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import numpy as np |
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def area_of(left_top, right_bottom): |
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"""Compute the areas of rectangles given two corners. |
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Args: |
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left_top (N, 2): left top corner. |
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right_bottom (N, 2): right bottom corner. |
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Returns: |
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area (N): return the area. |
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""" |
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hw = np.clip(right_bottom - left_top, 0.0, None) |
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return hw[..., 0] * hw[..., 1] |
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def iou_of(boxes0, boxes1, eps=1e-5): |
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"""Return intersection-over-union (Jaccard index) of boxes. |
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Args: |
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boxes0 (N, 4): ground truth boxes. |
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boxes1 (N or 1, 4): predicted boxes. |
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eps: a small number to avoid 0 as denominator. |
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Returns: |
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iou (N): IoU values. |
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""" |
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overlap_left_top = np.maximum(boxes0[..., :2], boxes1[..., :2]) |
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overlap_right_bottom = np.minimum(boxes0[..., 2:], boxes1[..., 2:]) |
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overlap_area = area_of(overlap_left_top, overlap_right_bottom) |
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area0 = area_of(boxes0[..., :2], boxes0[..., 2:]) |
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area1 = area_of(boxes1[..., :2], boxes1[..., 2:]) |
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return overlap_area / (area0 + area1 - overlap_area + eps) |
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def hard_nms(box_scores, iou_threshold, top_k=-1, candidate_size=200): |
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""" |
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Args: |
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box_scores (N, 5): boxes in corner-form and probabilities. |
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iou_threshold: intersection over union threshold. |
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top_k: keep top_k results. If k <= 0, keep all the results. |
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candidate_size: only consider the candidates with the highest scores. |
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Returns: |
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picked: a list of indexes of the kept boxes |
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""" |
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scores = box_scores[:, -1] |
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boxes = box_scores[:, :-1] |
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picked = [] |
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indexes = np.argsort(scores) |
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indexes = indexes[-candidate_size:] |
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while len(indexes) > 0: |
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current = indexes[-1] |
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picked.append(current) |
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if 0 < top_k == len(picked) or len(indexes) == 1: |
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break |
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current_box = boxes[current, :] |
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indexes = indexes[:-1] |
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rest_boxes = boxes[indexes, :] |
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iou = iou_of( |
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rest_boxes, |
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np.expand_dims(current_box, axis=0), |
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) |
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indexes = indexes[iou <= iou_threshold] |
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return box_scores[picked, :] |
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