below, write the equivalent equation in polar form.
x2+y2=4 x2+y2=6y (x−1)2+y2=1 (x−4)2+(y−1)2=17 x2+y2=9
For each equation below in polar form, write another equation in polar form that will produce the same graph.
r=4+3sinθ r=2−sinθ r=2+2cosθ r=3−cosθ r=2+sinθ
Determine whether each of the following sets of equations produce equivalent graphs without graphing.
r=3−sinθand r=3+sinθ r=1+2sinθand r=−1+2sinθ r=3sinθand r=3sin(−θ) r=2cosθand r=2cos(−θ) r=1+3cosθand r=1−3cosθ
To see the Review answers, open this PDF file and look for section 6.8. | s3://commoncrawl/crawl-data/CC-MAIN-2017-13/segments/1490218188717.24/warc/CC-MAIN-20170322212948-00537-ip-10-233-31-227.ec2.internal.warc.gz | CC-MAIN-2017-13 | 1,446 | 15 |
https://easyhsc.com.au/easyphys/advanced-mechanics-2/circular-motion/analyse-the-forces-acting-on-an-object-executing-uniform-circular-motion-in-a-variety-of-situations/ | math | Analyse the forces acting on an object executing uniform circular motion in a variety of situations
– cars moving around horizontal circular bends
The only force acting on this car in the horizontal is the force of friction
Hence the frictional force towards the center of the circular path should be equal to , where m is the mass of the car , v is the velocity of the car and r is the radius of the circular path.
-a mass on a string
The circular motion is in a vertical plane.
At every point in the uniform circular motion , the centripetal force acting on the mass must be equal to
The tension in the string at :
- point A is T1
- point B is T2
- point C is T3
At the top point A, the net force is T1+mg. Which implies
At point be B, the downward force is mg, and the inward force towards the center is T2. Hence
At point C, the net force acting is T3 – mg. Hence
-objects on banked tracks
A free body diagram of the car would be as follows:
without friction, the only inward force here is Nx, a component of the Normal force on the car from the road.
Now we know
[since there is no motion in the y axis]
to achieve speed v, without friction, the roads need to be banked at an angle
Extract from Physics Stage 6 Syllabus © 2017 NSW Education Standards Authority (NESA) | s3://commoncrawl/crawl-data/CC-MAIN-2024-10/segments/1707947473690.28/warc/CC-MAIN-20240222030017-20240222060017-00270.warc.gz | CC-MAIN-2024-10 | 1,277 | 21 |
http://waset.org/author/mohammad-r-jalali | math | The earliest theories of sloshing waves and solitary waves based on potential theory idealisations and irrotational flow have been extended to be applicable to more realistic domains. To this end, the computational fluid dynamics (CFD) methods are widely used. Three-dimensional CFD methods such as Navier-Stokes solvers with volume of fluid treatment of the free surface and Navier-Stokes solvers with mappings of the free surface inherently impose high computational expense; therefore, considerable effort has gone into developing depth-averaged approaches. Examples of such approaches include Green–Naghdi (GN) equations. In Cartesian system, GN velocity profile depends on horizontal directions, x-direction and y-direction. The effect of vertical direction (z-direction) is also taken into consideration by applying weighting function in approximation. GN theory considers the effect of vertical acceleration and the consequent non-hydrostatic pressure. Moreover, in GN theory, the flow is rotational. The present study illustrates the application of GN equations to propagation of sloshing waves and solitary waves. For this purpose, GN equations solver is verified for the benchmark tests of Gaussian hump sloshing and solitary wave propagation in shallow basins. Analysis of the free surface sloshing of even harmonic components of an initial Gaussian hump demonstrates that the GN model gives predictions in satisfactory agreement with the linear analytical solutions. Discrepancies between the GN predictions and the linear analytical solutions arise from the effect of wave nonlinearities arising from the wave amplitude itself and wave-wave interactions. Numerically predicted solitary wave propagation indicates that the GN model produces simulations in good agreement with the analytical solution of the linearised wave theory. Comparison between the GN model numerical prediction and the result from perturbation analysis confirms that nonlinear interaction between solitary wave and a solid wall is satisfactorilly modelled. Moreover, solitary wave propagation at an angle to the x-axis and the interaction of solitary waves with each other are conducted to validate the developed model. | s3://commoncrawl/crawl-data/CC-MAIN-2019-26/segments/1560627999946.25/warc/CC-MAIN-20190625192953-20190625214953-00017.warc.gz | CC-MAIN-2019-26 | 2,206 | 1 |
http://forums.wolfram.com/mathgroup/archive/2004/Nov/msg00642.html | math | - To: mathgroup at smc.vnet.net
- Subject: [mg52416] Projections
- From: pmarrone at poboxes.com (PMarrone)
- Date: Fri, 26 Nov 2004 01:05:02 -0500 (EST)
- Sender: owner-wri-mathgroup at wolfram.com
I am a Calculus Professor. I want to know how I can use Mathematica to produce projections in the xy, xz and yz axis of level surfaces. For example, compute the volume of a region R bounded by the parabolic cylinder x = y^2 and the planes z = 0 and x + z = 1. In the process we need to compute the projection of the level surface in the xy, xz and yz axis. | s3://commoncrawl/crawl-data/CC-MAIN-2020-24/segments/1590347389355.2/warc/CC-MAIN-20200525192537-20200525222537-00431.warc.gz | CC-MAIN-2020-24 | 555 | 6 |
https://mathoverflow.net/questions/293468/internal-mor-of-schemes | math | Let $S$ be a Noetherian scheme and $X,Y$ be $S$-schemes of finite type. Consider the functor $X^Y$ given by $T \mapsto Mor_S(Y \times_S T,X)$. When is this functor representable by an $S$-scheme of finite type?
Is it true when $Y \rightarrow S$ is finite and flat?
In http://www.math.harvard.edu/~gaitsgde/grad_2009/SeminarNotes/Sept17(Bun(G)).pdf (Thm 1.6) it is shown that $X^Y$ is representable if $X \rightarrow S$ is quasi-projective and $Y \rightarrow S$ is projective. Dennis Gaitsgory explained to us that this implies that $X^Y$ is representable by a locally finite type scheme. | s3://commoncrawl/crawl-data/CC-MAIN-2019-22/segments/1558232256724.28/warc/CC-MAIN-20190522022933-20190522044933-00008.warc.gz | CC-MAIN-2019-22 | 587 | 3 |
https://chalkdustmagazine.com/gerda-2/ | math | More from Chalkdust
- Sophie Maclean and David Sheard speak to a very top(olog)ical mathematician!
- David Sheard sets the third puzzle. Can you solve it?
- David Sheard explores the rich mathematics and history behind the Apollonian packing, and the cover of issue 11
- Write down a quadratic. What is the probability that it factorises? Paging Prof. Dirichet...
- Find your perfect partner with this wonderful tree diagram! | s3://commoncrawl/crawl-data/CC-MAIN-2021-49/segments/1637964358786.67/warc/CC-MAIN-20211129164711-20211129194711-00452.warc.gz | CC-MAIN-2021-49 | 425 | 6 |
https://www.impan.pl/en/publishing-house/journals-and-series/studia-mathematica/all/179/2/89885/some-remarks-on-gleason-measures | math | Some remarks on Gleason measures
Volume 179 / 2007
Studia Mathematica 179 (2007), 99-115 MSC: 47B15, 28C05. DOI: 10.4064/sm179-2-1
This work is devoted to generalizing the Lebesgue decomposition and the Radon–Nikodym theorem to Gleason measures. For that purpose we introduce a notion of integral for operators with respect to a Gleason measure. Finally, we give an example showing that the Gleason theorem does not hold in non-separable Hilbert spaces. | s3://commoncrawl/crawl-data/CC-MAIN-2023-23/segments/1685224646350.59/warc/CC-MAIN-20230610200654-20230610230654-00563.warc.gz | CC-MAIN-2023-23 | 455 | 4 |
https://answer-ya.com/questions/3801411-1-a-current-carrying-conductor-of-length-08-m-is-placed.html | math | 1.) a current-carrying conductor of length 0.8 m is placed perpendicular to the direction of the magnetic field of 0.6 tesla. wh
at is the value of the current in the conductor if the conductor experiences a force of 1.2 n? 2.5 a 1.6 a 1.2 a 0.4 a 2.) an electron moves to the east and enters the magnetic field. the direction of the magnetic field is perpendicular to the direction of velocity acting downward. what is the direction of the force the electron experiences? east west north south
1. The current can be calculated using the equation :
Force = current × length of wire × magnetic field strength
Plug in all the values
1.20 = current × 0.80 × 0.60
1.20 = current × 0.48
Isolate for current
current = 2.5 Amps
2. electron moves east magnetic field is downwards
the velocity, field and force all all perpendicular to each other. You can use the straight fingered left hand rule to determine the direction of the force.
Point your index finger to the right side (east), point your middle finger down towards the ground while you keep your index finger in place. You're left with your thumb pointing towards you, which is the south direction. | s3://commoncrawl/crawl-data/CC-MAIN-2022-27/segments/1656104683708.93/warc/CC-MAIN-20220707063442-20220707093442-00211.warc.gz | CC-MAIN-2022-27 | 1,155 | 12 |
https://kazmi.info/ldu-factorization-42/ | math | Is it possible to switch row 1 and row 2? I am using a shortcut method I found on a YouTube channel, but I am not sure how to do it if I swap the. Defines LDU factorization. Illustrates the technique using Tinney’s method of LDU decomposition. An LDU factorization of a square matrix A is a factorization A = LDU, where L is a unit lower triangular matrix, D is a diagonal matrix, and U is a unit upper.
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Factorizatio can be removed by simply reordering the rows of A so that the first element of the permuted matrix is nonzero. It can be described as follows. This page was last edited on 25 Novemberat This decomposition is called the Cholesky decomposition. Ideally, the cost of computation is determined by the number of nonzero entries, rather than by the size of the matrix.
If A is a symmetric or Hermitianif A is complex positive definite matrix, we can arrange matters so that U is the conjugate transpose of L. Upper triangular should be interpreted as having only zero entries below the main diagonal, which starts at the upper left corner.
If this assumption fails at some point, one needs to interchange n -th row with another row below it before continuing. The product sometimes includes a permutation matrix as well.
I am using a shortcut method I found on a YouTube channel, but I am not sure how to do it if I swap the rows. In that case, L and D are square matrices both of which have the same number of rows as Aand U has exactly the same dimensions as A.
Retrieved from ” https: The above procedure can be repeatedly applied to solve the equation multiple times for different b. These algorithms use the freedom to exchange rows and columns to minimize fill-in entries that change from an initial zero to a non-zero value during the execution of an algorithm. Note that in both cases we are dealing with triangular matrices L and Uwhich can be solved directly by forward and backward substitution without using the Gaussian elimination process however we do need this process or equivalent to compute the LU decomposition itself.
Because the inverse of a lower triangular matrix L n is again a lower triangular matrix, and the multiplication of two lower triangular matrices is again factorjzation lower triangular matrix, it follows that L is a lower triangular matrix. It results in a unit lower triangular matrix and an upper triangular matrix. Computation of the determinants is computationally expensiveso this explicit formula is not used in practice.
Find LDU Factorization
In numerical analysis and linear algebralower—upper LU decomposition or factorization factors a matrix as the product of a lower triangular matrix and an factorkzation triangular matrix.
It would follow that the result X must be the inverse of A. In this case it is faster and more convenient to do an LU decomposition of the matrix A once and then solve the triangular matrices for the different brather than using Factogization elimination each time.
The Cholesky decomposition always exists and is unique — provided the matrix is positive definite. Astronomy and Astrophysics Supplement. This system of lsu is underdetermined. It turns out that all square matrices can be factorized in this form, and the factorization is numerically stable in practice. Above we required that A be a square matrix, but these decompositions can all be generalized to rectangular matrices as well.
Email Required, but never shown. I am having some troubles finding the LDU decomposition of this matrix. Matrix decompositions Numerical linear algebra.
The conditions are expressed in terms of the ranks of certain submatrices. LU decomposition can be viewed as the matrix form of Gaussian elimination.
Sign up using Facebook. This is impossible if A is nonsingular invertible. | s3://commoncrawl/crawl-data/CC-MAIN-2021-31/segments/1627046150264.90/warc/CC-MAIN-20210724094631-20210724124631-00406.warc.gz | CC-MAIN-2021-31 | 3,906 | 18 |
https://www.studysmarter.us/textbooks/physics/physics-for-scientists-and-engineers-a-strategic-approach-with-modern-physics-4th/the-electric-field/q-38-/ | math | Your physics assignment is to figure out a way to use electricity to launch a small -long plastic drink stirrer. You decide that you’ll charge the little plastic rod by rubbing it with fur, then hold it near a long, charged wire, as shown in FIGURE P23.56. When you let go, the electric force of the wire on the plastic rod will shoot it away. Suppose you can uniformly charge the plastic stirrer to and that the linear charge density of the long wire is . What is the net electric force on the plastic stirrer if the end closest to the wire is away?
Hint: The stirrer cannot be modeled as a point charge; an integration is required.
The ozone molecule has a permanent dipole moment of 1. Although the molecule is very slightly bent— which is why it has a dipole moment—it can be modeled as a uniform rod of length with the dipole moment perpendicular to the axis of the rod. Suppose an ozone molecule is in a uniform electric field. In equilibrium, the dipole moment is aligned with the electric field. But if the molecule is rotated by a small angle and released, it will oscillate back and forth in simple harmonic motion. What is the frequency of oscillation?
94% of StudySmarter users get better grades.Sign up for free | s3://commoncrawl/crawl-data/CC-MAIN-2022-49/segments/1669446711150.61/warc/CC-MAIN-20221207053157-20221207083157-00082.warc.gz | CC-MAIN-2022-49 | 1,230 | 4 |
http://camera-wiki.org/wiki/Circle_of_confusion | math | Circle of confusion
In the ideal case, a lens intercepts light from a single point on the subject, and focuses it to a perfect pinpoint in the image plane. However if the lens is instead slightly misfocused, this light spreads out into a small blur disk, which by convention is given the rather flowery name circle of confusion (sometimes abbreviated CoC). The largest circle of confusion which is not noticeable, and which thus still appears sharp, is a key factor in calculating of depth of field.
Images which are viewed very critically (i.e. which occupy a very wide portion of the viewer's field of vision) have a more stringent limit on their acceptable circle of confusion diameter. Another factor to consider is the dimensions of the original film (or digital sensor) format: Larger formats require less enlargement to achieve the same viewing conditions. Thus, a larger diameter circle of confusion is permissible.
In creating depth of field tables or calculators, it is typical to use one conventional, or "industry standard" value for the circle of confusion. One common value is to use 1/1,500th of the diagonal of the image format. However this merely corresponds to average viewing conditions, such as holding an 8" x 10" print at arm's length. A more sophisticated depth of field calculator permits the user to select the circle of confusion as an independent value, corresponding to more or less stringent viewing conditions. | s3://commoncrawl/crawl-data/CC-MAIN-2022-33/segments/1659882571911.5/warc/CC-MAIN-20220813081639-20220813111639-00480.warc.gz | CC-MAIN-2022-33 | 1,441 | 4 |
https://www.hypertrophycoach.com/hypertrophy-forums/topic/hamstring-recovery/ | math | So apart from my hamstring , every other muscle recovers pretty well . Even though i use quite less volume , like 2 sets each of seated ham curl , and rdl …any particular reason for that ?
All other muscle groups have much .ore volume , but recover in time for the next session . Hams take generally longer , so now i stop few reps from failure . Why do u think it happens ? | s3://commoncrawl/crawl-data/CC-MAIN-2022-33/segments/1659882572198.93/warc/CC-MAIN-20220815175725-20220815205725-00381.warc.gz | CC-MAIN-2022-33 | 376 | 2 |
https://rogerpielkejr.blogspot.com/2010/06/wired-on-kaya-identity.html | math | Most of the ways we produce energy end up giving off carbon dioxide—which, in large quantities, screws up Earth's climate. But to reduce atmospheric CO2 we have to understand it. That's where Yoichi Kaya comes in. An engineer at Tokyo University, Kaya and a team of carbon experts put together this formula for computing the total CO2 emissions caused by humans—and where it comes from.If you want to see the Kaya Identity in action, pre-order your copy of The Climate Fix right now. (Thanks JJ)
Think about the equation for a while and you realize that if we want to reduce emissions to zero, then either population (P), consumption (g), energy used in production (e), or carbon used to produce that energy (f) must go to zero. Of course, we don't want to depopulate Earth or stop eating and commuting. Energy use might be cut dramatically, but it can't be zeroed out. So reducing any of those factors will just buy us some time to come up with a zero-carbon energy source. Get cracking, scientists!
03 June 2010
Wired on Kaya Identity
Here is fun online calculator from Wired illustrating the Kaya Identity. Wired writes: | s3://commoncrawl/crawl-data/CC-MAIN-2023-50/segments/1700679100518.73/warc/CC-MAIN-20231203225036-20231204015036-00866.warc.gz | CC-MAIN-2023-50 | 1,127 | 5 |
http://www.barmanstvi.cz/2008/10/video-z-pondlnho-trnovn.html | math | První český barmanský blog
With the value of certain 3D printers turning into ever cheaper and the standard continually growing many individuals have picked up the interest of 3D printing. As of present estimates there are over 2 million folks all over the world who have purchased a 3D printer for interest use. Construction of a model with up to date strategies can take anyplace from a number of} hours to a number of} days, depending on the strategy used and the scale and complexity of the model. Additive methods can usually scale back this time to a few hours, though it varies broadly depending on kind of|the type of} machine used and the scale and number of fashions being produced simultaneously. There is a growing R&D crisis Mittens occurring within the pharmaceutical trade, as medicine are failing at later and later levels. | s3://commoncrawl/crawl-data/CC-MAIN-2023-06/segments/1674764500664.85/warc/CC-MAIN-20230207233330-20230208023330-00796.warc.gz | CC-MAIN-2023-06 | 843 | 2 |
https://www.jwfsanctuary.club/forums/topic/link-vs-add/ | math | November 17, 2017 at 5:57 pm #863
Can someone explain the difference between when a variable is linked from simply adding a variable? I read every once in awhile someone will use the term link. And when does one use Link as opposed to Add?November 18, 2017 at 12:55 am #877
That’s a very good question, Bruce, and I wonder the same thing. I sometimes will add a linked transform without understanding what it does…I just know it does something different than strictly adding a transform. I do a lot of stuff with JWildfire that I don’t understand. I’m more of an intuitive fractal artist. I just explore and use a lot of trial and error. I’ll see if I can get someone in here to answer your question.November 18, 2017 at 1:11 am #878
While we’re waiting for someone to offer an answer, here are two links I just found that may help.
Also, I found this definition in a glossary of terms: Linked transform – A transform in a particular intimate relationship with another via xaos, opacity and color speed settings. Essentially, one transform’s ‘traffic’ (hits within the Chaos Game) is routed exclusively through another, which effectively becomes a post-transform with full transform properties.
The defining process for creating IFS (and therefore flame) fractals: a random point is ‘tranformed’ by the mapping function(s) (variations) contained in each of the transforms, the choice of which is influenced by the transform weight. The final fractal, to have sufficient aesthetic appeal, must have been generated by millions of such iterations.
The glossary of terms is found here: http://www.ultragnosis.com/fractals/Resources/Apophysis-Glossary.html
Note: That page was written for Apophysis, but there are many similarities to JWildfire. Most of it is the same.
I hope that helps for now. I’ll go ask some others what they think.November 18, 2017 at 1:56 am #880
Michael Hobbs got back with me on the answer to your question. This is a direct copy-and-paste from what he told me:
have a link to Andreas answering exactly this question. his answer – “1. Normally, in solving the IFS (iterated function system) each transform may be chosen after each other (independently).
2. You can influence this by choosing two types of weights:
– absolute weights (absolute probability to choose a certain transform at all)
– relative weights between transform A and B (probability to chose transform B, if transform A was selected before)
By default, all absolute weights are equal, and all relative weights are 1.0
3. A linked transform between two transforms A and B is a shortcut to set relative weights in a way, that
a) transform B can only be chosen after A was chosen
b) transform B is always chosen after A was chosen
I. E., a linked transform can also be achieved by setting the relative weights manually”November 19, 2017 at 8:44 pm #896
Thanks for that. It is interesting that when i was in high school I thought mathematics was a waste of time and something i did not do well at. I studied architecture in school and eventually settled on being a draftsman as my profession until i got into estimating. I can remember early on in my training that i would not be needing much math in my future endeavors. I might have to rethink that. But then again at 62 ….. well …..November 20, 2017 at 12:59 am #902
Well if it makes you feel any better, I majored in mathematics in college and I forgot all of it!November 20, 2017 at 1:51 am #915
Thanks. I do feel better.December 23, 2017 at 9:14 pm #2837
George Carlin said this in his routine about his college experience. Five years after he left he said he could fit everything he remembered from his college education on a five minute cassette tape. 😉December 23, 2017 at 11:07 pm #2853
I Like That.
You must be logged in to reply to this topic. | s3://commoncrawl/crawl-data/CC-MAIN-2018-22/segments/1526794867055.20/warc/CC-MAIN-20180525082822-20180525102822-00011.warc.gz | CC-MAIN-2018-22 | 3,833 | 25 |
https://www.studyalphaacademy.com/mathematics-honours-general | math | Bachelor of Science Honours in Mathematics classes for CALCUTTA UNIVERSITY (CU), JU, PRESIDENCY UNIVERSITY, ST. XAVIER’S COLLEGE (SEPARATE BATCHES)
B.Sc. (Hons.) Mathematics or Bachelor of Science Honours in Mathematics is an undergraduate Mathematics course. Mathematics is the study of quantity, structure, space, and change. B.Sc.Math(Hons.) Mathematics program provides in-depth knowledge about geometry, trigonometry, calculus and various other theories in Mathematics or related disciplines, such as computer science or statistics in addition to study of the normal Bachelor of Science subjects like Physics and Chemistry. The duration of the course is three years and the syllabus for the course is divided into six semesters or yearly. Sourav Sir’s Classes provides Coaching and tuition to those students who are pursuing B.Sc.Math(Hons/Gen) Mathematics. Coaching facility is available for students of all semesters or years.
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B.Sc. (Hons) Mathematics) degree serves as a basis for further higher studies in this field such as M.Sc, Ph.D and MPhil. Degree in Mathematics, the successful completion of which makes one eligible for the post of a lecturer in any university/college. B.Sc (Hons) (Mathematics) degree is very helpful in attaining other degrees in accounting and statistics, such as ICWA,etc.After completing B.Sc. (Hons)Mathematics, one can do post graduation in Mathematics/Applied Mathematics/Statistics /Actuarial Science/Astronomy/MCAVMBACAMCS and in a few more fields. After successfully completing B.Sc. (Hons.) (Mathematics) degree course, many job opportunities open up in statistics, actuarial sciences, mathematical modelling, cryptography, computer sciences, etc.
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Similar Course in B.Sc. (Hons.) Mathematics:
Advance Courses in B.Sc. (Hons.) Mathematics: | s3://commoncrawl/crawl-data/CC-MAIN-2019-43/segments/1570987756350.80/warc/CC-MAIN-20191021043233-20191021070733-00166.warc.gz | CC-MAIN-2019-43 | 2,369 | 19 |
https://paginas.matem.unam.mx/matematicos/matematicos-i-p/matematicos-l/lefschetz-s/461-teoremas-de-lefschetz | math | Cuando algún estudiante venía orgulloso con un astuto argumento para dar una prueba corta de alguno de los teoremas de Lefschetz, más que felicitarlo, dicen que le decía:
No me venga usted con sus pruebas bonitas. No nos molestamos con infantilismos.
Lefschetz valued independent thinking and originality above everything. He was, in fact, contemptuous of elegant or rigorous proofs of what he considered obvious points. He once dismissed a clever new proof of one of this theorems by saying, "Don't come to me with your pretty proofs. We don't bother with that baby stuff around here." Legend had it that he never wrote a correct proof or stated an incorrect theorem. His first comprehensive treatise on topology, a highly influential book in which he coined the term "algebraic topology," "hardly contains one completely correct proof. It was rumored that it had been written during one of Lefschetz' sabbaticals ... when his students did not have the opportunity to revise it."
Sylvia Nasar, A Beautiful Mind, 1998. | s3://commoncrawl/crawl-data/CC-MAIN-2022-33/segments/1659882572515.15/warc/CC-MAIN-20220816181215-20220816211215-00278.warc.gz | CC-MAIN-2022-33 | 1,022 | 4 |
https://www.northlandcollege.edu/programs/nursing/program_detail.php?quick_facts=program_facts&program_code=467 | math | Program Mission Statement
The mission of Northland Community and Technical College's Nursing Program is to serve learners, society, and particularly the region through a collaborative approach in the educational preparation of nursing personnel.
Northland Community and Technical College's (NCTC) Nursing program functions in conjunction with the mission and vision of NCTC. NCTC's nursing program has multiple campuses and modes of delivery which are committed to inspire student success and cultivate a quality educational environment.
The PN program develops the professional behaviors of the student Practical Nurse through utilization of the nursing process, with emphasis in the areas of communication, teamwork, and interprofessional collaboration.
Ongoing quality improvement activities are performed implementing established EBP, and current technology to deliver quality safe patient centered care.
Program Completion Rates:
Year -- Total
2015 -- 91%
2016 -- 85%
2017 -- 93%
2018 -- 88%
2019 -- 85%
NCLEX-PN Licensure Pass Rates:
|Year || NCTC || MN || National | | s3://commoncrawl/crawl-data/CC-MAIN-2021-25/segments/1623488517048.78/warc/CC-MAIN-20210622093910-20210622123910-00527.warc.gz | CC-MAIN-2021-25 | 1,122 | 14 |
https://competitive-exam.in/questions/discuss/among-t-v-b-e-and-c-who-is-the-third-from-the | math | Among T, V, B, E and C, who is the third from the top when arranged in the descending order of their weights ? Statements: (I) B is heavier than T and C and is less heavier than V who is not the heaviest. (II) C is heavier than only T.
A. I alone is sufficient while II alone is not sufficient
B. II alone is sufficient while I alone is not sufficient
C. Either I or II is sufficient
D. Neither I nor II is sufficient
E. Both I and II are sufficient
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Correct Answer : A.
From I, we have: B > T, B > C, V > B. Thus, V is heavier than each one of B, T and C. But V is not the heaviest. So, E is the heaviest. Thus, we have the order. E>V>B>T>C or E>V>B>C>T. Clearly, B is third from the top. | s3://commoncrawl/crawl-data/CC-MAIN-2021-49/segments/1637964362930.53/warc/CC-MAIN-20211204033320-20211204063320-00406.warc.gz | CC-MAIN-2021-49 | 726 | 9 |
http://tt.tennis-warehouse.com/showpost.php?p=7062296&postcount=344 | math | Originally Posted by Bartelby
Flagrant has something to do with intent, but intent can be inferred from behaviour.
Flagrant does not just mean clear or obvious, as you seem to think.
I don't think the rule as it stands is there to allow the receiver to engage in pedagogy.
It is not just me who seems to think that.
"shockingly noticeable or evident; obvious; glaring: a flagrant error."
"(of a bad action, situation, person, etc.) shocking because of being so obvious"
"Obvious and offensive, blatant, scandalous"
None of these mention intent. You did find a different definition that mentions the appearance
of intent. However, the word can certainly be used to mean simply surprisingly clear and obvious. To argue otherwise would be to argue that the above definitions are all flat out wrong. You are of course free to do that. I am of course free to think it is you who are wrong instead. | s3://commoncrawl/crawl-data/CC-MAIN-2015-18/segments/1430454576828.73/warc/CC-MAIN-20150501042936-00062-ip-10-235-10-82.ec2.internal.warc.gz | CC-MAIN-2015-18 | 892 | 10 |
https://borjsazan-rastak.com/qa/quick-answer-is-hz-equal-to-s-1.html | math | - What is the frequency in 1 s?
- Can I get 100 fps on 60hz monitor?
- What does S mean in frequency?
- What is the best frequency?
- What is the wavelength of 1 Hz?
- Is 5ms good for gaming?
- How many M are in a Hz?
- Is 75hz better than 60hz?
- What is Hz equivalent to?
- What is m/s divided by Hz?
- Does 120hz mean 120fps?
- Does 144hz mean 144fps?
- How many Hertz is 2 seconds?
- Why is frequency V?
- How do you convert Hz to SEC?
- Does 60hz mean 60 fps?
- How do you convert M to Hz?
- Is 75hz good for gaming?
- How do you calculate Hz?
- What is the frequency of 20?
- Can I get 100 fps on 75hz monitor?
What is the frequency in 1 s?
One wave per second is also called a Hertz (Hz) and in SI units is a reciprocal second (s−1).
The variable c is the speed of light..
Can I get 100 fps on 60hz monitor?
No, the max FPS you can get on your 60HZ display is 60 fps, if it is showing 100 fps on the game also you are getting only 60 fps. Your PC can sure send a 100 frames to your 60Hz monitor but it will just dicard the 40 extra frames and you will never see them until and unless you have a 100+ Hz monitor.
What does S mean in frequency?
Frequency’s units are per second, written s-1 or hertz, Hz. … Hertz and per second are identical units, i.e. 1 s-1 = 1 Hz. Example 1. When describing a moving wave, frequency means the number of peaks which pass a stationary point in a given amount of time.
What is the best frequency?
Most can agree that 440 Hz, the modern standard, should be replaced – but there’s some argument over which frequency should replace it: 432 Hz or 528 Hz.
What is the wavelength of 1 Hz?
For sound waves in air, the speed of sound is 343 m/s. The wavelength of a tuning fork (440 Hz) is thus equal to approximately 0.78 m. In SI units, the unit of frequency is the hertz (Hz). 1 Hz means that an event repeats once every second.
Is 5ms good for gaming?
5ms is good enough for games. 2ms can be better if other specs are also better. 5ms monitors can be better as they can offer better image quality, only the low quality TN panels can offer 2ms response times. … For the most part, though, TN panels these days are indistinguishable from other types of monitors.
How many M are in a Hz?
299792458m↔Hz 1 Hz = 299792458 m.
Is 75hz better than 60hz?
When comparing 60 Hz vs 75 Hz refresh rates, the answer is quite clear: 75 Hz is better. … Higher refresh rates are associated with better video quality, reduced eye strain, and even improved gaming experiences. And while 60 Hz has been the bare minimum for decades, a 75 Hz monitor offers an accessible upgrade.
What is Hz equivalent to?
Frequency is the rate at which current changes direction per second. It is measured in hertz (Hz), an international unit of measure where 1 hertz is equal to 1 cycle per second. Hertz (Hz) = One hertz is equal to one cycle per second. Cycle = One complete wave of alternating current or voltage.
What is m/s divided by Hz?
λ = c / f = wave speed c (m/s) / frequency f (Hz). The unit hertz (Hz) was once called cps = cycles per second. Centimeters per period / div. What is 1 Hertz equal to?…149896229 m.Wavelength In Metres [m]Hertz [Hz]2 m149896229 Hz3 m99930819.333333 Hz2 more rows•Feb 21, 2020
Does 120hz mean 120fps?
A 120Hz display refreshes twice as quickly as a 60Hz display, so it can display up to 120fps, and a 240Hz display can handle up to 240fps. This will eliminate tearing in most games.
Does 144hz mean 144fps?
as Punzer mentioned, the 144hz, directly translates to 144fps. the max frame rate you can display on the screen will be 144fps. … after 120 the difference is so slim that even people who use high refresh rate monitors for Esports cant tell the difference.
How many Hertz is 2 seconds?
Convert Cycles Per Second to Hertz A period of 1 second is equal to 1 Hertz frequency.
Why is frequency V?
It is NOT the letter v, it is the Greek letter nu. It stands for the frequency of the light wave. Frequency is defined as the number of wave cycles passing a fixed reference point in one second. … This is one cycle of the wave and if all that took place in one second, then the frequencey of the wave is 1 Hz.
How do you convert Hz to SEC?
In relation to the base unit of [frequency] => (hertz), 1 Hertz (Hz) is equal to 1 hertz, while 1 1 Per Second (1/s) = 1 hertz….FREQUENCY Units Conversion. hertz to 1-per-second.Hertzto 1 Per Second (table conversion)700 Hz= 700 1/s800 Hz= 800 1/s900 Hz= 900 1/s1000 Hz= 1000 1/s34 more rows
Does 60hz mean 60 fps?
A loose definition of Hz is “per second”. … A loose definition of Hz is “per second”. A 60Hz monitor can display any framerate up to 60fps with no issue. Anything above 60fps still looks exactly the same as 60fps, though screen tearing (fast-moving objects may have half of them flash or not appear correctly).
How do you convert M to Hz?
Please provide values below to convert wavelength in metres [m] to hertz [Hz], or vice versa….Wavelength In Metres to Hertz Conversion Table.Wavelength In Metres [m]Hertz [Hz]1 m299792458 Hz2 m149896229 Hz3 m99930819.333333 Hz5 m59958491.6 Hz7 more rows
Is 75hz good for gaming?
A simple question with a simple answer: YES. Of course, 75Hz still works for gaming, even 60Hz still works. … It is when your PC can render game frames at more than 75 fps. So for budget gamers, if the fps count is less than 75, then choose a 75Hz monitor and save some money.
How do you calculate Hz?
Frequency is expressed in Hz (Frequency = cycles/seconds). To calculate the time interval of a known frequency, simply divide 1 by the frequency (e.g. a frequency of 100 Hz has a time interval of 1/(100 Hz) = 0.01 seconds; 500 Hz = 1/(500Hz) = 0.002 seconds, etc.)
What is the frequency of 20?
Audible sound waves have a frequency of roughly 20 Hz to 20,000 Hz (20 kilohertz). Therefore, the sounds you hear have waves that occur anywhere from 20 to 20,000 times per second.
Can I get 100 fps on 75hz monitor?
For a 75Hz monitor, you should restrict the frame rate to 75 fps. This will remove screen tearing and also reduce input lag. … However, if you’re playing a game, it may not constantly run at that many frames per second. Or, you may not have a PC powerful enough to project that many frames. | s3://commoncrawl/crawl-data/CC-MAIN-2021-31/segments/1627046154385.24/warc/CC-MAIN-20210802203434-20210802233434-00202.warc.gz | CC-MAIN-2021-31 | 6,260 | 64 |
https://mars.vesmir.cz/detail/USfEiDOm?fbclid=IwAR1lFC2pkpNvLrJL4ZWjkQHg4JkhVaJQp2QTae4oWoZAXAjmNlAZ4yMEptQ | math | A cascade of tones fall from the top note of the piano to the bottom and rise back again, each mirroring the other. This whole tone melody passes once through what might be an endless spiralling 30 second cycle, each note of the piano's 88 sounded once. Two scales, gazing at each other across space and time. On the surface each pattern repeats in different depths of pitch, but their harmonic symmetries are dissolved in perception of the fleeting present moment.
Words of the recording
||: C8 . A#7 G#7 F#7 E7 D7 C7 Bb6 | G#6 F#6 E6 D6 C6 Bb5 Ab5 | F#5 E5 D5 C5 Bb4 Ab4 Gb4 | E4 D4 C4 Bb3 Ab3 Gb3 Fb3 | D3 C3 Bb2 Ab2 Gb2 Fb2 Ebb2 | C2 Bb1 Ab1 Gb1 Fb1 Ebb1 Dbb1 . Bb0 | A0 . Cb0 Db1 Eb1 F1 G1 A1 B1 | Db2 Eb2 F2 G2 A2 B2 C#3 | Eb3 F3 G3 A3 B3 C#4 D#4 | F4 G4 A4 B4 C#5 D#5 E#5 | G5 A5 B5 C#6 D#6 E#6 Fx6 | A6 C6 C#7 D#7 E#7 Fx7 Gx7 . B7 :|| live first performance by Thomas Nicholson, piano, at KM28 Berlin, 15 February 2019, composed by Marc Sabat
Back to the list of audio recordings | s3://commoncrawl/crawl-data/CC-MAIN-2022-05/segments/1642320304959.80/warc/CC-MAIN-20220126162115-20220126192115-00048.warc.gz | CC-MAIN-2022-05 | 987 | 4 |
http://www.pauldervan.com/2010/06/asking-for-just-penny-can-increase.html | math | Friday, June 11, 2010
Asking for just a penny can increase donations.
Image courtesy of sally monster
Last month, Conor wrote an interesting article about charity donations raised through text message. One of the assumptions that Conor questioned was this: If you ask people to donate through text, they will give less. You might get more people to give (higher response), but overall you will collect less cash for your efforts.
I don't know the answer. I understand the logic but think Conor is right to at least question this.
There is an interesting experiment from the American Cancer Society with surprising results. While not related to text messaging, it is related to asking for less. It may not hold up over text donations, but worth at least challenging the assumptions.
As part of a fundraising campaign, Robert Cialdini and the American Cancer Society went door-to-door asking for donations.
One half of the those they spoke with were asked the following question "Would you be willing to help by giving a donation?". For the other half, they added the following line "Even a penny will help".
The results? Almost twice as many people gave when told that even a penny would help. While not surprising, this might lead to one type of strategy over another. So instead of aiming to raise as much money as possible in one go, you might aim to get as many people as possible to show an initial interest, collect their details and then work on this group over time to turn them into advocates.
Here's the surprising bit from the experiment.
Despite being told that 'even a penny would help' the donation sizes were no smaller than the first group. So overall, by telling people that 'even a penny would help' increased the number of donations and the total amount collected. Nice eh.
Lots of behavioural economics examples like this in Robert Cialdini's books. | s3://commoncrawl/crawl-data/CC-MAIN-2024-18/segments/1712296817670.11/warc/CC-MAIN-20240420153103-20240420183103-00647.warc.gz | CC-MAIN-2024-18 | 1,868 | 12 |
https://saratchandrabankingssc.com/quiz/sarat-chandra-banking-ssc-june-17th-2021/ | math | Welcome to your Sarat Chandra Banking SSC June 17th 2021
1. The difference between the compound interest compounded annually and the simple interest on a certain sum for 2 years at 6% per annum is $ 18. Find the sum.
2. In what time will Rs.1000 become Rs.1331 at 10% per annum compounded annually
3. Certain sum becomes 3 times it self at compound interest in 10 years. In how many years it becomes 9 times?
4. Arrange the words given below in a meaningful sequence. 1. Word 2. Paragraph 3. Sentence 4. Letters 5. Phrase
5. Arrange the words in a meaningful, logical order and then select the appropriate sequence from the alternatives given below. 1. Farmer 2. Seed 3. Food 4. Cultivation
6. 1. Mother 2. Child 3. Milk 4. Cry 5. Smile
7. A person who talks in sleep is called a
8. Not allowing the passage of light.
9. Which of the following is used to represent a Weak entity set?
10. What is the name given to the electronic device that receives a signal and retransmits it at a higher level? | s3://commoncrawl/crawl-data/CC-MAIN-2023-14/segments/1679296949009.11/warc/CC-MAIN-20230329151629-20230329181629-00514.warc.gz | CC-MAIN-2023-14 | 996 | 11 |
https://www.dariosbrickoven.com/items/darios-12 | math | Back To Menu
mozzarella, roasted red peppers, artichoke hearts, prosciutto.
Extra Cheese +$2.50
Meat (Md):Anchovies +$2Bacon +$2Chicken +$2Hamburger +$2Meatball +$2Prosciutto +$2Pepperoni +$2Sausage +$2Ham +$2
Vegetable (md):Artichoke Hearts +$2Broccoli +$2Black olives +$2Caramelized Onions +$2Green pepper +$2Mushrooms +$2Onions +$2Pineapple +$2Roasted Eggplant +$2Roasted Red Peppers +$2Spinach +$2Sun-dried Tomatoes +$2Garlic +$2Cherry peppers +$2
Have you tried this item? Pop it!
Help other diners know what to expect by sharing your experience.
6 people have popped this item | s3://commoncrawl/crawl-data/CC-MAIN-2022-40/segments/1664030337371.9/warc/CC-MAIN-20221003003804-20221003033804-00445.warc.gz | CC-MAIN-2022-40 | 582 | 8 |
https://folk.ntnu.no/deng/fra_nt/other%20stuff/DSC_manuals/QDSC/About_Modulated_DSC.htm | math | MDSC is used to study the same material properties as conventional DSC including: transition temperatures, melting and crystallization, and heat capacity. However, MDSC provides unique capabilities that increase the amount of information that can be obtained from a single DSC experiment, thereby improving the quality of interpretation. These capabilities include:
Measurement of heat capacity and heat flow in a single experiment
Separation of complex transitions into more easily interpreted components
Increased sensitivity for detection of weak transitions
Increased resolution of transitions without loss of sensitivity
Increased accuracy in the measurement of polymer crystallinity
Direct determination of thermal conductivity.
The MDSC option includes special enhancements to the TA controller software and the DSC software.
For maximum experimental flexibility and highest quality results, MDSC experiments should be run using either a Refrigerated Cooling System (RCS) or a Liquid Nitrogen Cooling System (LNCS). The Finned air Cooling System (FACS) can be used to obtain MDSC results above ambient temperatures. However, experimental parameters (e.g., modulation amplitude) could be limited. The Quench Cooler is not compatible with MDSC.
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In MDSC a more complex heating profile (temperature regime) is applied to the sample than is used in conventional DSC. Specifically, a sinusoidal modulation (oscillation) is overlaid on the conventional linear heating or cooling ramp to yield a profile in which the average sample temperature changes sinusoidally rather than linearly. The net effect of imposing this more complex heating profile on the sample is the same as if two experiments were run simultaneously on the material—one experiment at the traditional linear (average) heating rate and one at a sinusoidal (instantaneous) heating rate. The general equation that describes the resultant heat flow at any point in a DSC or MDSC experiment is:
dQ/dt = Cpb + f(T,t)
dQ/dt = total heat flow
Cp = heat capacity
b = heating rate
f(T,t) = heat flow from kinetic (absolute temperature and time-dependent) processes
This equation clearly shows that the total heat flow (dQ/dt), which is the only heat flow measured by conventional DSC, is composed of two components. One component is a function of the sample's heat capacity and rate of temperature change, and the other is a function of absolute temperature and time. These components are generally referred to as the "reversing" and "nonreversing" heat flows respectively.
The actual complex temperature/time profile in MDSC depends on three variables—underlying heating/cooling rate, modulation period, and modulation temperature amplitude. There are three common types of operator-selectable MDSC experiments:
Conventional MDSC: In conventional MDSC experiments, all three variables are operator-selected and the experiment can be performed over some temperature range while either heating or cooling.
Heat-Only MDSC: Only modulation period and heating rate are operator-selectable in Heat Only MDSC experiments. The instrument automatically determines the modulation temperature amplitude required to ensure that the instantaneous heating rate goes to zero (isothermal) at one extreme of the temperature modulation cycle.
Quasi-Isothermal MDSC: In quasi-isothermal MDSC experiments the underlying heating rate is zero. However, by selecting a modulation temperature amplitude and period, the material is still exposed to an instantaneous heating rate, which permits the isothermal measurement of heat capacity.
Back to top | s3://commoncrawl/crawl-data/CC-MAIN-2023-23/segments/1685224648850.88/warc/CC-MAIN-20230602172755-20230602202755-00733.warc.gz | CC-MAIN-2023-23 | 3,600 | 22 |
https://productivityist.com/review-labour-day/ | math | I took my kids to this.
I started to work on this.
I watched a bunch of this.
I outlined some stuff for this.
I played a bit of this.
I rehearsed this.
Then I wrote this.
None of what I did on Labour Day is what I would call “labour” — because none of it felt like work. The result: A balanced day.
Because it all felt right and it felt alright. | s3://commoncrawl/crawl-data/CC-MAIN-2024-18/segments/1712296817249.26/warc/CC-MAIN-20240418222029-20240419012029-00420.warc.gz | CC-MAIN-2024-18 | 351 | 9 |
https://www.heldermann.de/JLT/JLT25/JLT254/jlt25043.htm | math | Journal of Lie Theory 25 (2015), No. 4, 903--947
Copyright Heldermann Verlag 2015
Isomorphy Classes of Involutions of SP(2n, k), n>2
Robert W. Benim
Dept. of Mathematics and Computer Science, Pacific University, 2043 College Way, Forest Grove, OR 97116, U.S.A.
Aloysius G. Helminck
Dept. of Mathematics, North Carolina State University, 2108 SAS Hall, Box 8205, Raleigh, NC 27695, U.S.A.
Farrah Jackson Ward
Dept. of Mathematics and Computer Science, Elizabeth City State University, 132 Lane Hall, Campus Box 851, Elizabeth City, NC 27909, U.S.A.
A first characterization of the isomorphism classes of k-involutions for any reductive algebraic groups defined over a perfect field was given by A. G. Helminck [On the Classification of k-involutions I, Adv. in Math. 153 (2000) 1--117] using 3 invariants. In another paper of A. G. Helminck, Ling Wu and C. Dometrius [Involutions of Sl(n, k), (n > 2), Acta Appl. Math. 90 (2006) 91--119] a classification of all involutions on SL(n,k) for k algebraically closed, the real numbers, the p-adic numbers or a finite field was provided. In this paper, we build on these results to develop a detailed characterization of the involutions of SP(2n,k). We use these results to classify the isomorphy classes of involutions of SP(2n, k) where k is any field not of characteristic 2.
Keywords: Symplectic Group, Involutions, Inner-automophisms.
MSC: 20G15, 20K30
[ Fulltext-pdf (418 KB)] for subscribers only. | s3://commoncrawl/crawl-data/CC-MAIN-2023-40/segments/1695233510941.58/warc/CC-MAIN-20231001205332-20231001235332-00077.warc.gz | CC-MAIN-2023-40 | 1,447 | 13 |
https://www.physicsforums.com/threads/motion-acceleration-equations.529866/ | math | Within 4 sec of liftoff, a spacecraft that is uniformly accelerating straight upward from rest reaches an altitude of 450 m [up]. What is the spacecraft 's acceleration?
The five key equations, plus the velocity, speed, and acceleration equations
The Attempt at a Solution
I don't know what the altitude would be (Displacement? Distance?), so I can't solve the equation with the five key equations. | s3://commoncrawl/crawl-data/CC-MAIN-2023-23/segments/1685224648850.88/warc/CC-MAIN-20230602172755-20230602202755-00006.warc.gz | CC-MAIN-2023-23 | 398 | 4 |
http://hydoho.com/epub/algebra-2-student-edition-ccss-merrill-algebra-2 | math | By McGraw-Hill Education
This system scholars want; the focal point lecturers wish! Glencoe Algebra 2 is a key application in our vertically aligned highschool arithmetic sequence constructed to assist all scholars in attaining a greater figuring out of arithmetic and increase their arithmetic ratings on today’s high-stakes checks.
Read or Download Algebra 2, Student Edition PDF
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28) Examples 2–4 (pp. 5. 1. a + 12 2. -6b 3. 2 FOOD For Exercises 4–6, use the following information. Most meat thermometers are accurate to within plus or minus 2°F. 4. If a meat thermometer reads 160°F, write an equation to determine the least and greatest possible temperatures of the meat. 5. Solve the equation you wrote in Exercise 4. 6. Ham needs to reach an internal temperature of 160°F to be fully cooked. To what temperature reading should you cook a ham to ensure that the minimum temperature is reached? | s3://commoncrawl/crawl-data/CC-MAIN-2017-43/segments/1508187826642.70/warc/CC-MAIN-20171023202120-20171023222120-00080.warc.gz | CC-MAIN-2017-43 | 3,373 | 15 |
http://www.rfreitas.com/Astro/HEPCETI1977.htm | math | Note: This web version is derived from an earlier draft of the paper and may possibly differ in some substantial aspects from the final published paper.
Sir, D. M. Jones has suggested that high energy particles in the 1010-1015 eV range might be used in CETI work . Although he makes passing mention of the "distorting effects of interstellar magnetic fields," I find no reference to the drift (caused by the Galactic magnetic field) in alignment of the particle beam itself.
Qualitatively, if such a beam is aimed exactly parallel to the local Galactic field, there will be no VxB force whatsoever. However, if the beam is normal to the field, deflection is maximal. Instead of travelling in a straight path from Earth to target star, the particles (assuming they're charged) trace out a gigantic loop in space, circling the magnetic field lines at some radius R. A simple calculation reveals that even across relatively short transmission distances, curvature of the beam is unacceptable for any reasonable particle energy E.
The relevant relativistic equations are as follows:
Lines of magnetic force are known roughly to follow the spiral arm structure of the Milky Way and to possess a strength of about 10-5 gauss [2, 3]. Assuming the bean is properly aimed, it will curve around and just barely reach the target if R is one-half the distance thereto. If we send message via high energy protons across ten light-years as Jones suggests, E must be at least 1.4 x 1016 eV if q = 90o (This assumes, of course, a nice, uniform B field all the way a dubious proposition at best).
If 1010 eV particles are used, the target must lie within q ~ 0.00002o of the Galactic field vector - probably not the direction in which we wish to transmit! Even if 1015 eV protons are used, the situation is not much. improved. To each a target 10 light-years distant, it must lie within q ~ 2o, which is still a miniscule CETI 'window,' and transmissions farther than 10 light-years are even more restricted.
In view of the Galactic deflection problem, it is difficult to see how
charged particle beams could represent the preferred communication mode for
advanced extraterrestrial civilisations.
Mr. Jones replies:
I would like to thank Mr. Freitas for pointing out the distorting effects of a uniform magnetic field along the path of the beam. In my initial analyses I had assumed that such a field would be very weak, or that it would be confined to small volumes of space with random orientations. This would cause small tweaks in the direction of travel but over small distances, 10 light years say, the distortion should not be excessive.
The effect of a uniform field throughout the length of the beam would be much more disturbing as the beam would travel in a large circle. This bending could be taken into account by the sender when aiming the beam, the receiver would receive the signal (provided that the receiver was not farther away from the sender than the diameter of the circle). However, one vital piece of information would be denied the receiver: from what part of the Galaxy did the beam originate? Knowing that the beam was bent by magnetic fields, and that the sender would be aware that the beam would be bent, the receiver would be forced to the conclusion that the transmitter was nearby, close enough that the arc of a circle traced out approximated a straight line. An electromagnetic search could then be made of the area of the sky from which the beam came, electromagnetic radiation being the preferred mode of communication due to the relative ease of transmission and the much higher data rate. I suggest the use of high energy particles as the attention getting mode, the main message being "LOOK OVER HERE", since they would be very easy to observe, although the correct interpretation of their origin may not be so easy.
Because of the curvature and dispersion of the beam its use is a strictly local affair. The condition that the path of the beam approximates a straight line sets a lower limit on the energy of the particles used, dependent on the mass of the particles used, distance between sender and receiver, the angle the beam makes with the galactic field and the strength of that field. What is an acceptable level of curvature for the beam? I think that 20' is a reasonable deviation, remembering that the receiving intelligence will be aware of the curvature of the beam and will accordingly widen the search to nearby stars centred around the direction of the beam.
The strength of the galactic field is still in dispute, but it is believed to be between 10-1-10-5 gauss, its effect on the beam being proportional to sinq where q is the angle between the direction of the beam and the magnetic field.
Taking these facts into consideration, I would like to increase my
original estimate of the particle energy to the 1015-1019
eV range, and to suggest that protons be used in preference to electrons. | s3://commoncrawl/crawl-data/CC-MAIN-2023-23/segments/1685224644683.18/warc/CC-MAIN-20230529042138-20230529072138-00357.warc.gz | CC-MAIN-2023-23 | 4,933 | 17 |
https://www.rhayden.us/microeconomic-theory/c10.html | math | fFirst Printing Errata: At the end of the first paragraph insert:
Assume throughout that conditions are such that (23. C. 8) holding is a condition for (k*(-),t1(•)»...•)j) to be truthfully
implementable in dominant strategies." Also, in the second line of part c)
insert the word "implementable" before "ex post efficient social choice function".]
a) Sufficiency: Suppose. that we can write V*(0) - Ei^i^ i)m Consider the transfer functions of the form tL(B) - [l Vj <**(»),fj)] + \
where for all i,
By proposition 23.C.4, (k*(•).•),...,t(•K) is truthfully implementable in
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http://timecapsule.x10.mx/ | math | Weekly Edition Volume 2, Number 49 December 5, 2015
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https://booking.mage-people.com/average-cost-definition-average-cost-definition/ | math | average cost definition: Average Cost Definition, Formula, Calculation, Examples
AFC declines continuously as output rises, as a given total amount of fixed cost is ‘spread’ over a greater number of units. For example, with fixed costs of £1,000 per year and annual output of 1000 units, fixed costs per unit would be £1, but if annual output rose to 2000 units the fixed cost per unit would fall to 50p. Unit variable cost tends to remain constant over the output range. To determine the total cost of a business, all the costs that accrue from producing a certain quantity over a period are considered. Variable costs are the cost that changes with the change in the number of quantities produced. Average cost can be divided into short-run and long-run average costs Short-run average cost- varies with the production of goods, provided the fixed costs are zero, and the variable costs are constant.
We can https://1investing.in/ the average cost using the following equation, where TC stands for the total cost and Q means the total quantity. GAAP allows for last in, first out , first in, first out , or average cost method of inventory valuation. On the other hand, International Financial Reporting Standards do not allow LIFO because it does not typically represent the actual flow of inventory through a business. Average cost method is a simple inventory valuation method, especially for businesses with large volumes of similar inventory items. Instead of tracking each individual item throughout the period, the weighted average can be applied across all similar items at the end of the period.
Manufacturing costs vs. non-manufacturing costs
It will be further discussed in the short-run average cost curve. So, an estimate is made before starting the production process on the cost that would incur in the production process. If the estimate is done for a short period that does not consider the change in the number of goods, it is called short-run average cost.
Utilizing an average-cost pricing strategy, a producer charges, for each product or service unit sold, only the addition to total cost resulting from materials and direct labor. Businesses will often set prices close to marginal cost if sales are suffering. If, for example, an item has a marginal cost of $1 and a normal selling price is $2, the firm selling the item might wish to lower the price to $1.10 if demand has waned. The business would choose this approach because the incremental profit of 10 cents from the transaction is better than no sale at all.
Using the Average cost inventory method (WAC) in a perpetual inventory
The average cost method utilizes the average of every similar good in the inventory irrespective of the date of purchase. It is then followed by the count of inventory items at the end of the accounting duration. To get the figure of the cost of goods available for sale, you multiply the average price per item by the final inventory count. You can apply the same average cost to the number of things you sell during the previous accounting period and still determine the cost of goods sold. Marginal costs and average costs are both equally important tools of analysis that can provide a deep and a meaningful insight pertaining to the overall costing function of the business. If, in the above example, the number of units produced during the year increased to 25,000, then determine the average cost of production for the increased production.
The average variable cost curve lies below the average total cost curve and is typically U-shaped or upward-sloping. Marginal cost is calculated by taking the change in total cost between two levels of output and dividing by the change in output. The first and foremost step is drafting a proper Business plan which includes both the long run as well as the short-run expenses. Calculating your cost beforehand helps you figure out your profit and the number of units that are to be produced. The short-run average cost determines the cost of fixed and variable short-run factors which in turn helps in estimating the average production.
Average Cost vs Marginal Cost
On the other hand, if the business opts to follow the cost concept, it’s not allowed to record revaluation. More generalized in the field of economics, cost is a metric that is totaling up as a result of a process or as a differential for the result of a decision. Hence cost is the metric used in the standard modeling paradigm applied to economic processes.
The quantity is shown on the x-axis, whereas the cost in dollars is given on the y-axis. You can think of the fixed cost as the amount of money you need to open a bakery. This includes, for instance, necessary machines, stands, and tables. In other words, fixed costs equal the required investment you need to make to start producing.
They are also known as traceable costs as they could be traced to a specific activity. Hence there are several different types of concepts of cost, which have been discussed in the following. Barriers to entry are the costs or other obstacles that prevent new competitors from easily entering an industry or area of business. Antitrust laws apply to virtually all industries and to every level of business, including manufacturing, transportation, distribution, and marketing. A defensive cost is an environmental expenditure to eliminate or prevent environmental damage. Defensive costs form part of the genuine progress indicator calculations.
Components of the Average Cost equation
Since the average cost definition cost is spread over the produced quantity, given a certain amount of fixed cost, the average fixed cost decreases as the output increases. The relationship between the average total cost curve and marginal cost curve is illustrated in Figure 2 below. The average total cost function has a U-shape, which means it is decreasing for low levels of output and increases for larger output quantities. This effect is called the spreading effect since the fixed cost is spread over the produced quantity. Given a certain amount of fixed cost, the average fixed cost decreases as the output increases. Here, the numerator represents the change in the total cost, and the denominator denotes the change in output.
Statistical evidence for the contribution of citizen-led initiatives and … – Nature.com
Statistical evidence for the contribution of citizen-led initiatives and ….
Posted: Thu, 02 Mar 2023 16:04:14 GMT [source]
Average fixed cost shows us the total fixed cost for each unit. This is the most efficient quantity to produce, as the average total cost is minimized. AVC is the Average Variable Cost, AFC the Average Fixed Cost, and MC the marginal cost curve crossing the minimum points of both the Average Variable Cost and Average Cost curves. The characteristic U-shape of the long-run average cost curve. It means you are selling products to your customers, and as such, you must deal with an inventory.
So in short cost is nothing but the expenses incurred to produce one unit of product. Average cost vs Marginal cost is the different type of cost technique used to calculate the production cost of output or product. Breaking down of costs into an average cost and marginal cost is important because each technique offers its own insight to the firm. The average cost is the sum of the fixed cost and average variable cost.
When Not to Use Average Costing
When there is an increase in the company’s production, then the AFC of the company falls. So, there is the advantage of the increase in the output, and the profit of the company, in that case, will be more. These machines are recorded on the balance sheet for the amount of money the business paid for them plus any expenses required to put them into service. Each piece of equipment is recorded this way on the balance sheet. Levels of output, the spreading effect dominates the diminishing returns effect.
Organizations following the revaluation concept need to apply technical accounting rules regarding unrealized gain, and depreciation. It is easy to locate the cost of the assets as there is no judgment. There is no revaluation, and there is no change in the amount/balance of the asset.
A method of determining the value of securities in a tax year. One calculates the average cost by taking the total cost of buying shares in a security and dividing it by the number of shares one owns. The average-cost method is useful especially when the security has fluctuated significantly in price and when the investor has an automatic investment plan.
- We can calculate the average cost using the following equation, where TC stands for the total cost and Q means the total quantity.
- The driver does not compensate for the environmental damage caused by using the car.
- It will be used by firms who are seeking to increase market share and who don’t seek to maximise profits.
- Efiling Income Tax Returns is made easy with ClearTax platform.
- All these costs can also be graphically depicted on the short-run average cost curve.
- Such changes may not sit well with your customers, and it will also make it hard for you to create quotations for prospective clients.
Indirect costs are expenses that could not be traced back to a single cost object or cost source. However, they are extremely important as they affect the total profitability. In practice, it can be difficult to work out a firms average cost. | s3://commoncrawl/crawl-data/CC-MAIN-2023-14/segments/1679296944996.49/warc/CC-MAIN-20230323034459-20230323064459-00237.warc.gz | CC-MAIN-2023-14 | 9,441 | 31 |
http://www.chegg.com/homework-help/questions-and-answers/recent-year-available-mean-annual-cost-attend-private-university-united-states-20-157-assu-q2699107 | math | For the most recent year available, the mean annual cost to attend
a private university in the United States was $20,157. Assume the
distribution of annual costs follows the normal probability
distribution and the standard deviation is $4,425.
Ninety-five percent of all students at private universities pay
less than what amount? (Round z value to 2 decimal places and your
final answer to the nearest whole number. Omit the "$" sign in your | s3://commoncrawl/crawl-data/CC-MAIN-2013-20/segments/1368710963930/warc/CC-MAIN-20130516132923-00021-ip-10-60-113-184.ec2.internal.warc.gz | CC-MAIN-2013-20 | 442 | 7 |
https://www.coursehero.com/file/8946335/One-Definition-For-a-function-ft-ft0-for-t0-Definition-ft/ | math | Unformatted text preview: course!
Definition: For a function f(t) (f(t)=0 for t<0),
f(t) (f(t)=0 Design specs
Frequency domain (s: complex variable) f(t)
f(t) PID & Lead-lag
LeadDesign examples 0 t F(s)
F(s) We denote Laplace transform of f(t) by F(s).
Matlab simulations & laboratories
2008/09 MECH466 : Automatic Control 3 2008/09 MECH466 : Automatic Control 4 1 Advantages of s-domain Examples of Laplace transform We can transform an ordinary differential
equation into an algebraic equation which is
easy to solve. (Next lecture)
It is easy to analyze and design interconnected
(series, feedback etc.) systems. (Throughout the
Frequency domain information of signals can be
dealt with. (Lectures for frequency responses:
after midterm) Unit step function
t 0 (Memorize this!)...
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- Laplace, automatic control | s3://commoncrawl/crawl-data/CC-MAIN-2018-26/segments/1529267862929.10/warc/CC-MAIN-20180619115101-20180619135101-00300.warc.gz | CC-MAIN-2018-26 | 844 | 20 |
https://ajee.utm.my/index.php/ajee/article/view/104 | math | Evaluation of Mathematical Competencies among Electrical Engineering Students
Keywords:Electromagnetic Field Theory, Mathematical Competencies, Evaluation
In universities, engineering students are often seen as a group of students with high level of intelligence. The engineering programme seeks applications from students with a strong command in Mathematics and Science. Therefore, it is believed that Mathematical Competencies (MC) are the element that plays a vital role in engineering education since there are plenty of applications of mathematical knowledge in engineering courses. This paper discusses mathematical competencies further, with emphasis on those demonstrated by the engineering students. MC consist of eight components: Thinking mathematically, posing and solving a mathematical problem, modelling mathematically, reasoning mathematically, representing mathematically, handling mathematical symbols and formalisms, communicating in, with, and about mathematics and using aids and tools. Unfortunately, many engineering students did not meet the required level as they did not perform well in the engineering course, whereby in this study, the focus was on the Electromagnetic Field Theory (EMT) course. EMT was chosen because the course contains high mathematical component. A qualitative method of ethnographic research design was selected as a mean to collect data, which was then analysed using thematic analysis. A set of EMT questions was developed for 17 participants from an electrical engineering programme. From the written work, it can be said that the participants demonstrated their MC based on their answers. It can be concluded that most of the participants with higher marks were able to demonstrate almost all of the MC components. | s3://commoncrawl/crawl-data/CC-MAIN-2023-23/segments/1685224652149.61/warc/CC-MAIN-20230605153700-20230605183700-00393.warc.gz | CC-MAIN-2023-23 | 1,769 | 3 |
http://www.optimization-online.org/DB_HTML/2008/01/1881.html | math | Primal interior point method for minimization of generalized minimax functions
Abstract: In this report, we propose a primal interior-point method for large sparse generalized minimax optimization. After a short introduction, where the problem is stated, we introduce the basic equations of the Newton method applied to the KKT conditions and propose a primal interior-point method. Next we describe the basic algorithm and give more details concerning its implementation covering numerical differentiation, variable metric updates, and a barrier parameter decrease. Using standard weak assumptions, we prove that this algorithm is globally convergent if a bounded barrier is used. Then, using stronger assumptions, we prove that it is globally convergent also for the logarithmic barrier. Finally, we present results of computational experiments confirming the efficiency of the primal interior point method for special cases of generalized minimax problems.
Keywords: Unconstrained optimization, large-scale optimization, nonsmooth optimization, generalized minimax optimization, interior-point methods, modified Newton methods, variable metric methods, global convergence, computational experiments.
Category 1: Nonlinear Optimization
Category 2: Nonlinear Optimization (Unconstrained Optimization )
Category 3: Convex and Nonsmooth Optimization (Nonsmooth Optimization )
Citation: Technical Report V1017-07, Institute of Computer Science, Czech Academy of Sciences, Prague, December 2007.
Entry Submitted: 01/12/2008
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https://testbook.com/question-answer/direction-in-the-question-below-are-given-three-s--5cfb7222fdb8bb22a5626a0c | math | Direction: In the question below are given three statements followed by two conclusions numbered I and II. You have to take the given statements to be true even if they seem to be at variance with commonly known facts. Read all the conclusions and then decide which of the given conclusions logically follows from the given statements disregarding commonly known facts.
Only a few circles are Dollars.
Some Dollars are Soaps.
No rectangle is a circle.
I. All circles being rectangles is a possibility.II. Some rectangles are definitely not soaps.
Free Practice With Testbook Mock Tests
This question was previously asked in
The least possible diagram for the given statements is as follows
I. All circles being rectangle is a possibility → False (as no rectangle is a circle means no circle is a rectangle)
II. Some rectangles are definitely not soaps → False.Hence, neither I nor II follows. | s3://commoncrawl/crawl-data/CC-MAIN-2021-31/segments/1627046153791.41/warc/CC-MAIN-20210728185528-20210728215528-00458.warc.gz | CC-MAIN-2021-31 | 896 | 10 |
http://tkuir.lib.tku.edu.tw:8080/dspace/handle/987654321/32867 | math | Amari模型乃是模擬包含激勵及抑制作用的單層齊次神經網路之積分微分方程式,本篇論文主要是討論此模型單峰解和多峰解的存在性及穩定性。若將幾個shift夠大的單峰解組合在一起,便可製造出多峰解。若將此積分微分方程式視為在無限維中之動態系統,則利用耦函數可計算出Frechet導數在單峰解和多峰解的分譜,以便討論其動態性質。應用中心流形理論及葉理可以探討多峰解的漸進相之穩定性。數值模擬的結果亦會發現一些分岐現象的產生。最後,當耦函數滿足某些特定條件時, 我們找到2-峰解存在的充分條件。 We consider the existence and stability of single-bump and multi-bump solutions of an Amari model, a class of integral-differential equations modeling a single layer of homogeneous neural network with both excitatory and inhibitory neuron. Existence results are obtained by combining several shifts of a one-bump solution. Dynamical properties are obtained by considering the equation as an infinite dimensional dynamical systems and the spectrum of single-bump and multi-bump solutions in terms of the coupling functions. The center manifold theory and its foliation are used to show exponential stability with asymptotic phase for multi-bump solutions. Numerical results for some possible bifurcation phenomena are also presented. Finally, we give a sufficient condition such that a 2-bump solution exists while the coupling function satisfying some particular conditions. | s3://commoncrawl/crawl-data/CC-MAIN-2019-09/segments/1550247495001.53/warc/CC-MAIN-20190220125916-20190220151916-00213.warc.gz | CC-MAIN-2019-09 | 1,561 | 1 |
https://digital.library.txstate.edu/handle/10877/13890 | math | Reduction of infinite dimensional equations
MetadataShow full metadata
In this paper, we use the general Legendre transformation to show the infinite dimensional integrable equations can be reduced to a finite dimensional integrable Hamiltonian system on an invariant set under the flow of the integrable equations. Then we obtain the periodic or quasi-periodic solution of the equation. This generalizes the results of Lax and Novikov regarding the periodic or quasi-periodic solution of the KdV equation to the general case of isospectral Hamiltonian integrable equation. And finally, we discuss the AKNS hierarchy as a special example.
CitationLi, Z., & Xu, T. (2006). Reduction of infinite dimensional equations. Electronic Journal of Differential Equations, 2006(17), pp. 1-15.
This work is licensed under a Creative Commons Attribution 4.0 International License. | s3://commoncrawl/crawl-data/CC-MAIN-2023-14/segments/1679296945433.92/warc/CC-MAIN-20230326044821-20230326074821-00451.warc.gz | CC-MAIN-2023-14 | 868 | 5 |
https://www.solutioninn.com/study-help/fundamentals-momentum-heat/a-cylindrical-graphite-rod-pure-solid-carbon-density-225-gcm3 | math | A cylindrical graphite rod (pure solid carbon, density 2.25 g/cm3) of length 25 cm and initial diameter of 2.0 cm is inserted into a flowing air stream at 1100 K and 2.0 atm total system pressure. The flowing gas creates a stagnant gas boundary layer 5.0 mm thick around the external surface of the rod. At this high temperature, the solid carbon oxidizes to carbon dioxide, CO2, gas according to the reaction C(s) + O2(g) 2 → CO2(g). This surface oxidation reaction is limited by the molecular diffusion of O2 through the stagnant gas film surrounding the surface of the rod, so that the O2 concentration at the graphite surface is effectively zero. Outside of the gas film, the bulk composition of the gas stream represents that of air.
a. Estimate the initial rate of CO2 production from the rod, assuming that the surface reaction is diffusion-limited.
b. How long will it take for the graphite rod to completely disappear? | s3://commoncrawl/crawl-data/CC-MAIN-2022-40/segments/1664030337244.17/warc/CC-MAIN-20221002021540-20221002051540-00146.warc.gz | CC-MAIN-2022-40 | 929 | 3 |
http://ngonevuwhank.mihanblog.com/post/61 | math | Geometric Algebra for Physicists by Anthony Lasenby, Chris Doran
Geometric Algebra for Physicists Anthony Lasenby, Chris Doran ebook
Publisher: Cambridge University Press
ISBN: 0521480221, 9780521480222
Cambridge Let me add one more reference: Theodore Frankel's book: The Geometry of Physics. For these students, algebra and calculus are all syntax and no semantics. Clifford algebras in Classical Physics is being discussed at Physics Forums. Goemetric Algebra Vs Algebraic Geometry. It is very "Geometric algebra for physicists". But you can see more of the same stuff by looking at what David Hestenes writes about geometric algebra, which is Clifford algebra with a physics interpretation, and related to the spacetime manifold. Physics is greatly facilitated by the use of Hestenes' spacetime algebra, which automatically incorporates the geometric structure of spacetime. In General Math is being discussed at Physics Forums. I quote the prologue to David Hestenes' Primer on Geometric Algebra for introductory mathematics and physics. Á�まりは蔵書を思いきって処分する! Geometric Algebra(GA)関連本が4冊ありましたが、それらも処分(売却)することにしました。以下の3冊です。 Doran and Lasenby, "Geometric Algebra for Physicists", 2003. This is demonstrated by examples from electromagnetism. I'm undertaking a self-study of geometric algebra and differential forms. | s3://commoncrawl/crawl-data/CC-MAIN-2019-35/segments/1566027321160.93/warc/CC-MAIN-20190824152236-20190824174236-00525.warc.gz | CC-MAIN-2019-35 | 1,428 | 5 |
http://www.math.iitb.ac.in/~seminar/geometry/smg-october1-2015.html | math | Date & Time: Thursday, October 1, 2015, 15:00-17:00.
Venue: Room 216
Title:Weyl Group, Roots, Root Datum
Speaker: Shripad Garge, IIT Bombay
Abstract: This lecture and the subsequent ones are based on chapter 7 of Springer's book on linear algebraic groups. We will discuss semisimple groups of rank one and reductive groups of semisimple rank one. | s3://commoncrawl/crawl-data/CC-MAIN-2018-43/segments/1539583509845.17/warc/CC-MAIN-20181015205152-20181015230652-00188.warc.gz | CC-MAIN-2018-43 | 347 | 5 |
http://stottle.blogspot.com/2007/07/serial-multiverse.html | math | That's what appears to be on offer from Physicists Paul Steinhardt and Neil Turok and is beautifully described for the layman right here.
I'm particularly intrigued by this passage:
"One can further show that, as the cycles proceed, the relaxation slows more and more as the cosmological constant gets smaller, so exponentially more time is spent in cycles with a small cosmological constant. In this picture, it is natural to expect the tiny value for the constant we observe today."
Surely this implies that - within the context of their conjecture - we could work out how many cycles we must have gone through already, in order for the cosmological constant to have reached its present minute value. And doesn't that imply a true "beginning" - albeit gazillions of times further back than we thought? A beginning at which the cosmo constant was the current predicted value 10^100 times what it is today. Or not?
It would be interesting to know just how many hundreds of trillions of years or cycles that implies.
It's also important to note that the cyclic nature proposed by this conjecture does not in any sense imply "repetition". If we don't survive the collapse of this Universe, we don't return in the next. The universe which arises in any given cycle will, inevitably, have a slightly different set of physical laws to its predecessor and thus be dramatically different in its history and appearance.
As a consequence, this model also provides an alternative to the "multiverse" as a solution to the anthropic problem. In fact, this conjecture is about a different sort of multiverse. It's a serial multiverse, as opposed to the more widely known parallel multiverse.
I think this idea might have legs... | s3://commoncrawl/crawl-data/CC-MAIN-2020-05/segments/1579251778272.69/warc/CC-MAIN-20200128122813-20200128152813-00098.warc.gz | CC-MAIN-2020-05 | 1,715 | 8 |
https://brainmass.com/engineering/electrical-engineering/electrostatic-field-ong-metal-cylinder-485425 | math | A long metal cylinder with radius a is coaxial with, and entirely inside, an equally long metal tube with internal radius 2a and external radius 3a. The space between the cylinder and the tube is filled with an LIH dielectric material with relative permittivity a. This space is also permeated by a uniform free charge distribution with density pf. outside the tube, the charge density is zero. (a) Write down Poisson's equation for the electrostatic potential in the dielectric material in the region between the cylinder and the tube. You should justify the choice of the coordinate system that you use. (b) Find the general solution of Poisson's equation in the dielectric material. Now assume that the metal cylinder and tube are both held at zero potential. (c) Using appropriate boundary conditions, show that the potential within the dielectric at distance r from the axis of symmetry is given by LlFa? (1 3 In 2 1n(r/a)) r21 V (r) = -Pf for a < 7' < 2a. oes )
(d) Determine the electrostatic field E in the dielectric material. (e) Obtain an expression for the free charge per unit length, A, on the inner cylinder.© BrainMass Inc. brainmass.com October 10, 2019, 4:57 am ad1c9bdddf
Poisson equation in a medium with relative permittivity is:
Since the system has cylindrical symmetry and can be considered infinite in the z-direction, we can conclude that the potential is independent of the z-coordinate and the equation becomes a two dimensional Poisson equation in polar coordinates:
To solve this equation we start with the associated Laplace equation:
And we assume that we can write the solution as a product of two univariate functions:
When we plug this back into equation (1.3) we see that the partial derivatives become full derivatives:
Dividing by we get:
Both sides are independent of each other (they each depend on a different variable), and since this must be true for any both sides must be equal the same constant:
We now look at the angular equation and we identify three cases. Furthermore, we require that the solution will be periodic, since a full revolution returns us to the same point and the potential must be a single value function.
The equation becomes:
The solution to this equation is:
However the periodic condition can be satisfied if and only if A=B=0.
The equation becomes:
The solution is:
Again, the ...
The electrostatic fields in a long metal cylinder is examined. | s3://commoncrawl/crawl-data/CC-MAIN-2019-47/segments/1573496670597.74/warc/CC-MAIN-20191120162215-20191120190215-00105.warc.gz | CC-MAIN-2019-47 | 2,414 | 17 |
https://solvedlib.com/n/pomnt-populations-shifts-in-a-certain-city-follow-a-particular,1137720 | math | So in this problem, we're going to be looking at probabilities and odds. So let's take a moment. Just recall how we do this when I'm finding the probability of an event. I need to know the number of items in the event set how many different ways in an event can happen. And I divide that by the total number in my entire sample set.
So this will give me a fraction somewhere between zero and one when I'm trying to find odds. What I'm going to do is take the probability of an event happening, divided by the probability of the event not happening. The compliment and I usually write it in this format. Okay, 223124 Something along those lines. So let's take a look at this particular problem first.
What is the probability that if I pick somebody from this chart in 2000 that they lived in the West? Well, my sample set for this case is going to be my population in the year 2000. So the probability of being in the West in the year 2000 Well, what is my event set? Well, that's the number of people in the West in 2000 that 63.2 According to my chart, My entire sample set will be the attire number of people in 2000. So if I add up that column, I get a population of 281.4. Large fractions like this could be very unwieldy. So let's put this into a calculator and get a decimal approximation.
So to three decimal places, I get 0.225 as the probability that somebody randomly selected in 2000 will be in from the West. Now what about the next question? The Midwest in 1995? Well, this is a new sample set. I'm now looking at the 1995 column. So the number of people in the Midwest in 1995 is 61.8, and my sample size is the entire population in 1995. If we add up that first column, we get 262.7 again putting this into our calculator and taking three decimal places.
I get 0.235 the next one living either in the mid Northeast or the Midwest in 2000. So the chances of somebody from the Northeast or Midwest in the year 2000? Well, anytime we haven't or we need to see if there's a possibility of overlap, can you be from the Northeast and the Midwest? In this case? No, they are separate. So I could just add the's too probabilities. So first Northeast in the year 2000. Well, in that column Northeast says 53.6.
And as you saw up here where I'm gonna just kind of market in green, my total population for 2000 is 281.4. I'm gonna add to that the Midwest 64.4 against same population, 281.4. If I add those together and put that into my calculator, I get a probability of 0.419 And the last probability we're going to find What is the probability that somebody is either in the south or the West in the year 2009 again? Is there overlap? We have to check. And in this case, no, you're gonna be in one category of the other, but not both. So we can just add these probabilities together.
Now, for 2009 we have a new sample set. We have not used this column before. So if I add them all up, my sample set is out of 307. South is 113.3. West is 71.6.
Adding these and putting it in my calculator gives me a decimal value of 0.602 So those are the four pop up probabilities we wanted to find. Now we're gonna find an odds. I'm going to give myself a little room over here. What are the odds that of randomly selected US resident in 2009 was not from the South? So to find those odds, I'm gonna take the probability that they're not from the South and I'm gonna divide that by its complement. Well, the compliment from not being from the South means I am from the South in 2000 nine are total sample set is 307.
So both of these probabilities are gonna be out of 307. The probability from being from the South is 113.3. And if I add up all the other options Northeast, Midwest and West. I get a total of 193 0.7. I'm gonna need to do this Division 193.7 out of 307 when I divide by a fraction, That's like multiplying by the reciprocal and my 300 sevens cancel.
So that gives me 193.7 over 113.3. I really don't want to have a decimal here, so I'm going to multiply top and bottom by 10. So those are the odds and we can write it just like this 1 1937 toe 1133.. | s3://commoncrawl/crawl-data/CC-MAIN-2022-33/segments/1659882573145.32/warc/CC-MAIN-20220818003501-20220818033501-00048.warc.gz | CC-MAIN-2022-33 | 4,061 | 10 |
https://www.queryhome.com/puzzle/366/ball-cost-the-difference-between-them-how-much-does-each-cost | math | Which Indian cricketer is known as "Brown Bradman"?
Which of the following Pair are not parent and child who have both won the Nobel prize?
Who was the first women nominated member of Rajya Sabha of India?
Who is the first women boxer to be honoured with the Rajiv Gandhi Khel Ratna Award?
Does UE waits for detach accept message from network in UE initiated detach?
How Many times RACH will be re-triggered if RACH fails in UE?
Who was the first English person who visited the court of Akbar?
Politics In the Philippines
What is Dedicated preamble in VoLTE? How to reduce or Cleared?
CAN ANYONE EXPLAIN CLEARLY ABOUT PHYSICAL LAYER GRID..I HAVE MORE CONFUSION WHEN IAM READING ..PLS
A bat and ball cost Rs. 1.10 and the difference between them is Rs. 1. How much does each cost?
Eq1: Bat + Ball = Rs 1.1
Eq2: Bat - Ball = Rs 1
Adding Eq1 + Eq2
2 Bat = Rs 2.1 i.e. Bat is Rs1.05 which implies ball is Rs .05
2x=2.10------>by summing up
x=1.05---->cost of bat
y=.05----->cost of ball
x = Cost of Bat
y = Cost of Ball
x - y = 1.00
2y = 0.10
Therefore , y = 0.10/2 = 0.05
x = 1.01-0.05 = 1.05
Now , Bat (x)= 1.05
Ball(y) = 0.05
bat rs 1, ball 0.10
Amogh buys three items at the store for exactly Rs 100. The second item costs half as much as the first item, and the third item is half as much as the second.
How much did each one cost?
An amount of money is to be distributed among X, Y and Z in the ratio 3 : 1 : 5. The difference between Y’s and Z’s share is Rs. 3600. What is the total of X’s and Y’s share?
Pete'sa Pete lists prices for his extra toppings in pairs. How much does each topping cost by itself? Each price is whole-dollar increments.
Pineapple & Hot Peppers $7
Broccoli & Extra Cheese $6
Mushrooms & Onions $2
Black Olives & Hot Peppers $5
Pepperoni & Mushrooms $4
Onions & Black Olives $3
Extra Cheese & Mushrooms $5
The difference between simple interest and compound interest on a sum for 2 years at 8%, when the interest is compounded annually is Rs.16. If the interest were compounded half yearly, then what would be the difference between simple interest and compound interest for the same sum in 2 years?
The cost of apple and grapes are between Rs 20 and 30 per kg. If total cost of 5 Kg apple and 7 Kg grapes is a number X having unit's and hundred's place equal and sum of cost of 1 Kg apple and 1 Kg grapes is Rs 50.
Then what is the value of X?
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https://sharewareonsale.com/s/scientific-calculator-complex-number-statistics | math | This complex calculator lets you enter complex numbers in the standard (rectangular) or in the polar form. The calculated values will be displayed in standard form; optionally, this complex calculator displays the results in the polar form and other modular forms.
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You are allowed to use this product only within the laws of your country/region. SharewareOnSale and its staff are not responsible for any illegal activity. We did not develop this product; if you have an issue with this product, contact the developer. This product is offered "as is" without express or implied or any other type of warranty. The description of this product on this page is not a recommendation, endorsement, or review; it is a marketing description, written by the developer. The quality and performance of this product is without guarantee. Download or use at your own risk. If you don't feel comfortable with this product, then don't download it. | s3://commoncrawl/crawl-data/CC-MAIN-2019-51/segments/1575541281438.51/warc/CC-MAIN-20191214150439-20191214174439-00093.warc.gz | CC-MAIN-2019-51 | 2,851 | 20 |
https://www.groundai.com/project/water-wave-gap-solitons-an-approximate-theory-and-accurate-numerical-experiments/ | math | Water-wave gap solitons: An approximate theory and accurate numerical experiments
It is demonstrated that a standard coupled-mode theory can successfully describe weakly-nonlinear gravity water waves in Bragg resonance with a periodic one-dimensional topography. Analytical solutions for gap solitons provided by this theory are in a reasonable agreement with accurate numerical simulations of exact equations of motion for ideal planar potential free-surface flows, even for strongly nonlinear waves. In numerical experiments, self-localized groups of nearly standing water waves can exist up to hundreds of wave periods. Generalizations of the model to the three-dimensional case are also derived.
pacs:47.15.K-, 47.35.Bb, 47.35.Lf
As we know from the nonlinear optics, specific self-localized waves can propagate in periodic nonlinear media, with a frequency inside a spectrum gap. These waves are referred to as gap solitons (alternatively called Bragg solitons; see, e.g., Refs.CM1987 (); AW1989 (); CJ1989 (); ESdSKS1996 (); PPLM1997 (); BPZ1998 (); RCT1998 (); CTA2000 (); IdS2000 (); CT2001 (); CMMNSW2008 ()). Also in the field of Bose-Einstein condensation, gap solitons (GS) have been known EC2003 (); PSK2004 (); MKTK2006 (). Recently, it has been realized that GS are also possible in water-wave systems R2008PRE-2 (). In particular, very accurate numerical experiments have shown that finite-amplitude standing waves over a periodic one-dimensional topography are subjected to a modulational instability which spontaneously produces Bragg quasisolitons — localized coherent structures existing for dozens of wave periods. However, in the cited work R2008PRE-2 (), no analytical approach was presented. As a result, many important questions about water-wave GS were not answered, concerning their shape and stability. The present work is intended to clarify this issue, at least partly. More specifically, for a given periodic bottom profile with a spatial period , we shall derive, in some approximation, coefficients for a standard model system of two coupled equations, describing evolution of the forward- and backward-propagating wave envelopes (see, e. g., Refs.AW1989 (); CJ1989 (); RCT1998 (); CT2001 ()),
where is the time, is the horizontal coordinate in the flow plane, and are slow functions. Let at equilibrium the free surface be at . Then elevation of the surface is given by the following formula,
where is the wave number corresponding to the main Bragg resonance, is the frequency at the gap center, is the gravity acceleration, and is an effective depth of the water canal [definitely, is not a mean depth; more precisely it will be specified later by Eqs.(6) and (7)]. The coefficients in Eqs.(1) are: an effective group velocity , a half-width of the frequency gap, a nonlinear self-interaction , and a nonlinear cross-interaction .
Generally, it is assumed in derivation of the above simplified standard model that: (a) dissipative processes are negligible, (b) a periodic inhomogeneity is relatively weak (that is ), (c) the waves are weakly nonlinear, (d) original (without inhomogeneity) equations of motion, when written in terms of normal complex variables , contain nonlinearities starting from the order three:
where is a linear dispersion relation in the absence of periodic inhomogeneity (a weak inhomogeneity adds some small terms to the right hand side of Eq.(3); the most important effect arises from a term , where is a “small” linear non-diagonal operator). It is also required, (e) the coefficient of the four-wave nonlinear interaction should be a continuous function. In application to water waves the requirements (d) and (e) mean that: (i) all the second-order nonlinearities are assumed to be excluded by a suitable canonical transformation (the corresponding procedure is described, e.g., in Refs.K1994 (); Z1999 ()); (ii) the model system (1) can be good only in the limit of relatively deep water, since on a finite depth the function is known to contain discontinuities which disappear on the infinite depth (see, e.g., Ref.Z1999 ()). Therefore we introduce a small parameter
and we consider in the main approximation only the principal effect of weak spatial periodicity, namely creation of a narrow frequency gap with under the main Bragg resonance conditions. Then we imply a standard procedure for obtaining approximate equations for slow wave envelopes, where the deep-water limit of is used for the coefficients and . Thus we neglect in the actual nonlinear wave interaction some relatively small terms with coefficients of order .
Of course, the functions should be sufficiently “narrow” in the Fourier space, since dispersive terms proportional to second-order derivatives are not included into the model.
After derivation of all the coefficients in section II, some known “solitonic” solutions of Eqs.(1) will be compared to numerical results for exact hydrodynamic equations, with nearly the same initial conditions as in the solitons (in section III). We shall see that very long-lived self-localized groups of standing water waves are possible. In some region of soliton parameters, water-wave GS exist up to hundreds of wave periods, until unaccounted by Egs.(1) processes change them significantly. In section IV we discuss some promising directions of further research, concerning three-dimensional generalizations of the coupled mode equations. Some auxiliary calculations are placed in two Appendices.
Ii Coefficients of the model
We start our consideration with a short discussion of conditions when dissipation due to bottom friction, caused by water (kinematic) viscosity , is not important in wave dynamics. Obviously, a viscous sub-layer should be relatively thin in this case: . In a nearly linear regime, a width of the sub-layer can be estimated as , where . This gives us the following necessary condition for applicability of the conservative theory:
Generally speaking, one cannot exclude a possibility that in a strongly nonlinear regime the vorticity can sometimes be advected by a wave-produced alternating velocity field far away from the rigid bottom boundary. Such vortex structures are typically generated near curved parts of the bed, and they can significantly interact with surface waves. However, we assume this is not the case; otherwise, the problem becomes too complicated. Though we do not have simple criterion to evaluate influence of the bottom-produced vorticity, with m we still hope to be correct when neglecting water viscosity, as well as compressibility and surface tension. This allows us to exploit the model of purely potential free-surface ideal fluid flows, commonly used in the water wave theory.
Since in this work we consider the case of relatively deep water, we can write , where is the frequency corresponding to the infinite depth. Later we will see that values are of the most interest.
Let us introduce conformal curvilinear coordinates determined by an analytic function , with , so that
with real coefficients . Without loss of generality, we assume . The unperturbed water surface corresponds to real values of , while at the bottom we have , and
is a parametric representation of the bed profile, which can be highly undulating (see, for example, Fig.1).
In these conformal coordinates, a spectrum of linear potential waves is determined through the following equation (compare to Ref.R2004PRE (), where an analogous approach but slightly different notations were used):
Here is a linear operator which is diagonal in Fourier representation: for any function we have
The eigenfunction takes the following form,
with some coefficients . With a given , we have an infinite homogeneous linear system of equations for . Non-trivial solutions exist for some discrete values . The first gap in the spectrum is the difference between the two first eigenvalues at , that is . Approximately, for small these eigenvalues are determined by the coefficient (compare to Ref.R2004PRE ()),
It should be noted that corresponds to , while corresponds to . Thus, in the first order on , the half-width of the gap in the spectrum of linear waves is
where is a small dimensionless quantity.
As to the nonlinearity coefficients and , their values for the case of infinite depth (in other words, their zeroth-order approximations in ) can be easily extracted from Ref.OOS2006 ():
It should be noted, the cited work OOS2006 () relies on results obtained earlier by Krasitskii K1994 (), who calculated kernels of so-called reduced integrodifferential equation for weakly nonlinear surface water waves (see also the paper by Zakharov Z1999 (), and references therein). It is important in many aspects that for deep-water waves the coefficients and have the opposite signs, and their ratio is .
With the same zeroth-order accuracy, the group velocity is
Now all the coefficients have been derived, and the simplified coupled-mode equations for relatively deep water waves in Bragg resonance with a periodic bottom take the following explicit form:
where are dimensionless wave amplitudes. Analytical solutions are known for the above system (see AW1989 (); CJ1989 (); RCT1998 (); CT2001 ()), describing moving localized structures, the gap solitons. In the simplest case the velocity of GS is zero, and the solutions essentially depend on a parameter , a relative frequency inside the gap ():
These expressions correspond to purely standing, spatially localized waves with frequency (concerning their stability, see Ref.RCT1998 (), where, however, stability domains were presented for a different ratio ; there are some numerical indications that the above GS are stable in a parametric interval , where a critical value ).
It should be noted, one can hardly expect a detailed correspondence between the very simple model (16-17) and the fully nonlinear dynamics, but just a general accordance sometimes is possible. In particular, the model does not describe nonlinear processes resulting in generation of short waves which take the wave energy away from a soliton, thus influencing its dynamics. The model is also not generally good to study collisions between solitons, since wave amplitude can significantly increase in intermediate states.
Iii Numerical experiments
In order co compare the above approximate analytical solutions to nearly exact numerical solutions, we chose the following function :
with real parameters , and . Hence, . For and both close to 1, Eq.(21) gives periodically arranged barriers (see, for example, Fig.1). The barriers are relatively thin as , and relatively high as . However, in numerical experiments with high-amplitude waves, a strong tendency was noticed towards formation of sharp wave crests over very thin barriers (say, when ), already after a few wave periods. With sharp crests, the conservative potential-flow-based model fails (it is also clear that tops of narrow barriers must generate strong vortex structures). Therefore we took in most of our computations in order to have a smooth surface for a longer time. Exact equations for ideal potential free-surface planar flows were simulated (their derivation can be found in Ref.R2004PRE (), some generalizations are made in Refs.R2005PLA (); R2008PRE ()). As in Ref.R2008PRE-2 (), we dealt with dimensionless variables corresponding to , . The dimensionless time is then related to the physical time by a factor . For instance, the period of linear deep-water waves with the length is . At , we set the horizontal free surface, while the initial distribution of the surface-value velocity potential was
in accordance with approximate relation .
Many simulations with different parameters were performed, and a very good general agreement was found between numerical and analytical results in the weakly-nonlinear case, that is for small steepness . So, with , , , and (example I), some noticeable deviations from the purely-standing-wave regime were observed only after (see Figs.2-3). In a real-world experiment it could be several minutes with m.
What is interesting, even for larger , up to , GS can exist for dozens of wave periods. A numerical example for such a relatively high-amplitude water-wave GS is presented in Figs.4-5, where , , , and (example II). In this simulation, there were 45 oscillations before sharp crests formation (see Figs.4 and 6). As to a further evolution of such GS, only in a real-world experiment it will be possible to get reliable knowledge about it, since various dissipative processes come into play.
Concerning water-wave GS with negative , their behavior for was found stable, while for the dynamics was unstable, and partial disintegration of GS was observed after a few tens of wave periods (not shown). However, in some numerical experiments, the life time of GS was limited by the above mentioned process of sharp crest formation rather than by their own instability in frame of the model (16-17), at least with (not shown).
Finally, we would like to present an example of interaction of two GS (example III). The bed parameters are , , . Both solitons initially had and they were separated by a distance . At we set the horizontal free surface and
This numerical experiment also describes interaction of a single GS with a vertical wall at . Surface profiles for several time moments are shown in Figs.7-8. We see that in this example the interaction between GS is attractive. They collide and produce a highly nonlinear and short wave group near .
Iv 3D generalizations and discussion
In this work, coefficients of the standard model (1) were derived for water-wave GS in the approximation of relatively deep water. The frequency gap in this case is small (of order ) despite strong bed undulations. It seems that a more general situation of intermediate depth cannot be described by this basic model, since an interaction of the main wave with a long-scale flow (“zeroth harmonics”) is then essential and should be included into equations. At the formal level, this corresponds to the mentioned discontinuities of the four-wave matrix element on a finite depth. Actually, in a finite-depth dynamics, three-wave interactions are more essential, and therefore they cannot be removed efficiently by a weakly-nonlinear transformation. This is the main difference between the present third-order theory and previously developed second-order theories (see, for example, Ref.HM1987 ()).
So far we considered purely two-dimensional flows, with the single horizontal coordinate . Let us now introduce two important generalizations for three-dimensional flows. Below we only derive equations, but their detailed analysis will be a subject of future work.
In the first case, the bottom topography is still one-dimensional, but we take into account weak variations of the wave field along the second horizontal coordinate , simply by adding dispersive terms, proportional to , to the coupled-mode system, as written below:
In this system, a near-band-edge approximation for the upper branch of the linear spectrum gives a 2D focusing nonlinear Schroedinger equation (NLSE). Thus, in a long-scale limit, the system (24) exhibits a tendency towards wave collapse which is known as a typical feature of 2D NLSE dynamics.
In the second case, a periodic bottom profile is essentially two-dimensional, and in the horizontal Fourier-plane there are several pairs of Bragg-resonant wave vectors. For simplicity, we present below equations for the case when has the symmetry of a square lattice, with equal periods in both horizontal directions and :
where coefficients possess the symmetry . Let us consider interaction of two wave pairs having slow complex amplitudes and , with the first pair corresponding to wave vectors , and with the second pair corresponding to . It is important that the absolute values are equal to each other: . Again we will assume . It is convenient to use new horizontal coordinates:
Elevation of the free surface is then given by the formula
where , with and , and the dots correspond to higher-order terms (again, we should note that generally ). Approximate equations of motion for the amplitudes have the following form:
where small constants and depend on a given bed profile, and mean the complex conjugate quantities, and the function corresponds to nonlinear interactions. Using an explicit expression from Ref.Z1999 () for the deep-water four-wave resonant interaction , we have
where is a normalized value of the matrix element for two perpendicular wave vectors of equal length (see Fig.9). Since , we actually may neglect in the terms proportional to .
The parameters , , and can in principle be calculated from solution of a linearized problem for water waves over a periodic 2D bed. An exact linearized equation for a surface value of the velocity potential can be written in the following form:
where is a radius-vector in the horizontal plane, , while is a self-conjugate linear operator corresponding to a bottom inhomogeneity. However, in three dimensions there is no compact form for , valid with any bottom profile. At the moment, there are only approximate expressions , obtained by expansion (up to a finite order ) of a vertical velocity at the level in powers of (relatively small) bottom deviation from a constant level . The linear self-conjugate operators have a general structure
and so on, where is the horizontal gradient (see Appendix A).
Now we are going to calculate , , and . Let us note that with the four independent eigenfunctions in Bragg resonance are: , , , and . Accordingly, we have for the eigenfrequencies
(where mean the average value in the horizontal plane), and analogously for and . Let us introduce short notations for small quantities: and similarly for and . Then we have approximate equalities,
As the result, we obtain the required formulas for the model parameters:
Moreover, since , it is possible to simplify the operators by writing there instead of . By doing so and taking into account only and , for the bottom profile (47) we obtain approximately
Thus, the expansion is certainly useful for analysis of the case , but it can hardly be valid for a strongly undulating bed. It should be noted that a global representation of the velocity potential in the form (54) (see Appendix A) is questionable in the general case. Derivation of for arbitrary , assuming , is an interesting open problem.
It is worth noting that an explicit (though approximate) form of operator allows us to derive weakly nonlinear equations of motion for water waves over a nonuniform 2D bottom. For example, the Hamiltonian functional (it is the kinetic energy plus the potential energy ) up to the 4th order in terms of the canonically conjugate variables and is written below:
where (see Appendix B). It is interesting to note that the bottom inhomogeneity comes into the Hamiltonian through the definition of operator only. For , it coincides with the previously known fourth-order Hamiltonian for water waves on a uniform depth (see, e.g., Ref.Z1999 (), and references therein). It is also clear that coupled-mode system (28)-(29) corresponds to the case , when the difference is neglected in the third- and fourth-order parts of the Hamiltonian, but it is kept in the second-order part. The functional determines canonical equations of motion,
Numerical simulation of these cubically nonlinear equations, with , will be an important subject of future research.
Further analytical and computational work is also needed to investigate formation of vortex structures near the bottom boundary and to evaluate their influence on the free surface dynamics. In any case, the present results, based on the 2D purely potential theory, are deserving much attention. Moreover, the author hopes that in a future real-world experiment all the mentioned dissipative processes will not be able to destroy water-wave GS for a sufficiently long time. Instead, with vortices and breaking wave crests, the predicted phenomenon of standing self-localized water waves over a periodic bed will be found even more rich, interesting, and beautiful.
Acknowledgments. These investigations were supported by RFBR grant No. 06-01-00665, by RFBR-CNRS grant No. 07-01-92165, by the “Leading Scientific Schools of Russia” grant No. 4887.2008.2, and by the Program “Fundamental Problems of Nonlinear Dynamics” from the RAS Presidium.
Appendix A. Expansion of operator
The expansion of in powers of is easily obtained from the integral representation of the velocity potential
where is the Fourier transform of the velocity potential at , and is the Fourier transform of an unknown function which should be determined by substitution of Eq.(54) into the bottom boundary condition
The resulting integral equation can be represented as follows,
where is a surface value of the velocity potential (in the linear approximation ). It gives us the equation (31) for eigenfunctions corresponding to some fixed frequency .
Appendix B. Hamiltonian of water waves up to 5th order
An approximate Hamiltonian of water waves can be easily derived by writing the kinetic energy of potential three-dimensional motion of an ideal fluid in the following form,
with subsequent substitution
After simplifying, we obtain , where
In the same manner, it is also possible to derive the Hamiltonian with a higher-order accuracy.
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- (22) T. Hara and C. C. Mei, J. Fluid Mech. 178, 221 (1987). | s3://commoncrawl/crawl-data/CC-MAIN-2019-39/segments/1568514575627.91/warc/CC-MAIN-20190922180536-20190922202536-00311.warc.gz | CC-MAIN-2019-39 | 22,900 | 96 |
https://slmshelfchallenge.blogspot.com/2012/04/book-no-30.html | math | I hadn't read this title before, but I know Leedy, like Stuary Murphy, is a go-to for quality math books. As the title implies, a frog and a lizard compete for who can complete the best graph. Each encounters a different set of data and chooses the right graph for the job. It's certainly not a subtle message, but I think it's no less effective. And since it's housed in our Everybody section (and not the 520's), it's definitely one I'll keep in mind for our classroom teachers.
Now there's a math-worthy idea! ...of all the books I read in this "L" section, how many are incorrectly classified? And from there, how many can I estimate are misclassified in the remainder of the Everybody section? | s3://commoncrawl/crawl-data/CC-MAIN-2018-22/segments/1526794866107.79/warc/CC-MAIN-20180524073324-20180524093324-00178.warc.gz | CC-MAIN-2018-22 | 698 | 2 |
https://www.wisc-online.com/arcade/games/mathematics2/mathematics?gameTypes=HANGMAN_TIMEOUT_BASEBALL_TRIVIATRON_BEEKEEPER | math | Solving 1 and 2 Step Equations Intro
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http://www.maa.org/press/maa-reviews/probability-a-very-short-introduction | math | The “Very Short Introduction” series from Oxford University Press is a collection of over 300 books on a wide variety of topics ranging alphabetically from “Advertising” to “Writing and Script”. (Mathematical topics on the list include game theory, logic, and statistics, as well as mathematics itself.) The books are designed as quick entries into new fields for curious readers, and this work on probability comes in at under 130 pages while hitting all of the most significant ideas without requiring any advanced mathematical prerequisites.
John Haigh is well-suited for this task, having previously written the much longer Taking Chances on the same subject and for approximately the same audience. His exposition draws on familiar circumstances where probability is applied, including airplane overbooking, medical testing, and surveys, and does so without either drowning in formulas or skimping on mathematics. The normal distribution and Central Limit Theorem both appear in their proper level of rigor but at the same time accessible to newcomers.
In teaching elementary probability, one invariably confronts the differences among theoretical, experimental, and subjective probability — and usually rapidly explains away the last as less important, because it’s far less amenable to mathematical description. Haigh chooses to place somewhat more emphasis than that on subjective probability, which is probably a wise move for a general audience. Someone wishing to learn what probability is about but who is concerned about their mathematical background will be well-served by this book, and perhaps will be interested enough to investigate the subject further. Since that’s what this series is all about, Probability: A Very Short Introduction has hit its target.
Mark Bollman ([email protected]) is associate professor of mathematics at Albion College in Michigan. His mathematical interests include number theory, probability, and geometry. His claim to be the only Project NExT fellow (Forest dot, 2002) who has taught both English composition and organic chemistry to college students has not, to his knowledge, been successfully contradicted. If it ever is, he is sure that his experience teaching introductory geology will break the deadlock. | s3://commoncrawl/crawl-data/CC-MAIN-2017-17/segments/1492917122992.88/warc/CC-MAIN-20170423031202-00166-ip-10-145-167-34.ec2.internal.warc.gz | CC-MAIN-2017-17 | 2,290 | 4 |
https://neurosoup.org/28-is-40-of-what-number/ | math | Step by action solution because that calculating 28 is 40 percent that what number
We currently have our very first value 28 and the 2nd value 40. Let"s assume the unknown worth is Y i m sorry answer we will find out.
You are watching: 28 is 40 of what number
As we have actually all the compelled values we need, now we have the right to put them in a simple mathematical formula as below:
STEP 1 28 = 40% × Y
STEP 2 28 = 40/100× Y
Multiplying both sides by 100 and also dividing both political parties of the equation through 40 we will certainly arrive at:
STEP 3 Y = 28 × 100/40
STEP 4 Y = 28 × 100 ÷ 40
STEP 5 Y = 70
Finally, us have uncovered the worth of Y i m sorry is 70 and also that is our answer.
You can quickly calculate 28 is 40 percent of what number through using any kind of regular calculator, simply enter 28 × 100 ÷ 40 and you will gain your answer which is 70
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Here is a percent Calculator to solve similar calculations such together 28 is 40 percent that what number. You can solve this form of calculation with your values by start them into the calculator"s fields, and also click "Calculate" to get the result and explanation.
percent of what number
Sample questions, answers, and how to
Question: her friend has actually a bag the marbles, and also he speak you that 40 percent the the marbles room red. If there space 28 red marbles. How many marbles go he have actually altogether?
Answer: 70 marbles.
How To: In this problem, we recognize that the Percent is 40, and we are additionally told the the component of the marbles is red, therefore we recognize that the component is 28.
So, that way that it need to be the complete that"s missing. Right here is the way to figure out what the complete is:
Part/Total = Percent/100
By using a an easy algebra we have the right to re-arrange our Percent equation choose this:
Part × 100/Percent = Total
If we take the "Part" and multiply that by 100, and then we divide that by the "Percent", we will get the "Total".
Let"s try it out on ours problem about the marbles, that"s very an easy and it"s just two steps! We know that the "Part" (red marbles) is 28.
So step one is to just multiply that component by 100.
28 × 100 = 2800
In action two, us take the 2800 and also divide that by the "Percent", i m sorry we room told is 40.
So, 2800 divided by 40 = 70
And that way that the total number of marbles is 70.
Question: A high institution marching band has actually 28 flute players, If 40 percent that the tape members beat the flute, climate how many members are in the band?
Answer: There space 70 members in the band.
How To: The smaller sized "Part" in this difficulty is 28 because there room 28 flute players and also we room told that they consist of 40 percent of the band, for this reason the "Percent" is 40.
Again, it"s the "Total" that"s missing here, and to find it, we just need to monitor our 2 action procedure together the previous problem.
For action one, us multiply the "Part" by 100.
28 × 100 = 2800
For step two, we divide that 2800 by the "Percent", i beg your pardon is 40.
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2800 divided by 40 equates to 70
That means that the total variety of band members is 70.
Have time and want to discover the calculation?
Let"s i think the unknown worth is Y
First writing it as: 100% / Y = 40% / 28
Drop the portion marks to simplify your calculations: 100 / Y = 40 / 28
Multiply both sides by Y to move Y ~ above the appropriate side that the equation: 100 = ( 40 / 28 ) Y | s3://commoncrawl/crawl-data/CC-MAIN-2022-27/segments/1656103661137.41/warc/CC-MAIN-20220630031950-20220630061950-00117.warc.gz | CC-MAIN-2022-27 | 3,599 | 45 |
https://www.mathworks.com/matlabcentral/fileexchange/4503-sector-plot | math | Plots a filled sector given a starting angle and a central angle (of the sector).
Laine Berhane Kahsay (2021). Sector Plot (https://www.mathworks.com/matlabcentral/fileexchange/4503-sector-plot), MATLAB Central File Exchange. Retrieved .
A bit late, but if anyone is stuck like Norouzi was: just add the X,Y coordinates of your desired center to every point generated with this function.
How can I change the center of this sector from (0,0) to another point?
Great program !
Warning: on line 49, 'else' should be replaced by 'elseif' so that the radius input argument is taken into account !
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https://www.scipedia.com/public/Nadukandi_et_al_2012b | math | A new Petrov–Galerkin (PG) method involving two parameters, namely and , is presented, which yields the following schemes on rectangular meshes: (i) a compact stencil obtained by the linear interpolation of the Galerkin FEM and the classical central finite difference method (FDM), should the parameters be equal, that is, ; and (ii) the nonstandard compact stencil presented in (Int. J. Numer. Meth. Engng 2011; 86:18–46) for the Helmholtz equation if the parameters are distinct, that is, . The nonstandard compact stencil is obtained by taking the linear interpolation of the diffusive terms (specified by ) and the mass terms (specified by ) that appear in the stencils obtained by the standard Galerkin FEM and the classical central FDM, respectively. On square meshes, these two schemes were shown to provide solutions to the Helmholtz equation that have a dispersion accuracy of fourth and sixth order, respectively (Int. J. Numer. Meth. Engng 2011; 86:18–46). The objective of this paper is to study the performance of this PG method for the Helmholtz equation using nonuniform meshes and the treatment of natural boundary conditions. | s3://commoncrawl/crawl-data/CC-MAIN-2021-43/segments/1634323585696.21/warc/CC-MAIN-20211023130922-20211023160922-00298.warc.gz | CC-MAIN-2021-43 | 1,148 | 1 |
https://groups.google.com/g/sage-support/c/KLvQSnja21c | math | I do not know how we define absolute value in Sage. Even in math in
general, I'm not sure of what means the absolute value of a complex
number. Depends on the data of a convex cone ?
I suppose that some Sage gurus will explain why abs(pi*I)=pi*I.
However as far as my knowledge in math is concerned, the "good"
generalization of abs to the complex plane is the norm.
This is the correct answer.
Hope it helps ...
Have a good afternoon
Sage's uses the following:
sage: abs(3 + 4*I)
> I suppose that some Sage gurus will explain why abs(pi*I)=pi*I.
I believe the underlying cause is due to #10064, #10583, #7160, and
#6132 all of which are the same issue.
On Mon, Feb 7, 2011 at 1:27 PM, Laurent wrote:
> Le 07/02/2011 13:05, Clemens Heuberger a écrit :
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https://www.immigrationboards.com/ireland/proofs-of-each-year-of-residence-claimed-t270929.html | math | I am wondering if my understanding is correct in relation to the proofs of residence of ‘each’ year claimed.
So, if I received a stamp 4 on 31 March 2016 and were to apply for citizenship as the spouse of an Irish citizen after coming March, my 3 years’ residnece runs:
Year 1 - 31 March 2016 to 30 March 2017
Year 2 - 31 March 2017 to 30 March 2018
Year 3 - 31 March 2018 to 30 March 2019
Therefore, I need three differents proofs of residence for the Year 1, another three for thr Year 2, and also three for the Year 3 (9 proofs in total)-this is my understanding.
Reading some other posts here, however, I have noticed that some people have a different interpretation in this regard, which is I have to submit 12 different proofs in total (3 for the ‘Calendar’ Year 2016, 3 for 2017, 3 for 2018, and 3 for 2019, EXCLUDING the additional three proofs of residence for both me and my spouse for the 3 months immediately before my application).
Could anyone here please advise me on this (which interpretation is correct)? Thank you very much for your help.. Happy New Year! | s3://commoncrawl/crawl-data/CC-MAIN-2019-22/segments/1558232257920.67/warc/CC-MAIN-20190525064654-20190525090654-00367.warc.gz | CC-MAIN-2019-22 | 1,084 | 8 |
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A decrease in the income tax rate _Increases_____ the value of the multiplier? That was my answer. Increases?
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9) A specific score in a distribution of data minus the mean and divided by the standard deviation produces a value known as a� A. Beta B. Z Score C. Variability Score D. Coefficient of Determination
8)X- DIVIDED BY 9=18 (Solve for X) A. 17 B. 21 C. 12 D. 31
7) What is the relationship of the Mean, Median and Mode as Measures of Central Tendency in a true Normal Curve? A. They are equal B. They align Median, Mode and Mean in that order C. They align Mean, Median and Mode in that order D. They align Mode, Median and Mean in that order
6) A Dichotomous Variable represents what level of measurement within the realm of quantitative analysis? A. Ordinal B. Nominal C. Ratio D. Interval
5) In a 95% Confidence Interval, the true mean has what chance of falling between the Lower Limit and Upper Limits of the calculated confidence interval? A. .90 B. 95% C. .05 D. 5%
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http://reformatusegyhazmontreal.ca/q4mql5/special-parallelograms-assignment-180c9d | math | Special Parallelograms Quiz. 4. October 8th. Still, we will get more specific in this section and discuss a special type of quadrilateral: the parallelogram. Finish Editing. 3. PLAY. Add one to cart. 1 GT/Honors Geometry S2 Unit 6: Lesson Plan: Polygons and Quadrilaterals Date Topic Assignment Jan 7-8 Revisit Polygon angle sum theorem. << Assignment 27b - Properties of Special Parallelograms. Geometry – GRADED ASSIGNMENT Name: _____ Special Parallelograms Practice Date: _____ Period: ____ For 1-8, complete the following charts by putting checks in the boxes that are true. Square The diagonals …. Step 3 Show that EG and FH are bisect each other. No, it is not a rectangle because the sides of the parallelogram do not meet at right angles. Explain. Test. Learn. When we discussed quadrilaterals in the last section, we essentially just specified that they were polygons with four vertices and four sides. 16 avr. Mar 25, 2014 - Properties of Special Parallelograms Notes, Assignment and Quiz Bundle This is a bundle of three of my Special Parallelogram Notes and Assignment sets and my Properties of Special Parallelograms Quiz. Homework. Voir plus d'idées sur le thème matériel éducatif montessori, science montessori, montessori ce1. Fill in these notes as you watch the tutorial video. Practice. Properties of parallelograms Geometry 6 2 properties of parallelograms worksheet answers. Log in Sign up. 20. Apr 10, 2015 - Properties of Special Parallelograms Notes, Assignment and Quiz Bundle This is a bundle of three of my Special Parallelogram Notes and Assignment sets and my Properties of Special Parallelograms Quiz. recording . Match. If . 4 Sides Opp. Since EG and FH have the same midpoint, they bisect each other. Parallelograms Assignment Answer the following questions. -Adjacent angles are supplementary-Opposite interior angles are equal to each other-All rhombuses are parallelograms, but not all parallelograms are rhombuses Kite: - 2 pairs of consecutive, congruent sides - 1 pair of opposite angles are congruent - Made up of two congruent triangles - Interior angles add up to 360 degrees Trapezoid: - Legs are congruent (in an isosceles trapezoid) - Base angles are congruent - … Previous Next. Print; Share; Edit; Delete; Report an issue; Host a game. Special Parallelograms Clue Assignment. /Contents 5 0 R endobj Special Parallelograms; What makes a Rhombus; What makes a Rectangle; What makes a Square; Using Coordinate Proofs with Special Parallelograms; Assignment 6-5: Pg. Rectangle 3. Special Parallelograms. Assignment 27a - special parallelograms. Worksheets, Activities, Homework. Digital Download . 0. Flashcards. Search. FlanMath. Learn vocabulary, terms, and more with flashcards, games, and other study tools. << Sides || Opp. Only $2.99/month. 7 days ago. PLAY. Edit. /Type /XObject Topics: 2-5 Proving Angles Congruent. 12 Followers. We can NOT find the perimeter because there are infinitely many possible parallelograms that can drawn having different lengths for the other two sides. AC BD A B C D Theorem 6-14 Theorem If a parallelogram is a rhombus, then each diagonal bisects a pair of opposite angles. . Played 1 times. There are six important properties of parallelograms to know: Opposite sides are congruent (AB = DC). %PDF-1.7 ���� JFIF � � �� � Add one to cart.
$.' Assignment 7.4 - Special Parallelograms DRAFT. VX A Use the diagram to answer the questions, The length of AB is Geometry. 4 Sides Opp. Do Problem Solving Lesson 6 4 Properties Of Special Parallelograms You Have Homework Helper Who Holds Expertise In All The Fields of Study? ",#(7),01444'9=82. >> /Length 8 0 R Assignment: Ch 2-4 evens Online homework 7 Quiz 7 (due October 22nd) class notes. Apr 10, 2015 - Properties of Special Parallelograms Notes, Assignment and Quiz Bundle This is a bundle of three of my Special Parallelogram Notes and Assignment sets and my Properties of Special Parallelograms Quiz. Write. STUDY. This work should take you about 30 minutes to complete. /MediaBox [ 0 0 612 792] Edit. Class notes. 6 0 obj PLAY. . >> Add to Wish List. From WyzAnt Tutoring Resources Properties of Parallelograms. . Sides All Opp. /PAGE0001 Do STUDY. /Name /PAGE0001 Adobe Acrobat Document 320.2 KB. Share practice link. /Height 2189 Key Concepts: Terms in this set (14) The figure is a parallelogram. /ColorSpace /DeviceRGB 9 th, 10 th, 11 th, 12 th. Use opposite sides equal, diagonals bisecting each other, opposite angle equal, adjacent angels supplementary. Digital Download. Parallelogram 2. Learn. $1.50. Learn. Special Parallelograms Puzzle ActivityThis is a very interactive activity to practice the properties/ Theorems for special parallelograms: Rhombuses, Rectangles and Squares.Students can review the properties with this activity by rearranging the provided pieces (15 pieces) by classifying them in a " Upgrade to remove ads. Mathematics. Q When you are thinking about similarities and differences, remember to think about the parallelogram’s sides, angles and diagonals. . Created by. Write. Solo Practice. 2 3 4 5 This is the time when I will answer emails and respond to any questions by email. >> Pgs 4-5 Jan 13-14 Students will Prove a quadrilateral is a parallelogram in a variety of ways. I use this as a mixed practice after I teach the shapes so students have to differentiate between the different properties and know when to use which property. Angles Parallelo ram Rectan le Rhombus S ware bisect each other are congruent are perpendicular bisect opposite angles /XObject PDF (402 KB | 6 pages) $1.50. Each Notes/Assignment set includes: ***fully illustrated teachers notes ***matching student notes ***a teacher's set of examples that are fully worked out ***a matching set of student examples for them to follow along and fill in ***a two page assignment for students to practice that includes a complete … Find an answer to your question What value of m would make parallelogram WXYZ a square? /ProcSet 6 0 R /Subtype /Image always. October 15th. Buy licenses to share. Fill in Notes - Compare Quadrilaterals and Parallelograms . (In addition, the square is a special case or type of both the rectangle and the rhombus.) These parallelograms show two of the infinitely many possible parallelograms with a base of 8 and a height of 4. /Length 43 stream Week 8. If . Write. Grade Levels. Reported resources will be reviewed by our team. Helpful Hint q ABCD is a rhombus A B C D Then . Buy licenses to share. Special Parallelograms Assignment Active Solving for Side Lengths of Rectangles ABCD is a rectangle. It also includes interior and exterior angles of polygons. Start studying Special Parallelograms. If it is taking you much longer than 30 minutes, stop, and email me. >> Match. [/PDF /ImageC] /Parent 3 0 R Format. One special kind of polygons is called a parallelogram. Match. 6-4 Properties of Special Parallelograms Objectives Prove and apply properties of … Created by. Geometry - GRADED ASSIGNMENT Special Parallelograms Practice Name: Date: Period: All For 1-8, complete the following charts by putting checks in the boxes that are true. Browse. /Width 1693 Angles ( All Angles ( 1. Parallelograms Assignment and Quiz. Holt McDougal Geometry Properties of Special Parallelograms Example 6 The vertices of square STVW are S(–5, –4), T(0, 2), V(6, –3) , and W(1, –9) . Created by. 2020 - Découvrez le tableau "Apprentissages" de Graines De Malice sur Pinterest. Spell. The three special parallelograms — rhombus, rectangle, and square — are so-called because they’re special cases of the parallelogram. Start studying Parallelograms Assignment and Quiz. MsCornelison. b. Is the figure a rectangle? Are you getting the free resources, updates, and special offers we send out every week in our teacher newsletter? We can find the area of these parallelograms by using A = bh = (8)(4) = 32. Download. Play. 5 0 obj . Terms in this set (58) always. answer with Sometimes, Always, or Never. Spell. endstream /Type /Page You can purchase them separately at: Properties of Parallelograms Notes and Assignment. Interior and Exterior angles of regular polygons. /Resources Geometry E-Learning While we are out, I will have office hours from 9:00-10:30 and 2:30-4:00. View g_ch06_04 student (1).ppt from FOREIGN LANGUAGE 332 at Renton Senior High School. 609.5 0 0 788.0 1.3 2.0 cm Special Parallelograms. Pgs 2-3: polygons Jan 11-12 Students will explore the properties of parallelograms. Week 7. ABCD is a rhombus A B C D Then . One diagonal measures 28 units. Parallelograms Properties Shapes Sides Diagonals and Angles with from properties of parallelograms worksheet answer key , source:mathwarehouse.com You need to understand how to project cash flow. Gravity. recording. Resource Type. Live Game Live. Download. View all testimonials . Log in Sign up. endobj If a quadrilateral is a rectangle, then its opposite sides are congruent . This is a self check assignment using properties of parallelograms, rectangles, and rhombus. /Filter /DCTDecode Opposite angels are congruent (D = B). . Gravity. Test. Subject. Taelor_Morton. This quiz is incomplete! Assignment 27b - special parallelograms. /BitsPerComponent 8 You can purchase them separately at: Properties of Parallelograms Notes and Assignment. Topics: 2-4 Reasoning in Algebra. If a quadrilateral is a parallelogram, then its opposite sides are congruent. << /PAGE0001 7 0 R >> << Spell. You can purchase them separately at: Properties of Parallelograms Notes and Assignment. Follow. However below, once you visit this web page, it will be hence very simple to get as with ease as download lead properties of special parallelograms answers It will not say yes many times as we accustom before. Learn vocabulary, terms, and more with flashcards, games, and other study tools. the broadcast properties of special parallelograms answers that you are looking for. We can craft any kind of writing assignment for you quickly, professionally, and at an affordable price! Teachers Pay Teachers is an online marketplace where teachers buy and sell original educational materials. Adobe Acrobat Document 27.1 KB. Use the rules of parallelograms to prove a quadrilateral is a parallelogram. Properties of Special Parallelograms Notes, Assignment and Quiz Bundle This is a bundle of three of my Special Parallelogram Notes and Assignment sets and my Properties of Special Parallelograms Quiz. 1 2 2. It is a quadrilateral where both pairs of opposite sides are parallel. Save. stream
Flashcards. 4 0 obj Special Parallelograms Rhombuses Squares Rectangles A B D C E F G H Theorem 6-13 Theorem If a parallelogram is a rhombus, then its diagonals are perpendicular. always. Rectangles, rhombuses, and squares are sometimes referred to as special parallelograms. Choose from 500 different sets of geometry special parallelograms flashcards on Quizlet. . | s3://commoncrawl/crawl-data/CC-MAIN-2021-31/segments/1627046155529.97/warc/CC-MAIN-20210805095314-20210805125314-00451.warc.gz | CC-MAIN-2021-31 | 10,916 | 3 |
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dy/dx + py = q, where p and q are functions of x or constants.
dx/dy + px = q, where p and q are functions of y or constants.
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6) This is the encryption algorithm that will begin to supplant the Data Encryption Standard (DES) - and later Triple DES - over the next few years as the new standard encryption algorithm.
9) This is a mode of operation for a block cipher, with the characteristic that each possible block of plaintext has a defined corresponding ciphertext value and vice versa.
b) hash function
d) Electronic Code Book
10) This is a trial and error method used to decode encrypted data through exhaustive effort rather than employing intellectual strategies.
a) chaffing and winnowing
d) brute force cracking | s3://commoncrawl/crawl-data/CC-MAIN-2021-10/segments/1614178376006.87/warc/CC-MAIN-20210307013626-20210307043626-00167.warc.gz | CC-MAIN-2021-10 | 1,093 | 11 |
http://thoughfulblog.blogspot.com/2011/02/ | math | A friend returned from a fascinating visit to the SNO lab, the slow neutron observatory in Sudbury, Ontario, Canada. He described the long ride down into the depths of the mine on the rickety, open elevator, and the remarkable equipment he observed. He made one statement, though, that bears examining, because it's a popular misconception.
He said, "You could feel yourself getting heavier."
Because he was progressing toward the centre of the Earth, he expected to weigh more.
This is a fallacy, though. He would weigh less. In fact, although weight follows the familiar inverse-square law outside, weight is proportional to the radius inside. It drops linearly.
Here's why. (It's a standard university calculus question, but you don't need calculus to see.)
First, the quick, intuitive answer. How much would you weigh at the centre? Zero, of course, because the mass is pulling you in all directions, each molecule on one side being cancelled by one on the other.
Since you weigh more than zero at the surface, and zero at the middle, either it decreases as you go down, or increases for a while before decreasing. Where is the logical turnaround point? (The surface, of course.) Also, it doesn't make sense to say that the force of gravity keeps increasing all the way to the centre, then instantly becomes zero when you travel that last nanometre to the absolute centre.
OK, so now that we expect a decreasing graph of weight versus distance from centre (radius), why is it linear.
The answer is easiest to understand if you consider the force inside a shell. Pretend the Earth is a perfectly spherical egg. You're inside. How much do you weigh? Then answer: zero everywhere. Pretend you are a two-thirds down to the centre. The mass below your feet is twice as far away as the mass above your head, so pulls a quarter strength (inverse-square law). But there is four times as much of the shell below you than above. Four times as much pulling at one-quarter the force…cancels out. Same with side-to-side, of course.
(This is analogous to the electric field inside a charged sphere--zero everywhere.)
So, now you're down a mineshaft. All the shells above you are cancelled out by mass below you, farther out than your radius. What's left is only the ground beneath your feet, acting as if it's all at the centre. Mass goes as volume, radius cubed. So as you go down, the mass of the sphere beneath your feet is decreasing by radius cubed, but acting stronger on you by radius squared.
Result, the force of gravity is decreasing by the radius to the first power. You feel lighter down a mine shaft. | s3://commoncrawl/crawl-data/CC-MAIN-2018-22/segments/1526794864837.40/warc/CC-MAIN-20180522170703-20180522190703-00537.warc.gz | CC-MAIN-2018-22 | 2,605 | 12 |
http://www.residentadvisor.net/feed-item.aspx?id=46046 | math | Fri, 04 May 2012 / ryankeelingClick through to listen to and rate a selection of offensive sounds for BBC Radio 4's So You Want To Be A Scientist? programme.
Fri, 04 May 2012 / terrencefullerSepia tint, half-naked girls, plenty of slow-mo—the WhoMadeWho member's hip new video has 'em all. "Broken Glass" is the first single to be taken from his recent album for Friends of Friends.
Fri, 04 May 2012 / RAThe Bristol label offers up a 2012 showcase mix featuring current and forthcoming releases. Peverelist and Kahn feature alongside Soul Motive staples like Eleven Tigers for a vibrant blend of melodic dubstep and garage.
Thu, 03 May 2012 / genericnickTo celebrate the upcoming re-release of Steve Rachmad's 1994 album The Secret Life of Machines, Rachmad and co have put together this 15-minute documentary on his career, which includes testimonials from Ben Klock, Marcel Dettmann, Dave Clake, Joris Voorn and others. More ›
Thu, 03 May 2012 / 808heinz808The MS Stubnitz, an 80-metre long former GDR fishing vessel, will be one of the stages at Bloc 2012; this fascinating eight-minute video tells the story of the ship through the eyes of its owner Urs Blaser, including his memories of an on-board back-to-back set from Hawtin and Villalobos.
Thu, 03 May 2012 / RAOne of Detroit's finest links up with Diamonds and Pearls for a 14-track session, utilizing cuts from Aux 88, Reggie Dokes and Larry Heard among others. | s3://commoncrawl/crawl-data/CC-MAIN-2013-20/segments/1368701063060/warc/CC-MAIN-20130516104423-00083-ip-10-60-113-184.ec2.internal.warc.gz | CC-MAIN-2013-20 | 1,450 | 6 |